Calculus Examples

$\frac{d y}{d x} + (\frac{1}{x}) y = x y^{2}$

Step 1

To solve the differential equation, let $v = y^{1 - n}$ where $n$ is the exponent of $y^{2}$ .

$v = y^{- 1}$

Step 2

Solve the equation for $y$ .

$y = v^{- 1}$

Step 3

Take the derivative of $y$ with respect to $x$ .

$y' = v^{- 1}$

Step 4

Take the derivative of $v^{- 1}$ with respect to $x$ .

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Step 4.1

Take the derivative of $v^{- 1}$ .

$y' = \frac{d}{d x} [v^{- 1}]$

Step 4.2

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$y' = \frac{d}{d x} [\frac{1}{v}]$

Step 4.3

Differentiate using the Quotient Rule which states that $\frac{d}{d x} [\frac{f (x)}{g (x)}]$ is $\frac{g (x) \frac{d}{d x} [f (x)] - f (x) \frac{d}{d x} [g (x)]}{{g (x)}^{2}}$ where $f (x) = 1$ and $g (x) = v$ .

$y' = \frac{v \frac{d}{d x} [1] - 1 \cdot 1 \frac{d}{d x} [v]}{v^{2}}$

Step 4.4

Differentiate using the Constant Rule.

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Step 4.4.1

Multiply $- 1$ by $1$ .

$y' = \frac{v \frac{d}{d x} [1] - \frac{d}{d x} [v]}{v^{2}}$

Step 4.4.2

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$y' = \frac{v \cdot 0 - \frac{d}{d x} [v]}{v^{2}}$

Step 4.4.3

Simplify the expression.

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Step 4.4.3.1

Multiply $v$ by $0$ .

$y' = \frac{0 - \frac{d}{d x} [v]}{v^{2}}$

Step 4.4.3.2

Subtract $\frac{d}{d x} [v]$ from $0$ .

$y' = \frac{- \frac{d}{d x} [v]}{v^{2}}$

Step 4.4.3.3

Move the negative in front of the fraction.

$y' = - \frac{\frac{d}{d x} [v]}{v^{2}}$

Step 4.5

Rewrite $\frac{d}{d x} [v]$ as $v'$ .

$y' = - \frac{v'}{v^{2}}$

Step 5

Substitute $- \frac{v'}{v^{2}}$ for $\frac{d y}{d x}$ and $v^{- 1}$ for $y$ in the original equation $\frac{d y}{d x} + (\frac{1}{x}) y = x y^{2}$ .

$- \frac{v'}{v^{2}} + \frac{1}{x} v^{- 1} = x {(v^{- 1})}^{2}$

Step 6

Solve the substituted differential equation.

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Step 6.1

Rewrite the differential equation as $\frac{d v}{d x} + M (x) v = Q (x)$ .

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Step 6.1.1

Multiply each term in $- \frac{\frac{d v}{d x}}{v^{2}} + \frac{1}{x} v^{- 1} = x {(v^{- 1})}^{2}$ by $- v^{2}$ to eliminate the fractions.

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Step 6.1.1.1

Multiply each term in $- \frac{\frac{d v}{d x}}{v^{2}} + \frac{1}{x} v^{- 1} = x {(v^{- 1})}^{2}$ by $- v^{2}$ .

$- \frac{\frac{d v}{d x}}{v^{2}} (- v^{2}) + \frac{1}{x} v^{- 1} (- v^{2}) = x {(v^{- 1})}^{2} (- v^{2})$

Step 6.1.1.2

Simplify the left side.

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Step 6.1.1.2.1

Simplify each term.

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Step 6.1.1.2.1.1

Cancel the common factor of $v^{2}$ .

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Step 6.1.1.2.1.1.1

Move the leading negative in $- \frac{\frac{d v}{d x}}{v^{2}}$ into the numerator.

$\frac{- \frac{d v}{d x}}{v^{2}} (- v^{2}) + \frac{1}{x} v^{- 1} (- v^{2}) = x {(v^{- 1})}^{2} (- v^{2})$

Step 6.1.1.2.1.1.2

Factor $v^{2}$ out of $- v^{2}$ .

$\frac{- \frac{d v}{d x}}{v^{2}} (v^{2} \cdot - 1) + \frac{1}{x} v^{- 1} (- v^{2}) = x {(v^{- 1})}^{2} (- v^{2})$

Step 6.1.1.2.1.1.3

Cancel the common factor.

$\frac{- \frac{d v}{d x}}{v^{2}} (v^{2} \cdot - 1) + \frac{1}{x} v^{- 1} (- v^{2}) = x {(v^{- 1})}^{2} (- v^{2})$

Step 6.1.1.2.1.1.4

Rewrite the expression.

$- \frac{d v}{d x} \cdot - 1 + \frac{1}{x} v^{- 1} (- v^{2}) = x {(v^{- 1})}^{2} (- v^{2})$

Step 6.1.1.2.1.2

Multiply $- 1$ by $- 1$ .

$1 \frac{d v}{d x} + \frac{1}{x} v^{- 1} (- v^{2}) = x {(v^{- 1})}^{2} (- v^{2})$

Step 6.1.1.2.1.3

Multiply $\frac{d v}{d x}$ by $1$ .

$\frac{d v}{d x} + \frac{1}{x} v^{- 1} (- v^{2}) = x {(v^{- 1})}^{2} (- v^{2})$

Step 6.1.1.2.1.4

Rewrite using the commutative property of multiplication.

$\frac{d v}{d x} - \frac{1}{x} v^{- 1} v^{2} = x {(v^{- 1})}^{2} (- v^{2})$

Step 6.1.1.2.1.5

Multiply $v^{- 1}$ by $v^{2}$ by adding the exponents.

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Step 6.1.1.2.1.5.1

Move $v^{2}$ .

$\frac{d v}{d x} - \frac{1}{x} (v^{2} v^{- 1}) = x {(v^{- 1})}^{2} (- v^{2})$

Step 6.1.1.2.1.5.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{d v}{d x} - \frac{1}{x} v^{2 - 1} = x {(v^{- 1})}^{2} (- v^{2})$

Step 6.1.1.2.1.5.3

Subtract $1$ from $2$ .

$\frac{d v}{d x} - \frac{1}{x} v^{1} = x {(v^{- 1})}^{2} (- v^{2})$

Step 6.1.1.2.1.6

Simplify $- \frac{1}{x} v^{1}$ .

$\frac{d v}{d x} - \frac{1}{x} v = x {(v^{- 1})}^{2} (- v^{2})$

Step 6.1.1.2.1.7

Combine $v$ and $\frac{1}{x}$ .

$\frac{d v}{d x} - \frac{v}{x} = x {(v^{- 1})}^{2} (- v^{2})$

Step 6.1.1.3

Simplify the right side.

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Step 6.1.1.3.1

Rewrite using the commutative property of multiplication.

$\frac{d v}{d x} - \frac{v}{x} = - x {(v^{- 1})}^{2} v^{2}$

Step 6.1.1.3.2

Multiply the exponents in ${(v^{- 1})}^{2}$ .

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Step 6.1.1.3.2.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{d v}{d x} - \frac{v}{x} = - x v^{- 1 \cdot 2} v^{2}$

Step 6.1.1.3.2.2

Multiply $- 1$ by $2$ .

$\frac{d v}{d x} - \frac{v}{x} = - x v^{- 2} v^{2}$

Step 6.1.1.3.3

Multiply $v^{- 2}$ by $v^{2}$ by adding the exponents.

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Step 6.1.1.3.3.1

Move $v^{2}$ .

$\frac{d v}{d x} - \frac{v}{x} = - x (v^{2} v^{- 2})$

Step 6.1.1.3.3.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{d v}{d x} - \frac{v}{x} = - x v^{2 - 2}$

Step 6.1.1.3.3.3

Subtract $2$ from $2$ .

$\frac{d v}{d x} - \frac{v}{x} = - x v^{0}$

Step 6.1.1.3.4

Simplify $- x v^{0}$ .

$\frac{d v}{d x} - \frac{v}{x} = - x$

Step 6.1.2

Factor $v$ out of $- \frac{v}{x}$ .

$\frac{d v}{d x} + v (- \frac{1}{x}) = - x$

Step 6.1.3

Reorder $v$ and $- \frac{1}{x}$ .

$\frac{d v}{d x} - \frac{1}{x} v = - x$

Step 6.2

The integrating factor is defined by the formula $e^{\int P (x) d x}$ , where $P (x) = - \frac{1}{x}$ .

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Step 6.2.1

Set up the integration.

$e^{\int - \frac{1}{x} d x}$

Step 6.2.2

Integrate $- \frac{1}{x}$ .

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Step 6.2.2.1

Since $- 1$ is constant with respect to $x$ , move $- 1$ out of the integral.

$e^{- \int \frac{1}{x} d x}$

Step 6.2.2.2

The integral of $\frac{1}{x}$ with respect to $x$ is $\ln (| x |)$ .

$e^{- (\ln (| x |) + C)}$

Step 6.2.2.3

Simplify.

$e^{- \ln (| x |) + C}$

Step 6.2.3

Remove the constant of integration.

$e^{- \ln (x)}$

Step 6.2.4

Use the logarithmic power rule.

$e^{\ln (x^{- 1})}$

Step 6.2.5

Exponentiation and log are inverse functions.

$x^{- 1}$

Step 6.2.6

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{x}$

Step 6.3

Multiply each term by the integrating factor $\frac{1}{x}$ .

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Step 6.3.1

Multiply each term by $\frac{1}{x}$ .

$\frac{1}{x} \frac{d v}{d x} + \frac{1}{x} (- \frac{1}{x} v) = \frac{1}{x} (- x)$

Step 6.3.2

Simplify each term.

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Step 6.3.2.1

Combine $\frac{1}{x}$ and $\frac{d v}{d x}$ .

$\frac{\frac{d v}{d x}}{x} + \frac{1}{x} (- \frac{1}{x} v) = \frac{1}{x} (- x)$

Step 6.3.2.2

Rewrite using the commutative property of multiplication.

$\frac{\frac{d v}{d x}}{x} - \frac{1}{x} (\frac{1}{x} v) = \frac{1}{x} (- x)$

Step 6.3.2.3

Combine $\frac{1}{x}$ and $v$ .

$\frac{\frac{d v}{d x}}{x} - \frac{1}{x} \cdot \frac{v}{x} = \frac{1}{x} (- x)$

Step 6.3.2.4

Multiply $- \frac{1}{x} \cdot \frac{v}{x}$ .

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Step 6.3.2.4.1

Multiply $\frac{v}{x}$ by $\frac{1}{x}$ .

$\frac{\frac{d v}{d x}}{x} - \frac{v}{x \cdot x} = \frac{1}{x} (- x)$

Step 6.3.2.4.2

Raise $x$ to the power of $1$ .

$\frac{\frac{d v}{d x}}{x} - \frac{v}{x^{1} x} = \frac{1}{x} (- x)$

Step 6.3.2.4.3

Raise $x$ to the power of $1$ .

$\frac{\frac{d v}{d x}}{x} - \frac{v}{x^{1} x^{1}} = \frac{1}{x} (- x)$

Step 6.3.2.4.4

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{\frac{d v}{d x}}{x} - \frac{v}{x^{1 + 1}} = \frac{1}{x} (- x)$

Step 6.3.2.4.5

Add $1$ and $1$ .

$\frac{\frac{d v}{d x}}{x} - \frac{v}{x^{2}} = \frac{1}{x} (- x)$

Step 6.3.3

Rewrite using the commutative property of multiplication.

$\frac{\frac{d v}{d x}}{x} - \frac{v}{x^{2}} = - \frac{1}{x} x$

Step 6.3.4

Cancel the common factor of $x$ .

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Step 6.3.4.1

Move the leading negative in $- \frac{1}{x}$ into the numerator.

$\frac{\frac{d v}{d x}}{x} - \frac{v}{x^{2}} = \frac{- 1}{x} x$

Step 6.3.4.2

Cancel the common factor.

$\frac{\frac{d v}{d x}}{x} - \frac{v}{x^{2}} = \frac{- 1}{x} x$

Step 6.3.4.3

Rewrite the expression.

$\frac{\frac{d v}{d x}}{x} - \frac{v}{x^{2}} = - 1$

Step 6.4

Rewrite the left side as a result of differentiating a product.

$\frac{d}{d x} [\frac{1}{x} v] = - 1$

Step 6.5

Set up an integral on each side.

$\int \frac{d}{d x} [\frac{1}{x} v] d x = \int - 1 d x$

Step 6.6

Integrate the left side.

$\frac{1}{x} v = \int - 1 d x$

Step 6.7

Apply the constant rule.

$\frac{1}{x} v = - x + C$

Step 6.8

Solve for $v$ .

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Step 6.8.1

Combine $\frac{1}{x}$ and $v$ .

$\frac{v}{x} = - x + C$

Step 6.8.2

Multiply both sides by $x$ .

$\frac{v}{x} x = (- x + C) x$

Step 6.8.3

Simplify.

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Step 6.8.3.1

Simplify the left side.

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Step 6.8.3.1.1

Cancel the common factor of $x$ .

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Step 6.8.3.1.1.1

Cancel the common factor.

$\frac{v}{x} x = (- x + C) x$

Step 6.8.3.1.1.2

Rewrite the expression.

$v = (- x + C) x$

Step 6.8.3.2

Simplify the right side.

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Step 6.8.3.2.1

Simplify $(- x + C) x$ .

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Step 6.8.3.2.1.1

Apply the distributive property.

$v = - x \cdot x + C x$

Step 6.8.3.2.1.2

Multiply $x$ by $x$ by adding the exponents.

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Step 6.8.3.2.1.2.1

Move $x$ .

$v = - (x \cdot x) + C x$

Step 6.8.3.2.1.2.2

Multiply $x$ by $x$ .

$v = - x^{2} + C x$

Step 6.8.3.2.1.3

Reorder $- x^{2}$ and $C x$ .

$v = C x - x^{2}$

Step 7

Substitute $y^{- 1}$ for $v$ .

$y^{- 1} = C x - x^{2}$