Calculus Examples

$(2 + 2 x^{2} y^{\frac{1}{2}}) y d x + (x^{2} y^{\frac{1}{2}} + 2) x d y = 0$

Step 1

Find $\frac{\partial M}{\partial y}$ where $M (x, y) = (2 + 2 x^{2} y^{\frac{1}{2}}) y$ .

Tap for more steps...

Step 1.1

Differentiate $M$ with respect to $y$ .

$\frac{\partial M}{\partial y} = \frac{d}{d y} [(2 + 2 x^{2} y^{\frac{1}{2}}) y]$

Step 1.2

Differentiate using the Product Rule which states that $\frac{d}{d y} [f (y) g (y)]$ is $f (y) \frac{d}{d y} [g (y)] + g (y) \frac{d}{d y} [f (y)]$ where $f (y) = 2 + 2 x^{2} y^{\frac{1}{2}}$ and $g (y) = y$ .

$\frac{\partial M}{\partial y} = (2 + 2 x^{2} y^{\frac{1}{2}}) \frac{d}{d y} [y] + y \frac{d}{d y} [2 + 2 x^{2} y^{\frac{1}{2}}]$

Step 1.3

Differentiate.

Tap for more steps...

Step 1.3.1

Differentiate using the Power Rule which states that $\frac{d}{d y} [y^{n}]$ is $n y^{n - 1}$ where $n = 1$ .

$\frac{\partial M}{\partial y} = (2 + 2 x^{2} y^{\frac{1}{2}}) \cdot 1 + y \frac{d}{d y} [2 + 2 x^{2} y^{\frac{1}{2}}]$

Step 1.3.2

Multiply $2 + 2 x^{2} y^{\frac{1}{2}}$ by $1$ .

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + y \frac{d}{d y} [2 + 2 x^{2} y^{\frac{1}{2}}]$

Step 1.3.3

By the Sum Rule, the derivative of $2 + 2 x^{2} y^{\frac{1}{2}}$ with respect to $y$ is $\frac{d}{d y} [2] + \frac{d}{d y} [2 x^{2} y^{\frac{1}{2}}]$ .

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + y (\frac{d}{d y} [2] + \frac{d}{d y} [2 x^{2} y^{\frac{1}{2}}])$

Step 1.3.4

Since $2$ is constant with respect to $y$ , the derivative of $2$ with respect to $y$ is $0$ .

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + y (0 + \frac{d}{d y} [2 x^{2} y^{\frac{1}{2}}])$

Step 1.3.5

Add $0$ and $\frac{d}{d y} [2 x^{2} y^{\frac{1}{2}}]$ .

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + y \frac{d}{d y} [2 x^{2} y^{\frac{1}{2}}]$

Step 1.3.6

Since $2 x^{2}$ is constant with respect to $y$ , the derivative of $2 x^{2} y^{\frac{1}{2}}$ with respect to $y$ is $2 x^{2} \frac{d}{d y} [y^{\frac{1}{2}}]$ .

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + y (2 x^{2} \frac{d}{d y} [y^{\frac{1}{2}}])$

Step 1.3.7

Differentiate using the Power Rule which states that $\frac{d}{d y} [y^{n}]$ is $n y^{n - 1}$ where $n = \frac{1}{2}$ .

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + y (2 x^{2} (\frac{1}{2} y^{\frac{1}{2} - 1}))$

Step 1.4

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + y (2 x^{2} (\frac{1}{2} y^{\frac{1}{2} - 1 \cdot \frac{2}{2}}))$

Step 1.5

Combine $- 1$ and $\frac{2}{2}$ .

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + y (2 x^{2} (\frac{1}{2} y^{\frac{1}{2} + \frac{- 1 \cdot 2}{2}}))$

Step 1.6

Combine the numerators over the common denominator.

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + y (2 x^{2} (\frac{1}{2} y^{\frac{1 - 1 \cdot 2}{2}}))$

Step 1.7

Simplify the numerator.

Tap for more steps...

Step 1.7.1

Multiply $- 1$ by $2$ .

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + y (2 x^{2} (\frac{1}{2} y^{\frac{1 - 2}{2}}))$

Step 1.7.2

Subtract $2$ from $1$ .

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + y (2 x^{2} (\frac{1}{2} y^{\frac{- 1}{2}}))$

Step 1.8

Move the negative in front of the fraction.

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + y (2 x^{2} (\frac{1}{2} y^{- \frac{1}{2}}))$

Step 1.9

Combine $\frac{1}{2}$ and $y^{- \frac{1}{2}}$ .

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + y (2 x^{2} \frac{y^{- \frac{1}{2}}}{2})$

Step 1.10

Combine $2$ and $\frac{y^{- \frac{1}{2}}}{2}$ .

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + y (x^{2} \frac{2 y^{- \frac{1}{2}}}{2})$

Step 1.11

Combine $x^{2}$ and $\frac{2 y^{- \frac{1}{2}}}{2}$ .

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + y \frac{x^{2} (2 y^{- \frac{1}{2}})}{2}$

Step 1.12

Simplify the expression.

Tap for more steps...

Step 1.12.1

Move $2$ to the left of $x^{2}$ .

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + y \frac{2 \cdot x^{2} y^{- \frac{1}{2}}}{2}$

Step 1.12.2

Move $y^{- \frac{1}{2}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + y \frac{2 x^{2}}{2 y^{\frac{1}{2}}}$

Step 1.13

Cancel the common factor.

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + y \frac{2 x^{2}}{2 y^{\frac{1}{2}}}$

Step 1.14

Rewrite the expression.

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + y \frac{x^{2}}{y^{\frac{1}{2}}}$

Step 1.15

Combine $y$ and $\frac{x^{2}}{y^{\frac{1}{2}}}$ .

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + \frac{y x^{2}}{y^{\frac{1}{2}}}$

Step 1.16

Move $y^{\frac{1}{2}}$ to the numerator using the negative exponent rule $\frac{1}{b^{n}} = b^{- n}$ .

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + y x^{2} y^{- \frac{1}{2}}$

Step 1.17

Multiply $y$ by $y^{- \frac{1}{2}}$ by adding the exponents.

Tap for more steps...

Step 1.17.1

Move $y^{- \frac{1}{2}}$ .

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + y^{- \frac{1}{2}} y x^{2}$

Step 1.17.2

Multiply $y^{- \frac{1}{2}}$ by $y$ .

Tap for more steps...

Step 1.17.2.1

Raise $y$ to the power of $1$ .

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + y^{- \frac{1}{2}} y^{1} x^{2}$

Step 1.17.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + y^{- \frac{1}{2} + 1} x^{2}$

Step 1.17.3

Write $1$ as a fraction with a common denominator.

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + y^{- \frac{1}{2} + \frac{2}{2}} x^{2}$

Step 1.17.4

Combine the numerators over the common denominator.

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + y^{\frac{- 1 + 2}{2}} x^{2}$

Step 1.17.5

Add $- 1$ and $2$ .

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + y^{\frac{1}{2}} x^{2}$

Step 1.18

Add $2 x^{2} y^{\frac{1}{2}}$ and $y^{\frac{1}{2}} x^{2}$ .

Tap for more steps...

Step 1.18.1

Reorder $y^{\frac{1}{2}}$ and $x^{2}$ .

$\frac{\partial M}{\partial y} = 2 + 2 x^{2} y^{\frac{1}{2}} + x^{2} y^{\frac{1}{2}}$

Step 1.18.2

Add $2 x^{2} y^{\frac{1}{2}}$ and $x^{2} y^{\frac{1}{2}}$ .

$\frac{\partial M}{\partial y} = 2 + 3 x^{2} y^{\frac{1}{2}}$

Step 1.19

Simplify.

Tap for more steps...

Step 1.19.1

Reorder terms.

$\frac{\partial M}{\partial y} = 3 y^{\frac{1}{2}} x^{2} + 2$

Step 1.19.2

Reorder factors in $3 y^{\frac{1}{2}} x^{2} + 2$ .

$\frac{\partial M}{\partial y} = 3 x^{2} y^{\frac{1}{2}} + 2$

Step 2

Find $\frac{\partial N}{\partial x}$ where $N (x, y) = (x^{2} y^{\frac{1}{2}} + 2) x$ .

Tap for more steps...

Step 2.1

Differentiate $N$ with respect to $x$ .

$\frac{\partial N}{\partial x} = \frac{d}{d x} [(x^{2} y^{\frac{1}{2}} + 2) x]$

Step 2.2

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x^{2} y^{\frac{1}{2}} + 2$ and $g (x) = x$ .

$\frac{\partial N}{\partial x} = (x^{2} y^{\frac{1}{2}} + 2) \frac{d}{d x} [x] + x \frac{d}{d x} [x^{2} y^{\frac{1}{2}} + 2]$

Step 2.3

Differentiate.

Tap for more steps...

Step 2.3.1

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{\partial N}{\partial x} = (x^{2} y^{\frac{1}{2}} + 2) \cdot 1 + x \frac{d}{d x} [x^{2} y^{\frac{1}{2}} + 2]$

Step 2.3.2

Multiply $x^{2} y^{\frac{1}{2}} + 2$ by $1$ .

$\frac{\partial N}{\partial x} = x^{2} y^{\frac{1}{2}} + 2 + x \frac{d}{d x} [x^{2} y^{\frac{1}{2}} + 2]$

Step 2.3.3

By the Sum Rule, the derivative of $x^{2} y^{\frac{1}{2}} + 2$ with respect to $x$ is $\frac{d}{d x} [x^{2} y^{\frac{1}{2}}] + \frac{d}{d x} [2]$ .

$\frac{\partial N}{\partial x} = x^{2} y^{\frac{1}{2}} + 2 + x (\frac{d}{d x} [x^{2} y^{\frac{1}{2}}] + \frac{d}{d x} [2])$

Step 2.3.4

Since $y^{\frac{1}{2}}$ is constant with respect to $x$ , the derivative of $x^{2} y^{\frac{1}{2}}$ with respect to $x$ is $y^{\frac{1}{2}} \frac{d}{d x} [x^{2}]$ .

$\frac{\partial N}{\partial x} = x^{2} y^{\frac{1}{2}} + 2 + x (y^{\frac{1}{2}} \frac{d}{d x} [x^{2}] + \frac{d}{d x} [2])$

Step 2.3.5

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$\frac{\partial N}{\partial x} = x^{2} y^{\frac{1}{2}} + 2 + x (y^{\frac{1}{2}} (2 x) + \frac{d}{d x} [2])$

Step 2.3.6

Move $2$ to the left of $y^{\frac{1}{2}}$ .

$\frac{\partial N}{\partial x} = x^{2} y^{\frac{1}{2}} + 2 + x (2 \cdot y^{\frac{1}{2}} x + \frac{d}{d x} [2])$

Step 2.3.7

Since $2$ is constant with respect to $x$ , the derivative of $2$ with respect to $x$ is $0$ .

$\frac{\partial N}{\partial x} = x^{2} y^{\frac{1}{2}} + 2 + x (2 y^{\frac{1}{2}} x + 0)$

Step 2.3.8

Add $2 y^{\frac{1}{2}} x$ and $0$ .

$\frac{\partial N}{\partial x} = x^{2} y^{\frac{1}{2}} + 2 + x (2 y^{\frac{1}{2}} x)$

Step 2.4

Raise $x$ to the power of $1$ .

$\frac{\partial N}{\partial x} = x^{2} y^{\frac{1}{2}} + 2 + x^{1} x (2 y^{\frac{1}{2}})$

Step 2.5

Raise $x$ to the power of $1$ .

$\frac{\partial N}{\partial x} = x^{2} y^{\frac{1}{2}} + 2 + x^{1} x^{1} (2 y^{\frac{1}{2}})$

Step 2.6

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{\partial N}{\partial x} = x^{2} y^{\frac{1}{2}} + 2 + x^{1 + 1} (2 y^{\frac{1}{2}})$

Step 2.7

Simplify the expression.

Tap for more steps...

Step 2.7.1

Add $1$ and $1$ .

$\frac{\partial N}{\partial x} = x^{2} y^{\frac{1}{2}} + 2 + x^{2} (2 y^{\frac{1}{2}})$

Step 2.7.2

Move $2$ to the left of $x^{2}$ .

$\frac{\partial N}{\partial x} = x^{2} y^{\frac{1}{2}} + 2 + 2 \cdot x^{2} y^{\frac{1}{2}}$

Step 2.8

Add $x^{2} y^{\frac{1}{2}}$ and $2 x^{2} y^{\frac{1}{2}}$ .

$\frac{\partial N}{\partial x} = 3 x^{2} y^{\frac{1}{2}} + 2$

Step 3

Check that $\frac{\partial M}{\partial y} = \frac{\partial N}{\partial x}$ .

Tap for more steps...

Step 3.1

Substitute $3 x^{2} y^{\frac{1}{2}} + 2$ for $\frac{\partial M}{\partial y}$ and $3 x^{2} y^{\frac{1}{2}} + 2$ for $\frac{\partial N}{\partial x}$ .

$3 x^{2} y^{\frac{1}{2}} + 2 = 3 x^{2} y^{\frac{1}{2}} + 2$

Step 3.2

Since the two sides have been shown to be equivalent, the equation is an identity.

$3 x^{2} y^{\frac{1}{2}} + 2 = 3 x^{2} y^{\frac{1}{2}} + 2$ is an identity.

Step 4

Set $f (x, y)$ equal to the integral of $M (x, y)$ .

$f (x, y) = \int (2 + 2 x^{2} y^{\frac{1}{2}}) y d x$

Step 5

Integrate $M (x, y) = (2 + 2 x^{2} y^{\frac{1}{2}}) y$ to find $f (x, y)$ .

Tap for more steps...

Step 5.1

Since $y$ is constant with respect to $x$ , move $y$ out of the integral.

$f (x, y) = y \int 2 + 2 x^{2} y^{\frac{1}{2}} d x$

Step 5.2

Split the single integral into multiple integrals.

$f (x, y) = y (\int 2 d x + \int 2 x^{2} y^{\frac{1}{2}} d x)$

Step 5.3

Apply the constant rule.

$f (x, y) = y (2 x + C + \int 2 x^{2} y^{\frac{1}{2}} d x)$

Step 5.4

Since $2 y^{\frac{1}{2}}$ is constant with respect to $x$ , move $2 y^{\frac{1}{2}}$ out of the integral.

$f (x, y) = y (2 x + C + 2 y^{\frac{1}{2}} \int x^{2} d x)$

Step 5.5

By the Power Rule, the integral of $x^{2}$ with respect to $x$ is $\frac{1}{3} x^{3}$ .

$f (x, y) = y (2 x + C + 2 y^{\frac{1}{2}} (\frac{1}{3} x^{3} + C))$

Step 5.6

Simplify.

$f (x, y) = y (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) + C$

Step 5.7

Reorder terms.

$f (x, y) = y (2 x + \frac{2}{3} y^{\frac{1}{2}} x^{3}) + C$

Step 6

Since the integral of $g (y)$ will contain an integration constant, we can replace $C$ with $g (y)$ .

$f (x, y) = y (2 x + \frac{2}{3} y^{\frac{1}{2}} x^{3}) + g (y)$

Step 7

Set $\frac{\partial f}{\partial y} = N (x, y)$ .

$\frac{\partial f}{\partial y} = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8

Find $\frac{\partial f}{\partial y}$ .

Tap for more steps...

Step 8.1

Differentiate $f$ with respect to $y$ .

$\frac{d}{d y} [y (2 x + \frac{2}{3} y^{\frac{1}{2}} x^{3}) + g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.2

By the Sum Rule, the derivative of $y (2 x + \frac{2}{3} y^{\frac{1}{2}} x^{3}) + g (y)$ with respect to $y$ is $\frac{d}{d y} [y (2 x + \frac{2}{3} y^{\frac{1}{2}} x^{3})] + \frac{d}{d y} [g (y)]$ .

$\frac{d}{d y} [y (2 x + \frac{2}{3} y^{\frac{1}{2}} x^{3})] + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3

Evaluate $\frac{d}{d y} [y (2 x + \frac{2}{3} y^{\frac{1}{2}} x^{3})]$ .

Tap for more steps...

Step 8.3.1

Combine $\frac{2}{3}$ and $y^{\frac{1}{2}}$ .

$\frac{d}{d y} [y (2 x + \frac{2 y^{\frac{1}{2}}}{3} x^{3})] + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.2

Combine $\frac{2 y^{\frac{1}{2}}}{3}$ and $x^{3}$ .

$\frac{d}{d y} [y (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3})] + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.3

Differentiate using the Product Rule which states that $\frac{d}{d y} [f (y) g (y)]$ is $f (y) \frac{d}{d y} [g (y)] + g (y) \frac{d}{d y} [f (y)]$ where $f (y) = y$ and $g (y) = 2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}$ .

$y \frac{d}{d y} [2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}] + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \frac{d}{d y} [y] + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.4

By the Sum Rule, the derivative of $2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}$ with respect to $y$ is $\frac{d}{d y} [2 x] + \frac{d}{d y} [\frac{2 y^{\frac{1}{2}} x^{3}}{3}]$ .

$y (\frac{d}{d y} [2 x] + \frac{d}{d y} [\frac{2 y^{\frac{1}{2}} x^{3}}{3}]) + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \frac{d}{d y} [y] + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.5

Since $2 x$ is constant with respect to $y$ , the derivative of $2 x$ with respect to $y$ is $0$ .

$y (0 + \frac{d}{d y} [\frac{2 y^{\frac{1}{2}} x^{3}}{3}]) + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \frac{d}{d y} [y] + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.6

Since $\frac{2 x^{3}}{3}$ is constant with respect to $y$ , the derivative of $\frac{2 y^{\frac{1}{2}} x^{3}}{3}$ with respect to $y$ is $\frac{2 x^{3}}{3} \frac{d}{d y} [y^{\frac{1}{2}}]$ .

$y (0 + \frac{2 x^{3}}{3} \frac{d}{d y} [y^{\frac{1}{2}}]) + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \frac{d}{d y} [y] + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.7

Differentiate using the Power Rule which states that $\frac{d}{d y} [y^{n}]$ is $n y^{n - 1}$ where $n = \frac{1}{2}$ .

$y (0 + \frac{2 x^{3}}{3} (\frac{1}{2} y^{\frac{1}{2} - 1})) + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \frac{d}{d y} [y] + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.8

Differentiate using the Power Rule which states that $\frac{d}{d y} [y^{n}]$ is $n y^{n - 1}$ where $n = 1$ .

$y (0 + \frac{2 x^{3}}{3} (\frac{1}{2} y^{\frac{1}{2} - 1})) + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \cdot 1 + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.9

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$y (0 + \frac{2 x^{3}}{3} (\frac{1}{2} y^{\frac{1}{2} - 1 \cdot \frac{2}{2}})) + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \cdot 1 + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.10

Combine $- 1$ and $\frac{2}{2}$ .

$y (0 + \frac{2 x^{3}}{3} (\frac{1}{2} y^{\frac{1}{2} + \frac{- 1 \cdot 2}{2}})) + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \cdot 1 + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.11

Combine the numerators over the common denominator.

$y (0 + \frac{2 x^{3}}{3} (\frac{1}{2} y^{\frac{1 - 1 \cdot 2}{2}})) + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \cdot 1 + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.12

Simplify the numerator.

Tap for more steps...

Step 8.3.12.1

Multiply $- 1$ by $2$ .

$y (0 + \frac{2 x^{3}}{3} (\frac{1}{2} y^{\frac{1 - 2}{2}})) + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \cdot 1 + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.12.2

Subtract $2$ from $1$ .

$y (0 + \frac{2 x^{3}}{3} (\frac{1}{2} y^{\frac{- 1}{2}})) + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \cdot 1 + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.13

Move the negative in front of the fraction.

$y (0 + \frac{2 x^{3}}{3} (\frac{1}{2} y^{- \frac{1}{2}})) + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \cdot 1 + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.14

Combine $\frac{1}{2}$ and $y^{- \frac{1}{2}}$ .

$y (0 + \frac{2 x^{3}}{3} \cdot \frac{y^{- \frac{1}{2}}}{2}) + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \cdot 1 + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.15

Multiply $\frac{2 x^{3}}{3}$ by $\frac{y^{- \frac{1}{2}}}{2}$ .

$y (0 + \frac{2 x^{3} y^{- \frac{1}{2}}}{3 \cdot 2}) + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \cdot 1 + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.16

Multiply $3$ by $2$ .

$y (0 + \frac{2 x^{3} y^{- \frac{1}{2}}}{6}) + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \cdot 1 + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.17

Move $y^{- \frac{1}{2}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$y (0 + \frac{2 x^{3}}{6 y^{\frac{1}{2}}}) + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \cdot 1 + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.18

Factor $2$ out of $2 x^{3}$ .

$y (0 + \frac{2 (x^{3})}{6 y^{\frac{1}{2}}}) + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \cdot 1 + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.19

Cancel the common factors.

Tap for more steps...

Step 8.3.19.1

Factor $2$ out of $6 y^{\frac{1}{2}}$ .

$y (0 + \frac{2 (x^{3})}{2 (3 y^{\frac{1}{2}})}) + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \cdot 1 + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.19.2

Cancel the common factor.

$y (0 + \frac{2 x^{3}}{2 (3 y^{\frac{1}{2}})}) + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \cdot 1 + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.19.3

Rewrite the expression.

$y (0 + \frac{x^{3}}{3 y^{\frac{1}{2}}}) + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \cdot 1 + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.20

Add $0$ and $\frac{x^{3}}{3 y^{\frac{1}{2}}}$ .

$y \frac{x^{3}}{3 y^{\frac{1}{2}}} + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \cdot 1 + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.21

Combine $y$ and $\frac{x^{3}}{3 y^{\frac{1}{2}}}$ .

$\frac{y x^{3}}{3 y^{\frac{1}{2}}} + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \cdot 1 + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.22

Move $y^{\frac{1}{2}}$ to the numerator using the negative exponent rule $\frac{1}{b^{n}} = b^{- n}$ .

$\frac{y x^{3} y^{- \frac{1}{2}}}{3} + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \cdot 1 + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.23

Multiply $y$ by $y^{- \frac{1}{2}}$ by adding the exponents.

Tap for more steps...

Step 8.3.23.1

Move $y^{- \frac{1}{2}}$ .

$\frac{y^{- \frac{1}{2}} y x^{3}}{3} + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \cdot 1 + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.23.2

Multiply $y^{- \frac{1}{2}}$ by $y$ .

Tap for more steps...

Step 8.3.23.2.1

Raise $y$ to the power of $1$ .

$\frac{y^{- \frac{1}{2}} y^{1} x^{3}}{3} + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \cdot 1 + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.23.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{y^{- \frac{1}{2} + 1} x^{3}}{3} + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \cdot 1 + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.23.3

Write $1$ as a fraction with a common denominator.

$\frac{y^{- \frac{1}{2} + \frac{2}{2}} x^{3}}{3} + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \cdot 1 + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.23.4

Combine the numerators over the common denominator.

$\frac{y^{\frac{- 1 + 2}{2}} x^{3}}{3} + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \cdot 1 + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.23.5

Add $- 1$ and $2$ .

$\frac{y^{\frac{1}{2}} x^{3}}{3} + (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) \cdot 1 + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.24

Multiply $2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}$ by $1$ .

$\frac{y^{\frac{1}{2}} x^{3}}{3} + 2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3} + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.25

Combine the numerators over the common denominator.

$2 x + \frac{y^{\frac{1}{2}} x^{3} + 2 y^{\frac{1}{2}} x^{3}}{3} + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.26

Add $y^{\frac{1}{2}} x^{3}$ and $2 y^{\frac{1}{2}} x^{3}$ .

$2 x + \frac{3 y^{\frac{1}{2}} x^{3}}{3} + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.27

Cancel the common factor.

$2 x + \frac{3 y^{\frac{1}{2}} x^{3}}{3} + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.3.28

Divide $y^{\frac{1}{2}} x^{3}$ by $1$ .

$2 x + y^{\frac{1}{2}} x^{3} + \frac{d}{d y} [g (y)] = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.4

Differentiate using the function rule which states that the derivative of $g (y)$ is $\frac{d g}{d y}$ .

$2 x + y^{\frac{1}{2}} x^{3} + \frac{d g}{d y} = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.5

Simplify.

Tap for more steps...

Step 8.5.1

Reorder terms.

$\frac{d g}{d y} + y^{\frac{1}{2}} x^{3} + 2 x = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 8.5.2

Reorder factors in $\frac{d g}{d y} + y^{\frac{1}{2}} x^{3} + 2 x$ .

$\frac{d g}{d y} + x^{3} y^{\frac{1}{2}} + 2 x = (x^{2} y^{\frac{1}{2}} + 2) x$

Step 9

Solve for $\frac{d g}{d y}$ .

Tap for more steps...

Step 9.1

Simplify $\frac{d g}{d y} + x^{3} y^{\frac{1}{2}} + 2 x - (x^{2} y^{\frac{1}{2}} + 2) x$ .

Tap for more steps...

Step 9.1.1

Simplify each term.

Tap for more steps...

Step 9.1.1.1

Apply the distributive property.

$\frac{d g}{d y} + x^{3} y^{\frac{1}{2}} + 2 x + (- (x^{2} y^{\frac{1}{2}}) - 1 \cdot 2) x = 0$

Step 9.1.1.2

Multiply $- 1$ by $2$ .

$\frac{d g}{d y} + x^{3} y^{\frac{1}{2}} + 2 x + (- x^{2} y^{\frac{1}{2}} - 2) x = 0$

Step 9.1.1.3

Apply the distributive property.

$\frac{d g}{d y} + x^{3} y^{\frac{1}{2}} + 2 x - x^{2} y^{\frac{1}{2}} x - 2 x = 0$

Step 9.1.1.4

Multiply $x^{2}$ by $x$ by adding the exponents.

Tap for more steps...

Step 9.1.1.4.1

Move $x$ .

$\frac{d g}{d y} + x^{3} y^{\frac{1}{2}} + 2 x - (x \cdot x^{2}) y^{\frac{1}{2}} - 2 x = 0$

Step 9.1.1.4.2

Multiply $x$ by $x^{2}$ .

Tap for more steps...

Step 9.1.1.4.2.1

Raise $x$ to the power of $1$ .

$\frac{d g}{d y} + x^{3} y^{\frac{1}{2}} + 2 x - (x^{1} x^{2}) y^{\frac{1}{2}} - 2 x = 0$

Step 9.1.1.4.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{d g}{d y} + x^{3} y^{\frac{1}{2}} + 2 x - x^{1 + 2} y^{\frac{1}{2}} - 2 x = 0$

Step 9.1.1.4.3

Add $1$ and $2$ .

$\frac{d g}{d y} + x^{3} y^{\frac{1}{2}} + 2 x - x^{3} y^{\frac{1}{2}} - 2 x = 0$

Step 9.1.2

Combine the opposite terms in $\frac{d g}{d y} + x^{3} y^{\frac{1}{2}} + 2 x - x^{3} y^{\frac{1}{2}} - 2 x$ .

Tap for more steps...

Step 9.1.2.1

Subtract $x^{3} y^{\frac{1}{2}}$ from $x^{3} y^{\frac{1}{2}}$ .

$\frac{d g}{d y} + 2 x + 0 - 2 x = 0$

Step 9.1.2.2

Add $\frac{d g}{d y} + 2 x$ and $0$ .

$\frac{d g}{d y} + 2 x - 2 x = 0$

Step 9.1.2.3

Subtract $2 x$ from $2 x$ .

$\frac{d g}{d y} + 0 = 0$

Step 9.1.2.4

Add $\frac{d g}{d y}$ and $0$ .

$\frac{d g}{d y} = 0$

Step 10

Find the antiderivative of $0$ to find $g (y)$ .

Tap for more steps...

Step 10.1

Integrate both sides of $\frac{d g}{d y} = 0$ .

$\int \frac{d g}{d y} d y = \int 0 d y$

Step 10.2

Evaluate $\int \frac{d g}{d y} d y$ .

$g (y) = \int 0 d y$

Step 10.3

The integral of $0$ with respect to $y$ is $0$ .

$g (y) = 0 + C$

Step 10.4

Add $0$ and $C$ .

$g (y) = C$

Step 11

Substitute for $g (y)$ in $f (x, y) = y (2 x + \frac{2}{3} y^{\frac{1}{2}} x^{3}) + g (y)$ .

$f (x, y) = y (2 x + \frac{2}{3} y^{\frac{1}{2}} x^{3}) + C$

Step 12

Simplify $f (x, y) = y (2 x + \frac{2}{3} y^{\frac{1}{2}} x^{3}) + C$ .

Tap for more steps...

Step 12.1

Simplify each term.

Tap for more steps...

Step 12.1.1

Simplify each term.

Tap for more steps...

Step 12.1.1.1

Combine $\frac{2}{3}$ and $y^{\frac{1}{2}}$ .

$f (x, y) = y (2 x + \frac{2 y^{\frac{1}{2}}}{3} x^{3}) + C$

Step 12.1.1.2

Combine $\frac{2 y^{\frac{1}{2}}}{3}$ and $x^{3}$ .

$f (x, y) = y (2 x + \frac{2 y^{\frac{1}{2}} x^{3}}{3}) + C$

Step 12.1.2

Apply the distributive property.

$f (x, y) = y (2 x) + y \frac{2 y^{\frac{1}{2}} x^{3}}{3} + C$

Step 12.1.3

Rewrite using the commutative property of multiplication.

$f (x, y) = 2 y x + y \frac{2 y^{\frac{1}{2}} x^{3}}{3} + C$

Step 12.1.4

Multiply $y \frac{2 y^{\frac{1}{2}} x^{3}}{3}$ .

Tap for more steps...

Step 12.1.4.1

Combine $y$ and $\frac{2 y^{\frac{1}{2}} x^{3}}{3}$ .

$f (x, y) = 2 y x + \frac{y (2 y^{\frac{1}{2}} x^{3})}{3} + C$

Step 12.1.4.2

Raise $y$ to the power of $1$ .

$f (x, y) = 2 y x + \frac{2 (y^{1} y^{\frac{1}{2}}) x^{3}}{3} + C$

Step 12.1.4.3

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f (x, y) = 2 y x + \frac{2 y^{1 + \frac{1}{2}} x^{3}}{3} + C$

Step 12.1.4.4

Write $1$ as a fraction with a common denominator.

$f (x, y) = 2 y x + \frac{2 y^{\frac{2}{2} + \frac{1}{2}} x^{3}}{3} + C$

Step 12.1.4.5

Combine the numerators over the common denominator.

$f (x, y) = 2 y x + \frac{2 y^{\frac{2 + 1}{2}} x^{3}}{3} + C$

Step 12.1.4.6

Add $2$ and $1$ .

$f (x, y) = 2 y x + \frac{2 y^{\frac{3}{2}} x^{3}}{3} + C$

Step 12.2

Reorder factors in $f (x, y) = 2 y x + \frac{2 y^{\frac{3}{2}} x^{3}}{3} + C$ .

$f (x, y) = 2 y x + \frac{2 x^{3} y^{\frac{3}{2}}}{3} + C$