Calculus Examples

$f (x) = \tan (x) \sec^{2} (x)$

Step 1

The function $F (x)$ can be found by finding the indefinite integral of the derivative $f (x)$ .

$F (x) = \int f (x) d x$

Step 2

Set up the integral to solve.

$F (x) = \int \tan (x) \sec^{2} (x) d x$

Step 3

Let $u = \sec (x)$ . Then $d u = \sec (x) \tan (x) d x$ , so $\frac{1}{\sec (x) \tan (x)} d u = d x$ . Rewrite using $u$ and $d$ $u$ .

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Step 3.1

Let $u = \sec (x)$ . Find $\frac{d u}{d x}$ .

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Step 3.1.1

Differentiate $\sec (x)$ .

$\frac{d}{d x} [\sec (x)]$

Step 3.1.2

The derivative of $\sec (x)$ with respect to $x$ is $\sec (x) \tan (x)$ .

$\sec (x) \tan (x)$

Step 3.2

Rewrite the problem using $u$ and $d u$ .

$\int u d u$

Step 4

By the Power Rule, the integral of $u$ with respect to $u$ is $\frac{1}{2} u^{2}$ .

$\frac{1}{2} u^{2} + C$

Step 5

Replace all occurrences of $u$ with $\sec (x)$ .

$\frac{1}{2} \sec^{2} (x) + C$

Step 6

The answer is the antiderivative of the function $f (x) = \tan (x) \sec^{2} (x)$ .

$F (x) =$ $\frac{1}{2} \sec^{2} (x) + C$