Calculus Examples

$\int_{0}^{1} x^{2} \cdot 2^{x} d x$

Step 1

Integrate by parts using the formula $\int u d v = u v - \int v d u$ , where $u = x^{2}$ and $d v = 2^{x}$ .

$x^{2} (\frac{1}{\ln (2)} \cdot 2^{x})]_{0}^{1} - \int_{0}^{1} \frac{1}{\ln (2)} \cdot 2^{x} (2 x) d x$

Step 2

Simplify.

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Step 2.1

Combine $\frac{1}{\ln (2)}$ and $2^{x}$ .

$x^{2} \frac{2^{x}}{\ln (2)}]_{0}^{1} - \int_{0}^{1} \frac{1}{\ln (2)} \cdot 2^{x} (2 x) d x$

Step 2.2

Combine $x^{2}$ and $\frac{2^{x}}{\ln (2)}$ .

$\frac{x^{2} \cdot 2^{x}}{\ln (2)}]_{0}^{1} - \int_{0}^{1} \frac{1}{\ln (2)} \cdot 2^{x} (2 x) d x$

Step 3

Since $\frac{1}{\ln (2)} \cdot 2$ is constant with respect to $x$ , move $\frac{1}{\ln (2)} \cdot 2$ out of the integral.

$\frac{x^{2} \cdot 2^{x}}{\ln (2)}]_{0}^{1} - (\frac{1}{\ln (2)} \cdot 2 \int_{0}^{1} 2^{x - 1} (2 x) d x)$

Step 4

Simplify.

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Step 4.1

Combine $\frac{1}{\ln (2)}$ and $2$ .

$\frac{x^{2} \cdot 2^{x}}{\ln (2)}]_{0}^{1} - (\frac{2}{\ln (2)} \int_{0}^{1} 2^{x - 1} (2 x) d x)$

Step 4.2

Multiply $2^{x - 1}$ by $2$ by adding the exponents.

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Step 4.2.1

Move $2$ .

$\frac{x^{2} \cdot 2^{x}}{\ln (2)}]_{0}^{1} - (\frac{2}{\ln (2)} \int_{0}^{1} 2 \cdot 2^{x - 1} x d x)$

Step 4.2.2

Multiply $2$ by $2^{x - 1}$ .

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Step 4.2.2.1

Raise $2$ to the power of $1$ .

$\frac{x^{2} \cdot 2^{x}}{\ln (2)}]_{0}^{1} - (\frac{2}{\ln (2)} \int_{0}^{1} 2^{1} \cdot 2^{x - 1} x d x)$

Step 4.2.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{x^{2} \cdot 2^{x}}{\ln (2)}]_{0}^{1} - (\frac{2}{\ln (2)} \int_{0}^{1} 2^{1 + x - 1} x d x)$

Step 4.2.3

Combine the opposite terms in $1 + x - 1$ .

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Step 4.2.3.1

Subtract $1$ from $1$ .

$\frac{x^{2} \cdot 2^{x}}{\ln (2)}]_{0}^{1} - (\frac{2}{\ln (2)} \int_{0}^{1} 2^{x + 0} x d x)$

Step 4.2.3.2

Add $x$ and $0$ .

$\frac{x^{2} \cdot 2^{x}}{\ln (2)}]_{0}^{1} - (\frac{2}{\ln (2)} \int_{0}^{1} 2^{x} x d x)$

$\frac{x^{2} \cdot 2^{x}}{\ln (2)}]_{0}^{1} - \frac{2}{\ln (2)} \int_{0}^{1} 2^{x} x d x$

Step 5

Integrate by parts using the formula $\int u d v = u v - \int v d u$ , where $u = x$ and $d v = 2^{x}$ .

$\frac{x^{2} \cdot 2^{x}}{\ln (2)}]_{0}^{1} - \frac{2}{\ln (2)} (x (\frac{1}{\ln (2)} \cdot 2^{x})]_{0}^{1} - \int_{0}^{1} \frac{1}{\ln (2)} \cdot 2^{x} d x)$

Step 6

Simplify.

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Step 6.1

Combine $\frac{1}{\ln (2)}$ and $2^{x}$ .

$\frac{x^{2} \cdot 2^{x}}{\ln (2)}]_{0}^{1} - \frac{2}{\ln (2)} (x \frac{2^{x}}{\ln (2)}]_{0}^{1} - \int_{0}^{1} \frac{1}{\ln (2)} \cdot 2^{x} d x)$

Step 6.2

Combine $x$ and $\frac{2^{x}}{\ln (2)}$ .

$\frac{x^{2} \cdot 2^{x}}{\ln (2)}]_{0}^{1} - \frac{2}{\ln (2)} (\frac{x \cdot 2^{x}}{\ln (2)}]_{0}^{1} - \int_{0}^{1} \frac{1}{\ln (2)} \cdot 2^{x} d x)$

Step 6.3

Combine $\frac{1}{\ln (2)}$ and $2^{x}$ .

$\frac{x^{2} \cdot 2^{x}}{\ln (2)}]_{0}^{1} - \frac{2}{\ln (2)} (\frac{x \cdot 2^{x}}{\ln (2)}]_{0}^{1} - \int_{0}^{1} \frac{2^{x}}{\ln (2)} d x)$

Step 7

Since $\frac{1}{\ln (2)}$ is constant with respect to $x$ , move $\frac{1}{\ln (2)}$ out of the integral.

$\frac{x^{2} \cdot 2^{x}}{\ln (2)}]_{0}^{1} - \frac{2}{\ln (2)} (\frac{x \cdot 2^{x}}{\ln (2)}]_{0}^{1} - (\frac{1}{\ln (2)} \int_{0}^{1} 2^{x} d x))$

Step 8

The integral of $2^{x}$ with respect to $x$ is $\frac{2^{x}}{\ln (2)}$ .

$\frac{x^{2} \cdot 2^{x}}{\ln (2)}]_{0}^{1} - \frac{2}{\ln (2)} (\frac{x \cdot 2^{x}}{\ln (2)}]_{0}^{1} - \frac{1}{\ln (2)} \frac{2^{x}}{\ln (2)}]_{0}^{1})$

Step 9

Simplify the answer.

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Step 9.1

Combine $\frac{2^{x}}{\ln (2)}]_{0}^{1}$ and $\frac{1}{\ln (2)}$ .

$\frac{x^{2} \cdot 2^{x}}{\ln (2)}]_{0}^{1} - \frac{2}{\ln (2)} (\frac{x \cdot 2^{x}}{\ln (2)}]_{0}^{1} - \frac{\frac{2^{x}}{\ln (2)}]_{0}^{1}}{\ln (2)})$

Step 9.2

Substitute and simplify.

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Step 9.2.1

Evaluate $\frac{x^{2} \cdot 2^{x}}{\ln (2)}$ at $1$ and at $0$ .

$(\frac{1^{2} \cdot 2^{1}}{\ln (2)}) - \frac{0^{2} \cdot 2^{0}}{\ln (2)} - \frac{2}{\ln (2)} (\frac{x \cdot 2^{x}}{\ln (2)}]_{0}^{1} - \frac{\frac{2^{x}}{\ln (2)}]_{0}^{1}}{\ln (2)})$

Step 9.2.2

Evaluate $\frac{x \cdot 2^{x}}{\ln (2)}$ at $1$ and at $0$ .

$(\frac{1^{2} \cdot 2^{1}}{\ln (2)}) - \frac{0^{2} \cdot 2^{0}}{\ln (2)} - \frac{2}{\ln (2)} ((\frac{1 \cdot 2^{1}}{\ln (2)}) - \frac{0 \cdot 2^{0}}{\ln (2)} - \frac{\frac{2^{x}}{\ln (2)}]_{0}^{1}}{\ln (2)})$

Step 9.2.3

Evaluate $\frac{2^{x}}{\ln (2)}$ at $1$ and at $0$ .

$(\frac{1^{2} \cdot 2^{1}}{\ln (2)}) - \frac{0^{2} \cdot 2^{0}}{\ln (2)} - \frac{2}{\ln (2)} ((\frac{1 \cdot 2^{1}}{\ln (2)}) - \frac{0 \cdot 2^{0}}{\ln (2)} - \frac{(\frac{2^{1}}{\ln (2)}) - \frac{2^{0}}{\ln (2)}}{\ln (2)})$

Step 9.2.4

Simplify.

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Step 9.2.4.1

One to any power is one.

$\frac{1 \cdot 2^{1}}{\ln (2)} - \frac{0^{2} \cdot 2^{0}}{\ln (2)} - \frac{2}{\ln (2)} ((\frac{1 \cdot 2^{1}}{\ln (2)}) - \frac{0 \cdot 2^{0}}{\ln (2)} - \frac{(\frac{2^{1}}{\ln (2)}) - \frac{2^{0}}{\ln (2)}}{\ln (2)})$

Step 9.2.4.2

Evaluate the exponent.

$\frac{1 \cdot 2}{\ln (2)} - \frac{0^{2} \cdot 2^{0}}{\ln (2)} - \frac{2}{\ln (2)} ((\frac{1 \cdot 2^{1}}{\ln (2)}) - \frac{0 \cdot 2^{0}}{\ln (2)} - \frac{(\frac{2^{1}}{\ln (2)}) - \frac{2^{0}}{\ln (2)}}{\ln (2)})$

Step 9.2.4.3

Multiply $2$ by $1$ .

$\frac{2}{\ln (2)} - \frac{0^{2} \cdot 2^{0}}{\ln (2)} - \frac{2}{\ln (2)} ((\frac{1 \cdot 2^{1}}{\ln (2)}) - \frac{0 \cdot 2^{0}}{\ln (2)} - \frac{(\frac{2^{1}}{\ln (2)}) - \frac{2^{0}}{\ln (2)}}{\ln (2)})$

Step 9.2.4.4

Raising $0$ to any positive power yields $0$ .

$\frac{2}{\ln (2)} - \frac{0 \cdot 2^{0}}{\ln (2)} - \frac{2}{\ln (2)} ((\frac{1 \cdot 2^{1}}{\ln (2)}) - \frac{0 \cdot 2^{0}}{\ln (2)} - \frac{(\frac{2^{1}}{\ln (2)}) - \frac{2^{0}}{\ln (2)}}{\ln (2)})$

Step 9.2.4.5

Anything raised to $0$ is $1$ .

$\frac{2}{\ln (2)} - \frac{0 \cdot 1}{\ln (2)} - \frac{2}{\ln (2)} ((\frac{1 \cdot 2^{1}}{\ln (2)}) - \frac{0 \cdot 2^{0}}{\ln (2)} - \frac{(\frac{2^{1}}{\ln (2)}) - \frac{2^{0}}{\ln (2)}}{\ln (2)})$

Step 9.2.4.6

Multiply $0$ by $1$ .

$\frac{2}{\ln (2)} - \frac{0}{\ln (2)} - \frac{2}{\ln (2)} ((\frac{1 \cdot 2^{1}}{\ln (2)}) - \frac{0 \cdot 2^{0}}{\ln (2)} - \frac{(\frac{2^{1}}{\ln (2)}) - \frac{2^{0}}{\ln (2)}}{\ln (2)})$

Step 9.2.4.7

Combine the numerators over the common denominator.

$\frac{2 + 0}{\ln (2)} - \frac{2}{\ln (2)} ((\frac{1 \cdot 2^{1}}{\ln (2)}) - \frac{0 \cdot 2^{0}}{\ln (2)} - \frac{(\frac{2^{1}}{\ln (2)}) - \frac{2^{0}}{\ln (2)}}{\ln (2)})$

Step 9.2.4.8

Add $2$ and $0$ .

$\frac{2}{\ln (2)} - \frac{2}{\ln (2)} ((\frac{1 \cdot 2^{1}}{\ln (2)}) - \frac{0 \cdot 2^{0}}{\ln (2)} - \frac{(\frac{2^{1}}{\ln (2)}) - \frac{2^{0}}{\ln (2)}}{\ln (2)})$

Step 9.2.4.9

Evaluate the exponent.

$\frac{2}{\ln (2)} - \frac{2}{\ln (2)} (\frac{1 \cdot 2}{\ln (2)} - \frac{0 \cdot 2^{0}}{\ln (2)} - \frac{(\frac{2^{1}}{\ln (2)}) - \frac{2^{0}}{\ln (2)}}{\ln (2)})$

Step 9.2.4.10

Multiply $2$ by $1$ .

$\frac{2}{\ln (2)} - \frac{2}{\ln (2)} (\frac{2}{\ln (2)} - \frac{0 \cdot 2^{0}}{\ln (2)} - \frac{(\frac{2^{1}}{\ln (2)}) - \frac{2^{0}}{\ln (2)}}{\ln (2)})$

Step 9.2.4.11

Anything raised to $0$ is $1$ .

$\frac{2}{\ln (2)} - \frac{2}{\ln (2)} (\frac{2}{\ln (2)} - \frac{0 \cdot 1}{\ln (2)} - \frac{(\frac{2^{1}}{\ln (2)}) - \frac{2^{0}}{\ln (2)}}{\ln (2)})$

Step 9.2.4.12

Multiply $0$ by $1$ .

$\frac{2}{\ln (2)} - \frac{2}{\ln (2)} (\frac{2}{\ln (2)} - \frac{0}{\ln (2)} - \frac{(\frac{2^{1}}{\ln (2)}) - \frac{2^{0}}{\ln (2)}}{\ln (2)})$

Step 9.2.4.13

Combine the numerators over the common denominator.

$\frac{2}{\ln (2)} - \frac{2}{\ln (2)} (\frac{2 + 0}{\ln (2)} - \frac{(\frac{2^{1}}{\ln (2)}) - \frac{2^{0}}{\ln (2)}}{\ln (2)})$

Step 9.2.4.14

Add $2$ and $0$ .

$\frac{2}{\ln (2)} - \frac{2}{\ln (2)} (\frac{2}{\ln (2)} - \frac{(\frac{2^{1}}{\ln (2)}) - \frac{2^{0}}{\ln (2)}}{\ln (2)})$

Step 9.2.4.15

Evaluate the exponent.

$\frac{2}{\ln (2)} - \frac{2}{\ln (2)} (\frac{2}{\ln (2)} - \frac{\frac{2}{\ln (2)} - \frac{2^{0}}{\ln (2)}}{\ln (2)})$

Step 9.2.4.16

Anything raised to $0$ is $1$ .

$\frac{2}{\ln (2)} - \frac{2}{\ln (2)} (\frac{2}{\ln (2)} - \frac{\frac{2}{\ln (2)} - \frac{1}{\ln (2)}}{\ln (2)})$

Step 9.2.4.17

Combine the numerators over the common denominator.

$\frac{2}{\ln (2)} - \frac{2}{\ln (2)} (\frac{2}{\ln (2)} - \frac{\frac{2 - 1}{\ln (2)}}{\ln (2)})$

Step 9.2.4.18

Subtract $1$ from $2$ .

$\frac{2}{\ln (2)} - \frac{2}{\ln (2)} (\frac{2}{\ln (2)} - \frac{\frac{1}{\ln (2)}}{\ln (2)})$

Step 9.2.4.19

Rewrite $\frac{\frac{1}{\ln (2)}}{\ln (2)}$ as a product.

$\frac{2}{\ln (2)} - \frac{2}{\ln (2)} (\frac{2}{\ln (2)} - (\frac{1}{\ln (2)} \cdot \frac{1}{\ln (2)}))$

Step 9.2.4.20

Multiply $\frac{1}{\ln (2)}$ by $\frac{1}{\ln (2)}$ .

$\frac{2}{\ln (2)} - \frac{2}{\ln (2)} (\frac{2}{\ln (2)} - \frac{1}{\ln (2) \ln (2)})$

Step 9.2.4.21

Raise $\ln (2)$ to the power of $1$ .

$\frac{2}{\ln (2)} - \frac{2}{\ln (2)} (\frac{2}{\ln (2)} - \frac{1}{\ln^{1} (2) \ln (2)})$

Step 9.2.4.22

Raise $\ln (2)$ to the power of $1$ .

$\frac{2}{\ln (2)} - \frac{2}{\ln (2)} (\frac{2}{\ln (2)} - \frac{1}{\ln^{1} (2) \ln^{1} (2)})$

Step 9.2.4.23

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2}{\ln (2)} - \frac{2}{\ln (2)} (\frac{2}{\ln (2)} - \frac{1}{{\ln (2)}^{1 + 1}})$

Step 9.2.4.24

Add $1$ and $1$ .

$\frac{2}{\ln (2)} - \frac{2}{\ln (2)} (\frac{2}{\ln (2)} - \frac{1}{\ln^{2} (2)})$

Step 9.2.4.25

To write $- \frac{2}{\ln (2)} (\frac{2}{\ln (2)} - \frac{1}{\ln^{2} (2)})$ as a fraction with a common denominator, multiply by $\frac{\ln (2)}{\ln (2)}$ .

$\frac{2}{\ln (2)} - \frac{2}{\ln (2)} (\frac{2}{\ln (2)} - \frac{1}{\ln^{2} (2)}) \cdot \frac{\ln (2)}{\ln (2)}$

Step 9.2.4.26

Combine $- \frac{2}{\ln (2)} (\frac{2}{\ln (2)} - \frac{1}{\ln^{2} (2)})$ and $\frac{\ln (2)}{\ln (2)}$ .

$\frac{2}{\ln (2)} + \frac{- \frac{2}{\ln (2)} (\frac{2}{\ln (2)} - \frac{1}{\ln^{2} (2)}) \ln (2)}{\ln (2)}$

Step 9.2.4.27

Combine the numerators over the common denominator.

$\frac{2 - \frac{2}{\ln (2)} (\frac{2}{\ln (2)} - \frac{1}{\ln^{2} (2)}) \ln (2)}{\ln (2)}$

Step 9.2.4.28

Combine $\ln (2)$ and $\frac{2}{\ln (2)}$ .

$\frac{2 - \frac{\ln (2) \cdot 2}{\ln (2)} (\frac{2}{\ln (2)} - \frac{1}{\ln^{2} (2)})}{\ln (2)}$

Step 9.2.4.29

Move $2$ to the left of $\ln (2)$ .

$\frac{2 - \frac{2 \cdot \ln (2)}{\ln (2)} (\frac{2}{\ln (2)} - \frac{1}{\ln^{2} (2)})}{\ln (2)}$

Step 9.2.4.30

Cancel the common factor of $\ln (2)$ .

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Step 9.2.4.30.1

Cancel the common factor.

$\frac{2 - \frac{2 \ln (2)}{\ln (2)} (\frac{2}{\ln (2)} - \frac{1}{\ln^{2} (2)})}{\ln (2)}$

Step 9.2.4.30.2

Divide $2$ by $1$ .

$\frac{2 - 1 \cdot 2 (\frac{2}{\ln (2)} - \frac{1}{\ln^{2} (2)})}{\ln (2)}$

Step 9.2.4.31

Multiply $- 1$ by $2$ .

$\frac{2 - 2 (\frac{2}{\ln (2)} - \frac{1}{\ln^{2} (2)})}{\ln (2)}$

Step 10

Simplify.

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Step 10.1

Simplify the numerator.

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Step 10.1.1

Apply the distributive property.

$\frac{2 - 2 \frac{2}{\ln (2)} - 2 (- \frac{1}{\ln^{2} (2)})}{\ln (2)}$

Step 10.1.2

Multiply $- 2 \frac{2}{\ln (2)}$ .

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Step 10.1.2.1

Combine $- 2$ and $\frac{2}{\ln (2)}$ .

$\frac{2 + \frac{- 2 \cdot 2}{\ln (2)} - 2 (- \frac{1}{\ln^{2} (2)})}{\ln (2)}$

Step 10.1.2.2

Multiply $- 2$ by $2$ .

$\frac{2 + \frac{- 4}{\ln (2)} - 2 (- \frac{1}{\ln^{2} (2)})}{\ln (2)}$

Step 10.1.3

Multiply $- 2 (- \frac{1}{\ln^{2} (2)})$ .

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Step 10.1.3.1

Multiply $- 1$ by $- 2$ .

$\frac{2 + \frac{- 4}{\ln (2)} + 2 \frac{1}{\ln^{2} (2)}}{\ln (2)}$

Step 10.1.3.2

Combine $2$ and $\frac{1}{\ln^{2} (2)}$ .

$\frac{2 + \frac{- 4}{\ln (2)} + \frac{2}{\ln^{2} (2)}}{\ln (2)}$

Step 10.1.4

Move the negative in front of the fraction.

$\frac{2 - \frac{4}{\ln (2)} + \frac{2}{\ln^{2} (2)}}{\ln (2)}$

Step 10.1.5

To write $2$ as a fraction with a common denominator, multiply by $\frac{\ln (2)}{\ln (2)}$ .

$\frac{\frac{2 \ln (2)}{\ln (2)} - \frac{4}{\ln (2)} + \frac{2}{\ln^{2} (2)}}{\ln (2)}$

Step 10.1.6

Combine the numerators over the common denominator.

$\frac{\frac{2 \ln (2) - 4}{\ln (2)} + \frac{2}{\ln^{2} (2)}}{\ln (2)}$

Step 10.1.7

To write $\frac{2 \ln (2) - 4}{\ln (2)}$ as a fraction with a common denominator, multiply by $\frac{\ln (2)}{\ln (2)}$ .

$\frac{\frac{2 \ln (2) - 4}{\ln (2)} \cdot \frac{\ln (2)}{\ln (2)} + \frac{2}{\ln^{2} (2)}}{\ln (2)}$

Step 10.1.8

Write each expression with a common denominator of $\ln^{2} (2)$ , by multiplying each by an appropriate factor of $1$ .

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Step 10.1.8.1

Multiply $\frac{2 \ln (2) - 4}{\ln (2)}$ by $\frac{\ln (2)}{\ln (2)}$ .

$\frac{\frac{(2 \ln (2) - 4) \ln (2)}{\ln (2) \ln (2)} + \frac{2}{\ln^{2} (2)}}{\ln (2)}$

Step 10.1.8.2

Raise $\ln (2)$ to the power of $1$ .

$\frac{\frac{(2 \ln (2) - 4) \ln (2)}{\ln^{1} (2) \ln (2)} + \frac{2}{\ln^{2} (2)}}{\ln (2)}$

Step 10.1.8.3

Raise $\ln (2)$ to the power of $1$ .

$\frac{\frac{(2 \ln (2) - 4) \ln (2)}{\ln^{1} (2) \ln^{1} (2)} + \frac{2}{\ln^{2} (2)}}{\ln (2)}$

Step 10.1.8.4

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{\frac{(2 \ln (2) - 4) \ln (2)}{{\ln (2)}^{1 + 1}} + \frac{2}{\ln^{2} (2)}}{\ln (2)}$

Step 10.1.8.5

Add $1$ and $1$ .

$\frac{\frac{(2 \ln (2) - 4) \ln (2)}{\ln^{2} (2)} + \frac{2}{\ln^{2} (2)}}{\ln (2)}$

Step 10.1.9

Combine the numerators over the common denominator.

$\frac{\frac{(2 \ln (2) - 4) \ln (2) + 2}{\ln^{2} (2)}}{\ln (2)}$

Step 10.1.10

Simplify the numerator.

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Step 10.1.10.1

Apply the distributive property.

$\frac{\frac{2 \ln (2) \ln (2) - 4 \ln (2) + 2}{\ln^{2} (2)}}{\ln (2)}$

Step 10.1.10.2

Multiply $2 \ln (2) \ln (2)$ .

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Step 10.1.10.2.1

Raise $\ln (2)$ to the power of $1$ .

$\frac{\frac{2 (\ln^{1} (2) \ln (2)) - 4 \ln (2) + 2}{\ln^{2} (2)}}{\ln (2)}$

Step 10.1.10.2.2

Raise $\ln (2)$ to the power of $1$ .

$\frac{\frac{2 (\ln^{1} (2) \ln^{1} (2)) - 4 \ln (2) + 2}{\ln^{2} (2)}}{\ln (2)}$

Step 10.1.10.2.3

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{\frac{2 {\ln (2)}^{1 + 1} - 4 \ln (2) + 2}{\ln^{2} (2)}}{\ln (2)}$

Step 10.1.10.2.4

Add $1$ and $1$ .

$\frac{\frac{2 \ln^{2} (2) - 4 \ln (2) + 2}{\ln^{2} (2)}}{\ln (2)}$

Step 10.2

Multiply the numerator by the reciprocal of the denominator.

$\frac{2 \ln^{2} (2) - 4 \ln (2) + 2}{\ln^{2} (2)} \cdot \frac{1}{\ln (2)}$

Step 10.3

Multiply $\frac{2 \ln^{2} (2) - 4 \ln (2) + 2}{\ln^{2} (2)} \cdot \frac{1}{\ln (2)}$ .

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Step 10.3.1

Multiply $\frac{2 \ln^{2} (2) - 4 \ln (2) + 2}{\ln^{2} (2)}$ by $\frac{1}{\ln (2)}$ .

$\frac{2 \ln^{2} (2) - 4 \ln (2) + 2}{\ln^{2} (2) \ln (2)}$

Step 10.3.2

Multiply $\ln^{2} (2)$ by $\ln (2)$ by adding the exponents.

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Step 10.3.2.1

Multiply $\ln^{2} (2)$ by $\ln (2)$ .

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Step 10.3.2.1.1

Raise $\ln (2)$ to the power of $1$ .

$\frac{2 \ln^{2} (2) - 4 \ln (2) + 2}{\ln^{2} (2) \ln^{1} (2)}$

Step 10.3.2.1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 \ln^{2} (2) - 4 \ln (2) + 2}{{\ln (2)}^{2 + 1}}$

Step 10.3.2.2

Add $2$ and $1$ .

$\frac{2 \ln^{2} (2) - 4 \ln (2) + 2}{\ln^{3} (2)}$

Step 11

The result can be shown in multiple forms.

Exact Form:

$\frac{2 \ln^{2} (2) - 4 \ln (2) + 2}{\ln^{3} (2)}$

Decimal Form:

$0.56547557 \dots$

Step 12