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Calculus
Solve the Differential Equation 3(3x^2+y^2)dx-2x^2dy=0
3
(
3
x
2
+
y
2
)
d
x
−
2
x
2
d
y
=
0
3
(
3
x
2
+
y
2
)
d
x
-
2
x
2
d
y
=
0
Step 1
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expression
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3
(
3
x
2
+
y
2
)
d
x
−
2
x
2
d
y
=
0
3
(
3
x
2
+
y
2
)
d
x
-
2
x
2
d
y
=
0
⎡
⎢
⎣
x
2
1
2
√
π
∫
x
d
x
⎤
⎥
⎦
[
x
2
1
2
π
∫
x
d
x
]
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