Calculus Examples

$\frac{e^{x}}{1 + e^{2 x}}$

Step 1

Differentiate using the Quotient Rule which states that $\frac{d}{d x} [\frac{f (x)}{g (x)}]$ is $\frac{g (x) \frac{d}{d x} [f (x)] - f (x) \frac{d}{d x} [g (x)]}{{g (x)}^{2}}$ where $f (x) = e^{x}$ and $g (x) = 1 + e^{2 x}$ .

$\frac{(1 + e^{2 x}) \frac{d}{d x} [e^{x}] - e^{x} \frac{d}{d x} [1 + e^{2 x}]}{{(1 + e^{2 x})}^{2}}$

Step 2

Differentiate using the Exponential Rule which states that $\frac{d}{d x} [a^{x}]$ is $a^{x} \ln (a)$ where $a$ = $e$ .

$\frac{(1 + e^{2 x}) e^{x} - e^{x} \frac{d}{d x} [1 + e^{2 x}]}{{(1 + e^{2 x})}^{2}}$

Step 3

Differentiate.

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Step 3.1

By the Sum Rule, the derivative of $1 + e^{2 x}$ with respect to $x$ is $\frac{d}{d x} [1] + \frac{d}{d x} [e^{2 x}]$ .

$\frac{(1 + e^{2 x}) e^{x} - e^{x} (\frac{d}{d x} [1] + \frac{d}{d x} [e^{2 x}])}{{(1 + e^{2 x})}^{2}}$

Step 3.2

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$\frac{(1 + e^{2 x}) e^{x} - e^{x} (0 + \frac{d}{d x} [e^{2 x}])}{{(1 + e^{2 x})}^{2}}$

Step 3.3

Add $0$ and $\frac{d}{d x} [e^{2 x}]$ .

$\frac{(1 + e^{2 x}) e^{x} - e^{x} \frac{d}{d x} [e^{2 x}]}{{(1 + e^{2 x})}^{2}}$

Step 4

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = e^{x}$ and $g (x) = 2 x$ .

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Step 4.1

To apply the Chain Rule, set $u$ as $2 x$ .

$\frac{(1 + e^{2 x}) e^{x} - e^{x} (\frac{d}{d u} [e^{u}] \frac{d}{d x} [2 x])}{{(1 + e^{2 x})}^{2}}$

Step 4.2

Differentiate using the Exponential Rule which states that $\frac{d}{d u} [a^{u}]$ is $a^{u} \ln (a)$ where $a$ = $e$ .

$\frac{(1 + e^{2 x}) e^{x} - e^{x} (e^{u} \frac{d}{d x} [2 x])}{{(1 + e^{2 x})}^{2}}$

Step 4.3

Replace all occurrences of $u$ with $2 x$ .

$\frac{(1 + e^{2 x}) e^{x} - e^{x} (e^{2 x} \frac{d}{d x} [2 x])}{{(1 + e^{2 x})}^{2}}$

Step 5

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{(1 + e^{2 x}) e^{x} - e^{2 x + x} \frac{d}{d x} [2 x]}{{(1 + e^{2 x})}^{2}}$

Step 6

Add $2 x$ and $x$ .

$\frac{(1 + e^{2 x}) e^{x} - e^{3 x} \frac{d}{d x} [2 x]}{{(1 + e^{2 x})}^{2}}$

Step 7

Since $2$ is constant with respect to $x$ , the derivative of $2 x$ with respect to $x$ is $2 \frac{d}{d x} [x]$ .

$\frac{(1 + e^{2 x}) e^{x} - e^{3 x} (2 \frac{d}{d x} [x])}{{(1 + e^{2 x})}^{2}}$

Step 8

Multiply $2$ by $- 1$ .

$\frac{(1 + e^{2 x}) e^{x} - 2 e^{3 x} \frac{d}{d x} [x]}{{(1 + e^{2 x})}^{2}}$

Step 9

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{(1 + e^{2 x}) e^{x} - 2 e^{3 x} \cdot 1}{{(1 + e^{2 x})}^{2}}$

Step 10

Multiply $- 2$ by $1$ .

$\frac{(1 + e^{2 x}) e^{x} - 2 e^{3 x}}{{(1 + e^{2 x})}^{2}}$

Step 11

Simplify.

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Step 11.1

Apply the distributive property.

$\frac{1 e^{x} + e^{2 x} e^{x} - 2 e^{3 x}}{{(1 + e^{2 x})}^{2}}$

Step 11.2

Simplify the numerator.

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Step 11.2.1

Simplify each term.

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Step 11.2.1.1

Multiply $e^{x}$ by $1$ .

$\frac{e^{x} + e^{2 x} e^{x} - 2 e^{3 x}}{{(1 + e^{2 x})}^{2}}$

Step 11.2.1.2

Multiply $e^{2 x}$ by $e^{x}$ by adding the exponents.

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Step 11.2.1.2.1

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{e^{x} + e^{2 x + x} - 2 e^{3 x}}{{(1 + e^{2 x})}^{2}}$

Step 11.2.1.2.2

Add $2 x$ and $x$ .

$\frac{e^{x} + e^{3 x} - 2 e^{3 x}}{{(1 + e^{2 x})}^{2}}$

Step 11.2.2

Subtract $2 e^{3 x}$ from $e^{3 x}$ .

$\frac{e^{x} - e^{3 x}}{{(1 + e^{2 x})}^{2}}$