Calculus Examples

$\frac{d y}{d x} = x^{8} e^{x^{9}}$

Step 1

Rewrite the equation.

$d y = x^{8} e^{x^{9}} d x$

Step 2

Integrate both sides.

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Step 2.1

Set up an integral on each side.

$\int d y = \int x^{8} e^{x^{9}} d x$

Step 2.2

Apply the constant rule.

$y + C_{1} = \int x^{8} e^{x^{9}} d x$

Step 2.3

Integrate the right side.

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Step 2.3.1

Let $u_{2} = e^{x^{9}}$ . Then $d u_{2} = 9 x^{8} e^{x^{9}} d x$ , so $\frac{1}{9} d u_{2} = x^{8} e^{x^{9}} d x$ . Rewrite using $u_{2}$ and $d$ $u_{2}$ .

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Step 2.3.1.1

Let $u_{2} = e^{x^{9}}$ . Find $\frac{d u_{2}}{d x}$ .

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Step 2.3.1.1.1

Differentiate $e^{x^{9}}$ .

$\frac{d}{d x} [e^{x^{9}}]$

Step 2.3.1.1.2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = e^{x}$ and $g (x) = x^{9}$ .

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Step 2.3.1.1.2.1

To apply the Chain Rule, set $u_{1}$ as $x^{9}$ .

$\frac{d}{d u_{1}} [e^{u_{1}}] \frac{d}{d x} [x^{9}]$

Step 2.3.1.1.2.2

Differentiate using the Exponential Rule which states that $\frac{d}{d u_{1}} [a^{u_{1}}]$ is $a^{u_{1}} \ln (a)$ where $a$ = $e$ .

$e^{u_{1}} \frac{d}{d x} [x^{9}]$

Step 2.3.1.1.2.3

Replace all occurrences of $u_{1}$ with $x^{9}$ .

$e^{x^{9}} \frac{d}{d x} [x^{9}]$

Step 2.3.1.1.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 9$ .

$e^{x^{9}} (9 x^{8})$

Step 2.3.1.1.4

Simplify.

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Step 2.3.1.1.4.1

Reorder the factors of $e^{x^{9}} (9 x^{8})$ .

$9 e^{x^{9}} x^{8}$

Step 2.3.1.1.4.2

Reorder factors in $9 e^{x^{9}} x^{8}$ .

$9 x^{8} e^{x^{9}}$

Step 2.3.1.2

Rewrite the problem using $u_{2}$ and $d u_{2}$ .

$y + C_{1} = \int \frac{1}{9} d u_{2}$

Step 2.3.2

Apply the constant rule.

$y + C_{1} = \frac{1}{9} u_{2} + C_{2}$

Step 2.3.3

Replace all occurrences of $u_{2}$ with $e^{x^{9}}$ .

$y + C_{1} = \frac{1}{9} e^{x^{9}} + C_{2}$

Step 2.4

Group the constant of integration on the right side as $K$ .

$y = \frac{1}{9} e^{x^{9}} + K$