Calculus Examples

$\frac{d x}{d t} = 1 + x^{2}$

Step 1

Separate the variables.

Tap for more steps...

Step 1.1

Multiply both sides by $\frac{1}{1 + x^{2}}$ .

$\frac{1}{1 + x^{2}} \frac{d x}{d t} = \frac{1}{1 + x^{2}} (1 + x^{2})$

Step 1.2

Cancel the common factor of $1 + x^{2}$ .

Tap for more steps...

Step 1.2.1

Cancel the common factor.

$\frac{1}{1 + x^{2}} \frac{d x}{d t} = \frac{1}{1 + x^{2}} (1 + x^{2})$

Step 1.2.2

Rewrite the expression.

$\frac{1}{1 + x^{2}} \frac{d x}{d t} = 1$

Step 1.3

Rewrite the equation.

$\frac{1}{1 + x^{2}} d x = 1 d t$

Step 2

Integrate both sides.

Tap for more steps...

Step 2.1

Set up an integral on each side.

$\int \frac{1}{1 + x^{2}} d x = \int d t$

Step 2.2

Integrate the left side.

Tap for more steps...

Step 2.2.1

Rewrite $1$ as $1^{2}$ .

$\int \frac{1}{1^{2} + x^{2}} d x = \int d t$

Step 2.2.2

The integral of $\frac{1}{1^{2} + x^{2}}$ with respect to $x$ is $\arctan (x) + C_{1}$ .

$\arctan (x) + C_{1} = \int d t$

Step 2.3

Apply the constant rule.

$\arctan (x) + C_{1} = t + C_{2}$

Step 2.4

Group the constant of integration on the right side as $K$ .

$\arctan (x) = t + K$

Step 3

Take the inverse arctangent of both sides of the equation to extract $x$ from inside the arctangent.

$x = \tan (t + K)$