Calculus Examples

$\frac{d y}{d x} = 6 x (y^{2} + 1)$

Step 1

Separate the variables.

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Step 1.1

Multiply both sides by $\frac{1}{y^{2} + 1}$ .

$\frac{1}{y^{2} + 1} \frac{d y}{d x} = \frac{1}{y^{2} + 1} (6 x (y^{2} + 1))$

Step 1.2

Simplify.

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Step 1.2.1

Rewrite using the commutative property of multiplication.

$\frac{1}{y^{2} + 1} \frac{d y}{d x} = 6 \frac{1}{y^{2} + 1} (x (y^{2} + 1))$

Step 1.2.2

Combine $6$ and $\frac{1}{y^{2} + 1}$ .

$\frac{1}{y^{2} + 1} \frac{d y}{d x} = \frac{6}{y^{2} + 1} (x (y^{2} + 1))$

Step 1.2.3

Cancel the common factor of $y^{2} + 1$ .

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Step 1.2.3.1

Factor $y^{2} + 1$ out of $x (y^{2} + 1)$ .

$\frac{1}{y^{2} + 1} \frac{d y}{d x} = \frac{6}{y^{2} + 1} ((y^{2} + 1) x)$

Step 1.2.3.2

Cancel the common factor.

$\frac{1}{y^{2} + 1} \frac{d y}{d x} = \frac{6}{y^{2} + 1} ((y^{2} + 1) x)$

Step 1.2.3.3

Rewrite the expression.

$\frac{1}{y^{2} + 1} \frac{d y}{d x} = 6 x$

Step 1.3

Rewrite the equation.

$\frac{1}{y^{2} + 1} d y = 6 x d x$

Step 2

Integrate both sides.

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Step 2.1

Set up an integral on each side.

$\int \frac{1}{y^{2} + 1} d y = \int 6 x d x$

Step 2.2

Integrate the left side.

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Step 2.2.1

Simplify the expression.

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Step 2.2.1.1

Reorder $y^{2}$ and $1$ .

$\int \frac{1}{1 + y^{2}} d y = \int 6 x d x$

Step 2.2.1.2

Rewrite $1$ as $1^{2}$ .

$\int \frac{1}{1^{2} + y^{2}} d y = \int 6 x d x$

Step 2.2.2

The integral of $\frac{1}{1^{2} + y^{2}}$ with respect to $y$ is $\arctan (y) + C_{1}$ .

$\arctan (y) + C_{1} = \int 6 x d x$

Step 2.3

Integrate the right side.

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Step 2.3.1

Since $6$ is constant with respect to $x$ , move $6$ out of the integral.

$\arctan (y) + C_{1} = 6 \int x d x$

Step 2.3.2

By the Power Rule, the integral of $x$ with respect to $x$ is $\frac{1}{2} x^{2}$ .

$\arctan (y) + C_{1} = 6 (\frac{1}{2} x^{2} + C_{2})$

Step 2.3.3

Simplify the answer.

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Step 2.3.3.1

Rewrite $6 (\frac{1}{2} x^{2} + C_{2})$ as $6 (\frac{1}{2}) x^{2} + C_{2}$ .

$\arctan (y) + C_{1} = 6 (\frac{1}{2}) x^{2} + C_{2}$

Step 2.3.3.2

Simplify.

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Step 2.3.3.2.1

Combine $6$ and $\frac{1}{2}$ .

$\arctan (y) + C_{1} = \frac{6}{2} x^{2} + C_{2}$

Step 2.3.3.2.2

Cancel the common factor of $6$ and $2$ .

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Step 2.3.3.2.2.1

Factor $2$ out of $6$ .

$\arctan (y) + C_{1} = \frac{2 \cdot 3}{2} x^{2} + C_{2}$

Step 2.3.3.2.2.2

Cancel the common factors.

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Step 2.3.3.2.2.2.1

Factor $2$ out of $2$ .

$\arctan (y) + C_{1} = \frac{2 \cdot 3}{2 (1)} x^{2} + C_{2}$

Step 2.3.3.2.2.2.2

Cancel the common factor.

$\arctan (y) + C_{1} = \frac{2 \cdot 3}{2 \cdot 1} x^{2} + C_{2}$

Step 2.3.3.2.2.2.3

Rewrite the expression.

$\arctan (y) + C_{1} = \frac{3}{1} x^{2} + C_{2}$

Step 2.3.3.2.2.2.4

Divide $3$ by $1$ .

$\arctan (y) + C_{1} = 3 x^{2} + C_{2}$

Step 2.4

Group the constant of integration on the right side as $K$ .

$\arctan (y) = 3 x^{2} + K$

Step 3

Take the inverse arctangent of both sides of the equation to extract $y$ from inside the arctangent.

$y = \tan (3 x^{2} + K)$