Calculus Examples

$\frac{d y}{d x} = \frac{1}{\sqrt{36 - x^{2}}}$ , $y (0) = π$

Step 1

Rewrite the differential equation.

$y' = \frac{1}{\sqrt{36 - x^{2}}}$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$