Calculus Examples

$2 x d y + 3 y d x = 0$

Step 1

Subtract $3 y d x$ from both sides of the equation.

$2 x d y = - 3 y d x$

Step 2

Multiply both sides by $\frac{1}{x y}$ .

$\frac{1}{x y} (2 x) d y = \frac{1}{x y} (- 3 y) d x$

Step 3

Simplify.

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Step 3.1

Rewrite using the commutative property of multiplication.

$2 \frac{1}{x y} x d y = \frac{1}{x y} (- 3 y) d x$

Step 3.2

Combine $2$ and $\frac{1}{x y}$ .

$\frac{2}{x y} x d y = \frac{1}{x y} (- 3 y) d x$

Step 3.3

Cancel the common factor of $x$ .

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Step 3.3.1

Factor $x$ out of $x y$ .

$\frac{2}{x (y)} x d y = \frac{1}{x y} (- 3 y) d x$

Step 3.3.2

Cancel the common factor.

$\frac{2}{x y} x d y = \frac{1}{x y} (- 3 y) d x$

Step 3.3.3

Rewrite the expression.

$\frac{2}{y} d y = \frac{1}{x y} (- 3 y) d x$

Step 3.4

Rewrite using the commutative property of multiplication.

$\frac{2}{y} d y = - 3 \frac{1}{x y} y d x$

Step 3.5

Combine $- 3$ and $\frac{1}{x y}$ .

$\frac{2}{y} d y = \frac{- 3}{x y} y d x$

Step 3.6

Cancel the common factor of $y$ .

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Step 3.6.1

Factor $y$ out of $x y$ .

$\frac{2}{y} d y = \frac{- 3}{y x} y d x$

Step 3.6.2

Cancel the common factor.

$\frac{2}{y} d y = \frac{- 3}{y x} y d x$

Step 3.6.3

Rewrite the expression.

$\frac{2}{y} d y = \frac{- 3}{x} d x$

Step 3.7

Move the negative in front of the fraction.

$\frac{2}{y} d y = - \frac{3}{x} d x$

Step 4

Integrate both sides.

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Step 4.1

Set up an integral on each side.

$\int \frac{2}{y} d y = \int - \frac{3}{x} d x$

Step 4.2

Integrate the left side.

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Step 4.2.1

Since $2$ is constant with respect to $y$ , move $2$ out of the integral.

$2 \int \frac{1}{y} d y = \int - \frac{3}{x} d x$

Step 4.2.2

The integral of $\frac{1}{y}$ with respect to $y$ is $\ln (| y |)$ .

$2 (\ln (| y |) + C_{1}) = \int - \frac{3}{x} d x$

Step 4.2.3

Simplify.

$2 \ln (| y |) + C_{1} = \int - \frac{3}{x} d x$

Step 4.3

Integrate the right side.

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Step 4.3.1

Since $- 1$ is constant with respect to $x$ , move $- 1$ out of the integral.

$2 \ln (| y |) + C_{1} = - \int \frac{3}{x} d x$

Step 4.3.2

Since $3$ is constant with respect to $x$ , move $3$ out of the integral.

$2 \ln (| y |) + C_{1} = - (3 \int \frac{1}{x} d x)$

Step 4.3.3

Multiply $3$ by $- 1$ .

$2 \ln (| y |) + C_{1} = - 3 \int \frac{1}{x} d x$

Step 4.3.4

The integral of $\frac{1}{x}$ with respect to $x$ is $\ln (| x |)$ .

$2 \ln (| y |) + C_{1} = - 3 (\ln (| x |) + C_{2})$

Step 4.3.5

Simplify.

$2 \ln (| y |) + C_{1} = - 3 \ln (| x |) + C_{2}$

Step 4.4

Group the constant of integration on the right side as $C$ .

$2 \ln (| y |) = - 3 \ln (| x |) + C$

Step 5

Solve for $y$ .

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Step 5.1

Move all the terms containing a logarithm to the left side of the equation.

$2 \ln (| y |) + 3 \ln (| x |) = C$

Step 5.2

Simplify the left side.

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Step 5.2.1

Simplify $2 \ln (| y |) + 3 \ln (| x |)$ .

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Step 5.2.1.1

Simplify each term.

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Step 5.2.1.1.1

Simplify $2 \ln (| y |)$ by moving $2$ inside the logarithm.

$\ln ({| y |}^{2}) + 3 \ln (| x |) = C$

Step 5.2.1.1.2

Remove the absolute value in ${| y |}^{2}$ because exponentiations with even powers are always positive.

$\ln (y^{2}) + 3 \ln (| x |) = C$

Step 5.2.1.1.3

Simplify $3 \ln (| x |)$ by moving $3$ inside the logarithm.

$\ln (y^{2}) + \ln ({| x |}^{3}) = C$

Step 5.2.1.2

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\ln (y^{2} {| x |}^{3}) = C$

Step 5.3

To solve for $y$ , rewrite the equation using properties of logarithms.

$e^{\ln (y^{2} {| x |}^{3})} = e^{C}$

Step 5.4

Rewrite $\ln (y^{2} {| x |}^{3}) = C$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$e^{C} = y^{2} {| x |}^{3}$

Step 5.5

Solve for $y$ .

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Step 5.5.1

Rewrite the equation as $y^{2} {| x |}^{3} = e^{C}$ .

$y^{2} {| x |}^{3} = e^{C}$

Step 5.5.2

Divide each term in $y^{2} {| x |}^{3} = e^{C}$ by ${| x |}^{3}$ and simplify.

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Step 5.5.2.1

Divide each term in $y^{2} {| x |}^{3} = e^{C}$ by ${| x |}^{3}$ .

$\frac{y^{2} {| x |}^{3}}{{| x |}^{3}} = \frac{e^{C}}{{| x |}^{3}}$

Step 5.5.2.2

Simplify the left side.

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Step 5.5.2.2.1

Cancel the common factor of ${| x |}^{3}$ .

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Step 5.5.2.2.1.1

Cancel the common factor.

$\frac{y^{2} {| x |}^{3}}{{| x |}^{3}} = \frac{e^{C}}{{| x |}^{3}}$

Step 5.5.2.2.1.2

Divide $y^{2}$ by $1$ .

$y^{2} = \frac{e^{C}}{{| x |}^{3}}$

Step 5.5.3

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$y = \pm \sqrt{\frac{e^{C}}{{| x |}^{3}}}$

Step 5.5.4

Simplify $\pm \sqrt{\frac{e^{C}}{{| x |}^{3}}}$ .

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Step 5.5.4.1

Rewrite $\frac{e^{C}}{{| x |}^{3}}$ as ${(\frac{1}{| x |})}^{2} \frac{e^{C}}{| x |}$ .

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Step 5.5.4.1.1

Factor the perfect power $1^{2}$ out of $e^{C}$ .

$y = \pm \sqrt{\frac{1^{2} e^{C}}{{| x |}^{3}}}$

Step 5.5.4.1.2

Factor the perfect power ${| x |}^{2}$ out of ${| x |}^{3}$ .

$y = \pm \sqrt{\frac{1^{2} e^{C}}{{| x |}^{2} | x |}}$

Step 5.5.4.1.3

Rearrange the fraction $\frac{1^{2} e^{C}}{{| x |}^{2} | x |}$ .

$y = \pm \sqrt{{(\frac{1}{| x |})}^{2} \frac{e^{C}}{| x |}}$

Step 5.5.4.2

Pull terms out from under the radical.

$y = \pm \frac{1}{| x |} \sqrt{\frac{e^{C}}{| x |}}$

Step 5.5.4.3

Rewrite $\sqrt{\frac{e^{C}}{| x |}}$ as $\frac{\sqrt{e^{C}}}{\sqrt{| x |}}$ .

$y = \pm \frac{1}{| x |} \cdot \frac{\sqrt{e^{C}}}{\sqrt{| x |}}$

Step 5.5.4.4

Combine.

$y = \pm \frac{1 \sqrt{e^{C}}}{| x | \sqrt{| x |}}$

Step 5.5.4.5

Multiply $\sqrt{e^{C}}$ by $1$ .

$y = \pm \frac{\sqrt{e^{C}}}{| x | \sqrt{| x |}}$

Step 5.5.4.6

Multiply $\frac{\sqrt{e^{C}}}{| x | \sqrt{| x |}}$ by $\frac{\sqrt{| x |}}{\sqrt{| x |}}$ .

$y = \pm \frac{\sqrt{e^{C}}}{| x | \sqrt{| x |}} \cdot \frac{\sqrt{| x |}}{\sqrt{| x |}}$

Step 5.5.4.7

Combine and simplify the denominator.

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Step 5.5.4.7.1

Multiply $\frac{\sqrt{e^{C}}}{| x | \sqrt{| x |}}$ by $\frac{\sqrt{| x |}}{\sqrt{| x |}}$ .

$y = \pm \frac{\sqrt{e^{C}} \sqrt{| x |}}{| x | \sqrt{| x |} \sqrt{| x |}}$

Step 5.5.4.7.2

Move $\sqrt{| x |}$ .

$y = \pm \frac{\sqrt{e^{C}} \sqrt{| x |}}{| x | (\sqrt{| x |} \sqrt{| x |})}$

Step 5.5.4.7.3

Raise $\sqrt{| x |}$ to the power of $1$ .

$y = \pm \frac{\sqrt{e^{C}} \sqrt{| x |}}{| x | ({\sqrt{| x |}}^{1} \sqrt{| x |})}$

Step 5.5.4.7.4

Raise $\sqrt{| x |}$ to the power of $1$ .

$y = \pm \frac{\sqrt{e^{C}} \sqrt{| x |}}{| x | ({\sqrt{| x |}}^{1} {\sqrt{| x |}}^{1})}$

Step 5.5.4.7.5

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$y = \pm \frac{\sqrt{e^{C}} \sqrt{| x |}}{| x | {\sqrt{| x |}}^{1 + 1}}$

Step 5.5.4.7.6

Add $1$ and $1$ .

$y = \pm \frac{\sqrt{e^{C}} \sqrt{| x |}}{| x | {\sqrt{| x |}}^{2}}$

Step 5.5.4.7.7

Rewrite ${\sqrt{| x |}}^{2}$ as $| x |$ .

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Step 5.5.4.7.7.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{| x |}$ as ${| x |}^{\frac{1}{2}}$ .

$y = \pm \frac{\sqrt{e^{C}} \sqrt{| x |}}{| x | {({| x |}^{\frac{1}{2}})}^{2}}$

Step 5.5.4.7.7.2

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$y = \pm \frac{\sqrt{e^{C}} \sqrt{| x |}}{| x | {| x |}^{\frac{1}{2} \cdot 2}}$

Step 5.5.4.7.7.3

Combine $\frac{1}{2}$ and $2$ .

$y = \pm \frac{\sqrt{e^{C}} \sqrt{| x |}}{| x | {| x |}^{\frac{2}{2}}}$

Step 5.5.4.7.7.4

Cancel the common factor of $2$ .

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Step 5.5.4.7.7.4.1

Cancel the common factor.

$y = \pm \frac{\sqrt{e^{C}} \sqrt{| x |}}{| x | {| x |}^{\frac{2}{2}}}$

Step 5.5.4.7.7.4.2

Rewrite the expression.

$y = \pm \frac{\sqrt{e^{C}} \sqrt{| x |}}{| x | {| x |}^{1}}$

Step 5.5.4.7.7.5

Simplify.

$y = \pm \frac{\sqrt{e^{C}} \sqrt{| x |}}{| x | | x |}$

Step 5.5.4.8

Combine using the product rule for radicals.

$y = \pm \frac{\sqrt{e^{C} | x |}}{| x | | x |}$

Step 5.5.4.9

To multiply absolute values, multiply the terms inside each absolute value.

$y = \pm \frac{\sqrt{e^{C} | x |}}{| x \cdot x |}$

Step 5.5.4.10

Simplify the denominator.

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Step 5.5.4.10.1

Multiply $x$ by $x$ .

$y = \pm \frac{\sqrt{e^{C} | x |}}{| x^{2} |}$

Step 5.5.4.10.2

Remove non-negative terms from the absolute value.

$y = \pm \frac{\sqrt{e^{C} | x |}}{x^{2}}$

Step 5.5.5

The complete solution is the result of both the positive and negative portions of the solution.

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Step 5.5.5.1

First, use the positive value of the $\pm$ to find the first solution.