Calculus Examples

$x^{4} \frac{d y}{d x} + 2 x^{3} y = 5$

Step 1

Rewrite the differential equation as $\frac{d y}{d x} + M (x) y = Q (x)$ .

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Step 1.1

Divide each term in $x^{4} \frac{d y}{d x} + 2 x^{3} y = 5$ by $x^{4}$ .

$\frac{x^{4} \frac{d y}{d x}}{x^{4}} + \frac{2 x^{3} y}{x^{4}} = \frac{5}{x^{4}}$

Step 1.2

Cancel the common factor of $x^{4}$ .

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Step 1.2.1

Cancel the common factor.

$\frac{x^{4} \frac{d y}{d x}}{x^{4}} + \frac{2 x^{3} y}{x^{4}} = \frac{5}{x^{4}}$

Step 1.2.2

Divide $\frac{d y}{d x}$ by $1$ .

$\frac{d y}{d x} + \frac{2 x^{3} y}{x^{4}} = \frac{5}{x^{4}}$

Step 1.3

Cancel the common factor of $x^{3}$ and $x^{4}$ .

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Step 1.3.1

Factor $x^{3}$ out of $2 x^{3} y$ .

$\frac{d y}{d x} + \frac{x^{3} (2 y)}{x^{4}} = \frac{5}{x^{4}}$

Step 1.3.2

Cancel the common factors.

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Step 1.3.2.1

Factor $x^{3}$ out of $x^{4}$ .

$\frac{d y}{d x} + \frac{x^{3} (2 y)}{x^{3} x} = \frac{5}{x^{4}}$

Step 1.3.2.2

Cancel the common factor.

$\frac{d y}{d x} + \frac{x^{3} (2 y)}{x^{3} x} = \frac{5}{x^{4}}$

Step 1.3.2.3

Rewrite the expression.

$\frac{d y}{d x} + \frac{2 y}{x} = \frac{5}{x^{4}}$

Step 1.4

Factor $y$ out of $\frac{2 y}{x}$ .

$\frac{d y}{d x} + y \frac{2}{x} = \frac{5}{x^{4}}$

Step 1.5

Reorder $y$ and $\frac{2}{x}$ .

$\frac{d y}{d x} + \frac{2}{x} y = \frac{5}{x^{4}}$

Step 2

The integrating factor is defined by the formula $e^{\int P (x) d x}$ , where $P (x) = \frac{2}{x}$ .

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Step 2.1

Set up the integration.

$e^{\int \frac{2}{x} d x}$

Step 2.2

Integrate $\frac{2}{x}$ .

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Step 2.2.1

Since $2$ is constant with respect to $x$ , move $2$ out of the integral.

$e^{2 \int \frac{1}{x} d x}$

Step 2.2.2

The integral of $\frac{1}{x}$ with respect to $x$ is $\ln (| x |)$ .

$e^{2 (\ln (| x |) + C)}$

Step 2.2.3

Simplify.

$e^{2 \ln (| x |) + C}$

Step 2.3

Remove the constant of integration.

$e^{2 \ln (x)}$

Step 2.4

Use the logarithmic power rule.

$e^{\ln (x^{2})}$

Step 2.5

Exponentiation and log are inverse functions.

$x^{2}$

Step 3

Multiply each term by the integrating factor $x^{2}$ .

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Step 3.1

Multiply each term by $x^{2}$ .

$x^{2} \frac{d y}{d x} + x^{2} (\frac{2}{x} y) = x^{2} \frac{5}{x^{4}}$

Step 3.2

Simplify each term.

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Step 3.2.1

Combine $\frac{2}{x}$ and $y$ .

$x^{2} \frac{d y}{d x} + x^{2} \frac{2 y}{x} = x^{2} \frac{5}{x^{4}}$

Step 3.2.2

Cancel the common factor of $x$ .

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Step 3.2.2.1

Factor $x$ out of $x^{2}$ .

$x^{2} \frac{d y}{d x} + x \cdot x \frac{2 y}{x} = x^{2} \frac{5}{x^{4}}$

Step 3.2.2.2

Cancel the common factor.

$x^{2} \frac{d y}{d x} + x \cdot x \frac{2 y}{x} = x^{2} \frac{5}{x^{4}}$

Step 3.2.2.3

Rewrite the expression.

$x^{2} \frac{d y}{d x} + x (2 y) = x^{2} \frac{5}{x^{4}}$

Step 3.2.3

Rewrite using the commutative property of multiplication.

$x^{2} \frac{d y}{d x} + 2 x y = x^{2} \frac{5}{x^{4}}$

Step 3.3

Cancel the common factor of $x^{2}$ .

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Step 3.3.1

Factor $x^{2}$ out of $x^{4}$ .

$x^{2} \frac{d y}{d x} + 2 x y = x^{2} \frac{5}{x^{2} x^{2}}$

Step 3.3.2

Cancel the common factor.

$x^{2} \frac{d y}{d x} + 2 x y = x^{2} \frac{5}{x^{2} x^{2}}$

Step 3.3.3

Rewrite the expression.

$x^{2} \frac{d y}{d x} + 2 x y = \frac{5}{x^{2}}$

Step 4

Rewrite the left side as a result of differentiating a product.

$\frac{d}{d x} [x^{2} y] = \frac{5}{x^{2}}$

Step 5

Set up an integral on each side.

$\int \frac{d}{d x} [x^{2} y] d x = \int \frac{5}{x^{2}} d x$

Step 6

Integrate the left side.

$x^{2} y = \int \frac{5}{x^{2}} d x$

Step 7

Integrate the right side.

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Step 7.1

Since $5$ is constant with respect to $x$ , move $5$ out of the integral.

$x^{2} y = 5 \int \frac{1}{x^{2}} d x$

Step 7.2

Apply basic rules of exponents.

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Step 7.2.1

Move $x^{2}$ out of the denominator by raising it to the $- 1$ power.

$x^{2} y = 5 \int {(x^{2})}^{- 1} d x$

Step 7.2.2

Multiply the exponents in ${(x^{2})}^{- 1}$ .

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Step 7.2.2.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x^{2} y = 5 \int x^{2 \cdot - 1} d x$

Step 7.2.2.2

Multiply $2$ by $- 1$ .

$x^{2} y = 5 \int x^{- 2} d x$

Step 7.3

By the Power Rule, the integral of $x^{- 2}$ with respect to $x$ is $- x^{- 1}$ .

$x^{2} y = 5 (- x^{- 1} + C)$

Step 7.4

Simplify the answer.

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Step 7.4.1

Rewrite $5 (- x^{- 1} + C)$ as $5 (- \frac{1}{x}) + C$ .

$x^{2} y = 5 (- \frac{1}{x}) + C$

Step 7.4.2

Simplify.

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Step 7.4.2.1

Multiply $- 1$ by $5$ .

$x^{2} y = - 5 \frac{1}{x} + C$

Step 7.4.2.2

Combine $- 5$ and $\frac{1}{x}$ .

$x^{2} y = \frac{- 5}{x} + C$

Step 7.4.2.3

Move the negative in front of the fraction.

$x^{2} y = - \frac{5}{x} + C$

Step 8

Divide each term in $x^{2} y = - \frac{5}{x} + C$ by $x^{2}$ and simplify.

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Step 8.1

Divide each term in $x^{2} y = - \frac{5}{x} + C$ by $x^{2}$ .

$\frac{x^{2} y}{x^{2}} = \frac{- \frac{5}{x}}{x^{2}} + \frac{C}{x^{2}}$

Step 8.2

Simplify the left side.

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Step 8.2.1

Cancel the common factor of $x^{2}$ .

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Step 8.2.1.1

Cancel the common factor.

$\frac{x^{2} y}{x^{2}} = \frac{- \frac{5}{x}}{x^{2}} + \frac{C}{x^{2}}$

Step 8.2.1.2

Divide $y$ by $1$ .

$y = \frac{- \frac{5}{x}}{x^{2}} + \frac{C}{x^{2}}$

Step 8.3

Simplify the right side.

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Step 8.3.1

Simplify each term.

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Step 8.3.1.1

Multiply the numerator by the reciprocal of the denominator.

$y = - \frac{5}{x} \cdot \frac{1}{x^{2}} + \frac{C}{x^{2}}$

Step 8.3.1.2

Multiply $- \frac{5}{x} \cdot \frac{1}{x^{2}}$ .

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Step 8.3.1.2.1

Multiply $\frac{1}{x^{2}}$ by $\frac{5}{x}$ .

$y = - \frac{5}{x^{2} x} + \frac{C}{x^{2}}$

Step 8.3.1.2.2

Multiply $x^{2}$ by $x$ by adding the exponents.

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Step 8.3.1.2.2.1

Multiply $x^{2}$ by $x$ .

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Step 8.3.1.2.2.1.1

Raise $x$ to the power of $1$ .

$y = - \frac{5}{x^{2} x^{1}} + \frac{C}{x^{2}}$

Step 8.3.1.2.2.1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$y = - \frac{5}{x^{2 + 1}} + \frac{C}{x^{2}}$

Step 8.3.1.2.2.2

Add $2$ and $1$ .

$y = - \frac{5}{x^{3}} + \frac{C}{x^{2}}$