Enter a problem...
Calculus Examples
dydx=xy3dydx=xy3
Step 1
Step 1.1
Multiply both sides by 1y31y3.
1y3dydx=1y3(xy3)1y3dydx=1y3(xy3)
Step 1.2
Cancel the common factor of y3.
Step 1.2.1
Factor y3 out of xy3.
1y3dydx=1y3(y3x)
Step 1.2.2
Cancel the common factor.
1y3dydx=1y3(y3x)
Step 1.2.3
Rewrite the expression.
1y3dydx=x
1y3dydx=x
Step 1.3
Rewrite the equation.
1y3dy=xdx
1y3dy=xdx
Step 2
Step 2.1
Set up an integral on each side.
∫1y3dy=∫xdx
Step 2.2
Integrate the left side.
Step 2.2.1
Apply basic rules of exponents.
Step 2.2.1.1
Move y3 out of the denominator by raising it to the -1 power.
∫(y3)-1dy=∫xdx
Step 2.2.1.2
Multiply the exponents in (y3)-1.
Step 2.2.1.2.1
Apply the power rule and multiply exponents, (am)n=amn.
∫y3⋅-1dy=∫xdx
Step 2.2.1.2.2
Multiply 3 by -1.
∫y-3dy=∫xdx
∫y-3dy=∫xdx
∫y-3dy=∫xdx
Step 2.2.2
By the Power Rule, the integral of y-3 with respect to y is -12y-2.
-12y-2+C1=∫xdx
Step 2.2.3
Simplify the answer.
Step 2.2.3.1
Rewrite -12y-2+C1 as -12⋅1y2+C1.
-12⋅1y2+C1=∫xdx
Step 2.2.3.2
Simplify.
Step 2.2.3.2.1
Multiply 1y2 by 12.
-1y2⋅2+C1=∫xdx
Step 2.2.3.2.2
Move 2 to the left of y2.
-12y2+C1=∫xdx
-12y2+C1=∫xdx
-12y2+C1=∫xdx
-12y2+C1=∫xdx
Step 2.3
By the Power Rule, the integral of x with respect to x is 12x2.
-12y2+C1=12x2+C2
Step 2.4
Group the constant of integration on the right side as K.
-12y2=12x2+K
-12y2=12x2+K
Step 3
Step 3.1
Combine 12 and x2.
-12y2=x22+K
Step 3.2
Find the LCD of the terms in the equation.
Step 3.2.1
Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.
2y2,2,1
Step 3.2.2
Since 2y2,2,1 contains both numbers and variables, there are two steps to find the LCM. Find LCM for the numeric part 2,2,1 then find LCM for the variable part y2.
Step 3.2.3
The LCM is the smallest positive number that all of the numbers divide into evenly.
1. List the prime factors of each number.
2. Multiply each factor the greatest number of times it occurs in either number.
Step 3.2.4
Since 2 has no factors besides 1 and 2.
2 is a prime number
Step 3.2.5
The number 1 is not a prime number because it only has one positive factor, which is itself.
Not prime
Step 3.2.6
The LCM of 2,2,1 is the result of multiplying all prime factors the greatest number of times they occur in either number.
2
Step 3.2.7
The factors for y2 are y⋅y, which is y multiplied by each other 2 times.
y2=y⋅y
y occurs 2 times.
Step 3.2.8
The LCM of y2 is the result of multiplying all prime factors the greatest number of times they occur in either term.
y⋅y
Step 3.2.9
Multiply y by y.
y2
Step 3.2.10
The LCM for 2y2,2,1 is the numeric part 2 multiplied by the variable part.
2y2
2y2
Step 3.3
Multiply each term in -12y2=x22+K by 2y2 to eliminate the fractions.
Step 3.3.1
Multiply each term in -12y2=x22+K by 2y2.
-12y2(2y2)=x22(2y2)+K(2y2)
Step 3.3.2
Simplify the left side.
Step 3.3.2.1
Cancel the common factor of 2y2.
Step 3.3.2.1.1
Move the leading negative in -12y2 into the numerator.
-12y2(2y2)=x22(2y2)+K(2y2)
Step 3.3.2.1.2
Cancel the common factor.
-12y2(2y2)=x22(2y2)+K(2y2)
Step 3.3.2.1.3
Rewrite the expression.
-1=x22(2y2)+K(2y2)
-1=x22(2y2)+K(2y2)
-1=x22(2y2)+K(2y2)
Step 3.3.3
Simplify the right side.
Step 3.3.3.1
Simplify each term.
Step 3.3.3.1.1
Rewrite using the commutative property of multiplication.
-1=2x22y2+K(2y2)
Step 3.3.3.1.2
Cancel the common factor of 2.
Step 3.3.3.1.2.1
Cancel the common factor.
-1=2x22y2+K(2y2)
Step 3.3.3.1.2.2
Rewrite the expression.
-1=x2y2+K(2y2)
-1=x2y2+K(2y2)
Step 3.3.3.1.3
Rewrite using the commutative property of multiplication.
-1=x2y2+2Ky2
-1=x2y2+2Ky2
-1=x2y2+2Ky2
-1=x2y2+2Ky2
Step 3.4
Solve the equation.
Step 3.4.1
Rewrite the equation as x2y2+2Ky2=-1.
x2y2+2Ky2=-1
Step 3.4.2
Factor y2 out of x2y2+2Ky2.
Step 3.4.2.1
Factor y2 out of x2y2.
y2x2+2Ky2=-1
Step 3.4.2.2
Factor y2 out of 2Ky2.
y2x2+y2(2K)=-1
Step 3.4.2.3
Factor y2 out of y2x2+y2(2K).
y2(x2+2K)=-1
y2(x2+2K)=-1
Step 3.4.3
Divide each term in y2(x2+2K)=-1 by x2+2K and simplify.
Step 3.4.3.1
Divide each term in y2(x2+2K)=-1 by x2+2K.
y2(x2+2K)x2+2K=-1x2+2K
Step 3.4.3.2
Simplify the left side.
Step 3.4.3.2.1
Cancel the common factor of x2+2K.
Step 3.4.3.2.1.1
Cancel the common factor.
y2(x2+2K)x2+2K=-1x2+2K
Step 3.4.3.2.1.2
Divide y2 by 1.
y2=-1x2+2K
y2=-1x2+2K
y2=-1x2+2K
Step 3.4.3.3
Simplify the right side.
Step 3.4.3.3.1
Move the negative in front of the fraction.
y2=-1x2+2K
y2=-1x2+2K
y2=-1x2+2K
Step 3.4.4
Take the specified root of both sides of the equation to eliminate the exponent on the left side.
y=±√-1x2+2K
Step 3.4.5
The complete solution is the result of both the positive and negative portions of the solution.
Step 3.4.5.1
First, use the positive value of the ± to find the first solution.
y=√-1x2+2K
Step 3.4.5.2
Next, use the negative value of the ± to find the second solution.
y=-√-1x2+2K
Step 3.4.5.3
The complete solution is the result of both the positive and negative portions of the solution.
y=√-1x2+2K
y=-√-1x2+2K
y=√-1x2+2K
y=-√-1x2+2K
y=√-1x2+2K
y=-√-1x2+2K
y=√-1x2+2K
y=-√-1x2+2K
Step 4
Simplify the constant of integration.
y=√-1x2+K
y=-√-1x2+K