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Calculus Examples
limx→∞(x3+4)2-x6x3limx→∞(x3+4)2−x6x3
Step 1
Divide the numerator and denominator by the highest power of xx in the denominator.
limx→∞(x3x3+4x3)2-x6x3x3x3limx→∞(x3x3+4x3)2−x6x3x3x3
Step 2
Step 2.1
Cancel the common factor of x6x6 and x3x3.
Step 2.1.1
Factor x3x3 out of x6x6.
limx→∞(x3x3+4x3)2-x3x3x3x3x3limx→∞(x3x3+4x3)2−x3x3x3x3x3
Step 2.1.2
Cancel the common factors.
Step 2.1.2.1
Multiply by 11.
limx→∞(x3x3+4x3)2-x3x3x3⋅1x3x3limx→∞(x3x3+4x3)2−x3x3x3⋅1x3x3
Step 2.1.2.2
Cancel the common factor.
limx→∞(x3x3+4x3)2-x3x3x3⋅1x3x3
Step 2.1.2.3
Rewrite the expression.
limx→∞(x3x3+4x3)2-x31x3x3
Step 2.1.2.4
Divide x3 by 1.
limx→∞(x3x3+4x3)2-x3x3x3
limx→∞(x3x3+4x3)2-x3x3x3
limx→∞(x3x3+4x3)2-x3x3x3
Step 2.2
Cancel the common factor of x3.
limx→∞(x3x3+4x3)2-x31
limx→∞(x3x3+4x3)2-x31
Step 3
As x approaches ∞, the fraction 4x3 approaches 0.
limx→∞(x3x3+0)2-x31
Step 4
Since its numerator is unbounded while its denominator approaches a constant number, the fraction (x3x3+0)2-x31 approaches negative infinity.
-∞