Calculus Examples

$\frac{d y}{d t} - 2 t y = 0$

Step 1

The integrating factor is defined by the formula $e^{\int P (t) d t}$ , where $P (t) = - 2 t$ .

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Step 1.1

Set up the integration.

$e^{\int - 2 t d t}$

Step 1.2

Integrate $- 2 t$ .

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Step 1.2.1

Since $- 2$ is constant with respect to $t$ , move $- 2$ out of the integral.

$e^{- 2 \int t d t}$

Step 1.2.2

By the Power Rule, the integral of $t$ with respect to $t$ is $\frac{1}{2} t^{2}$ .

$e^{- 2 (\frac{1}{2} t^{2} + C)}$

Step 1.2.3

Simplify the answer.

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Step 1.2.3.1

Rewrite $- 2 (\frac{1}{2} t^{2} + C)$ as $- 2 (\frac{1}{2}) t^{2} + C$ .

$e^{- 2 (\frac{1}{2}) t^{2} + C}$

Step 1.2.3.2

Simplify.

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Step 1.2.3.2.1

Combine $- 2$ and $\frac{1}{2}$ .

$e^{\frac{- 2}{2} t^{2} + C}$

Step 1.2.3.2.2

Cancel the common factor of $- 2$ and $2$ .

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Step 1.2.3.2.2.1

Factor $2$ out of $- 2$ .

$e^{\frac{2 \cdot - 1}{2} t^{2} + C}$

Step 1.2.3.2.2.2

Cancel the common factors.

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Step 1.2.3.2.2.2.1

Factor $2$ out of $2$ .

$e^{\frac{2 \cdot - 1}{2 (1)} t^{2} + C}$

Step 1.2.3.2.2.2.2

Cancel the common factor.

$e^{\frac{2 \cdot - 1}{2 \cdot 1} t^{2} + C}$

Step 1.2.3.2.2.2.3

Rewrite the expression.

$e^{\frac{- 1}{1} t^{2} + C}$

Step 1.2.3.2.2.2.4

Divide $- 1$ by $1$ .

$e^{- t^{2} + C}$

Step 1.3

Remove the constant of integration.

$e^{- t^{2}}$

Step 2

Multiply each term by the integrating factor $e^{- t^{2}}$ .

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Step 2.1

Multiply each term by $e^{- t^{2}}$ .

$e^{- t^{2}} \frac{d y}{d t} + e^{- t^{2}} (- 2 t y) = e^{- t^{2}} \cdot 0$

Step 2.2

Rewrite using the commutative property of multiplication.

$e^{- t^{2}} \frac{d y}{d t} - 2 e^{- t^{2}} (t y) = e^{- t^{2}} \cdot 0$

Step 2.3

Multiply $e^{- t^{2}}$ by $0$ .

$e^{- t^{2}} \frac{d y}{d t} - 2 e^{- t^{2}} (t y) = 0$

Step 2.4

Reorder factors in $e^{- t^{2}} \frac{d y}{d t} - 2 e^{- t^{2}} (t y) = 0$ .

$e^{- t^{2}} \frac{d y}{d t} - 2 t y e^{- t^{2}} = 0$

Step 3

Rewrite the left side as a result of differentiating a product.

$\frac{d}{d t} [e^{- t^{2}} y] = 0$

Step 4

Set up an integral on each side.

$\int \frac{d}{d t} [e^{- t^{2}} y] d t = \int 0 d t$

Step 5

Integrate the left side.

$e^{- t^{2}} y = \int 0 d t$

Step 6

Integrate the right side.

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Step 6.1

The integral of $0$ with respect to $t$ is $0$ .

$e^{- t^{2}} y = 0 + C$

Step 6.2

Add $0$ and $C$ .

$e^{- t^{2}} y = C$

Step 7

Divide each term in $e^{- t^{2}} y = C$ by $e^{- t^{2}}$ and simplify.

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Step 7.1

Divide each term in $e^{- t^{2}} y = C$ by $e^{- t^{2}}$ .

$\frac{e^{- t^{2}} y}{e^{- t^{2}}} = \frac{C}{e^{- t^{2}}}$

Step 7.2

Simplify the left side.

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Step 7.2.1

Cancel the common factor of $e^{- t^{2}}$ .

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Step 7.2.1.1

Cancel the common factor.

$\frac{e^{- t^{2}} y}{e^{- t^{2}}} = \frac{C}{e^{- t^{2}}}$

Step 7.2.1.2

Divide $y$ by $1$ .

$y = \frac{C}{e^{- t^{2}}}$