Calculus Examples

$\frac{d y}{d x} + e^{- x} = 0$

Step 1

Separate the variables.

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Step 1.1

Subtract $e^{- x}$ from both sides of the equation.

$\frac{d y}{d x} = - e^{- x}$

Step 1.2

Rewrite the equation.

$d y = - e^{- x} d x$

Step 2

Integrate both sides.

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Step 2.1

Set up an integral on each side.

$\int d y = \int - e^{- x} d x$

Step 2.2

Apply the constant rule.

$y + C_{1} = \int - e^{- x} d x$

Step 2.3

Integrate the right side.

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Step 2.3.1

Since $- 1$ is constant with respect to $x$ , move $- 1$ out of the integral.

$y + C_{1} = - \int e^{- x} d x$

Step 2.3.2

Let $u = - x$ . Then $d u = - d x$ , so $- d u = d x$ . Rewrite using $u$ and $d$ $u$ .

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Step 2.3.2.1

Let $u = - x$ . Find $\frac{d u}{d x}$ .

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Step 2.3.2.1.1

Differentiate $- x$ .

$\frac{d}{d x} [- x]$

Step 2.3.2.1.2

Since $- 1$ is constant with respect to $x$ , the derivative of $- x$ with respect to $x$ is $- \frac{d}{d x} [x]$ .

$- \frac{d}{d x} [x]$

Step 2.3.2.1.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$- 1 \cdot 1$

Step 2.3.2.1.4

Multiply $- 1$ by $1$ .

$- 1$

Step 2.3.2.2

Rewrite the problem using $u$ and $d u$ .

$y + C_{1} = - \int - e^{u} d u$

Step 2.3.3

Since $- 1$ is constant with respect to $u$ , move $- 1$ out of the integral.

$y + C_{1} = - - \int e^{u} d u$

Step 2.3.4

Simplify.

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Step 2.3.4.1

Multiply $- 1$ by $- 1$ .

$y + C_{1} = 1 \int e^{u} d u$

Step 2.3.4.2

Multiply $\int e^{u} d u$ by $1$ .

$y + C_{1} = \int e^{u} d u$

Step 2.3.5

The integral of $e^{u}$ with respect to $u$ is $e^{u}$ .

$y + C_{1} = e^{u} + C_{2}$

Step 2.3.6

Replace all occurrences of $u$ with $- x$ .

$y + C_{1} = e^{- x} + C_{2}$

Step 2.4

Group the constant of integration on the right side as $K$ .

$y = e^{- x} + K$