Calculus Examples

$\frac{d y}{d x} = \frac{y}{x} + \frac{y}{\sqrt{x y}}$

Step 1

Rewrite the differential equation as a function of $\frac{y}{x}$ .

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Step 1.1

Assume $\sqrt{y^{2}} = y$ .

$\frac{d y}{d x} = \frac{y}{x} + \frac{\sqrt{y^{2}}}{\sqrt{x y}}$

Step 1.2

Combine $\sqrt{y^{2}}$ and $\sqrt{x y}$ into a single radical.

$\frac{d y}{d x} = \frac{y}{x} + \sqrt{\frac{y^{2}}{x y}}$

Step 1.3

Reduce the expression $\frac{y^{2}}{x y}$ by cancelling the common factors.

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Step 1.3.1

Factor $y$ out of $y^{2}$ .

$\frac{d y}{d x} = \frac{y}{x} + \sqrt{\frac{y \cdot y}{x y}}$

Step 1.3.2

Factor $y$ out of $x y$ .

$\frac{d y}{d x} = \frac{y}{x} + \sqrt{\frac{y \cdot y}{y x}}$

Step 1.3.3

Cancel the common factor.

$\frac{d y}{d x} = \frac{y}{x} + \sqrt{\frac{y \cdot y}{y x}}$

Step 1.3.4

Rewrite the expression.

$\frac{d y}{d x} = \frac{y}{x} + \sqrt{\frac{y}{x}}$

Step 2

Let $V = \frac{y}{x}$ . Substitute $V$ for $\frac{y}{x}$ .

$\frac{d y}{d x} = V + \sqrt{V}$

Step 3

Solve $V = \frac{y}{x}$ for $y$ .

$y = V x$

Step 4

Use the product rule to find the derivative of $y = V x$ with respect to $x$ .

$\frac{d y}{d x} = x \frac{d V}{d x} + V$

Step 5

Substitute $x \frac{d V}{d x} + V$ for $\frac{d y}{d x}$ .

$x \frac{d V}{d x} + V = V + \sqrt{V}$

Step 6

Solve the substituted differential equation.

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Step 6.1

Separate the variables.

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Step 6.1.1

Solve for $\frac{d V}{d x}$ .

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Step 6.1.1.1

Move all terms not containing $\frac{d V}{d x}$ to the right side of the equation.

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Step 6.1.1.1.1

Subtract $V$ from both sides of the equation.

$x \frac{d V}{d x} = V + \sqrt{V} - V$

Step 6.1.1.1.2

Combine the opposite terms in $V + \sqrt{V} - V$ .

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Step 6.1.1.1.2.1

Subtract $V$ from $V$ .

$x \frac{d V}{d x} = 0 + \sqrt{V}$

Step 6.1.1.1.2.2

Add $0$ and $\sqrt{V}$ .

$x \frac{d V}{d x} = \sqrt{V}$

Step 6.1.1.2

Divide each term in $x \frac{d V}{d x} = \sqrt{V}$ by $x$ and simplify.

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Step 6.1.1.2.1

Divide each term in $x \frac{d V}{d x} = \sqrt{V}$ by $x$ .

$\frac{x \frac{d V}{d x}}{x} = \frac{\sqrt{V}}{x}$

Step 6.1.1.2.2

Simplify the left side.

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Step 6.1.1.2.2.1

Cancel the common factor of $x$ .

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Step 6.1.1.2.2.1.1

Cancel the common factor.

$\frac{x \frac{d V}{d x}}{x} = \frac{\sqrt{V}}{x}$

Step 6.1.1.2.2.1.2

Divide $\frac{d V}{d x}$ by $1$ .

$\frac{d V}{d x} = \frac{\sqrt{V}}{x}$

Step 6.1.2

Multiply both sides by $\frac{1}{\sqrt{V}}$ .

$\frac{1}{\sqrt{V}} \frac{d V}{d x} = \frac{1}{\sqrt{V}} \cdot \frac{\sqrt{V}}{x}$

Step 6.1.3

Cancel the common factor of $\sqrt{V}$ .

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Step 6.1.3.1

Cancel the common factor.

$\frac{1}{\sqrt{V}} \frac{d V}{d x} = \frac{1}{\sqrt{V}} \cdot \frac{\sqrt{V}}{x}$

Step 6.1.3.2

Rewrite the expression.

$\frac{1}{\sqrt{V}} \frac{d V}{d x} = \frac{1}{x}$

Step 6.1.4

Rewrite the equation.

$\frac{1}{\sqrt{V}} d V = \frac{1}{x} d x$

Step 6.2

Integrate both sides.

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Step 6.2.1

Set up an integral on each side.

$\int \frac{1}{\sqrt{V}} d V = \int \frac{1}{x} d x$

Step 6.2.2

Integrate the left side.

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Step 6.2.2.1

Apply basic rules of exponents.

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Step 6.2.2.1.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{V}$ as $V^{\frac{1}{2}}$ .

$\int \frac{1}{V^{\frac{1}{2}}} d V = \int \frac{1}{x} d x$

Step 6.2.2.1.2

Move $V^{\frac{1}{2}}$ out of the denominator by raising it to the $- 1$ power.

$\int {(V^{\frac{1}{2}})}^{- 1} d V = \int \frac{1}{x} d x$

Step 6.2.2.1.3

Multiply the exponents in ${(V^{\frac{1}{2}})}^{- 1}$ .

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Step 6.2.2.1.3.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\int V^{\frac{1}{2} \cdot - 1} d V = \int \frac{1}{x} d x$

Step 6.2.2.1.3.2

Combine $\frac{1}{2}$ and $- 1$ .

$\int V^{\frac{- 1}{2}} d V = \int \frac{1}{x} d x$

Step 6.2.2.1.3.3

Move the negative in front of the fraction.

$\int V^{- \frac{1}{2}} d V = \int \frac{1}{x} d x$

Step 6.2.2.2

By the Power Rule, the integral of $V^{- \frac{1}{2}}$ with respect to $V$ is $2 V^{\frac{1}{2}}$ .

$2 V^{\frac{1}{2}} + C_{1} = \int \frac{1}{x} d x$

Step 6.2.3

The integral of $\frac{1}{x}$ with respect to $x$ is $\ln (| x |)$ .

$2 V^{\frac{1}{2}} + C_{1} = \ln (| x |) + C_{2}$

Step 6.2.4

Group the constant of integration on the right side as $C$ .

$2 V^{\frac{1}{2}} = \ln (| x |) + C$

Step 6.3

Solve for $V$ .

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Step 6.3.1

Divide each term in $2 V^{\frac{1}{2}} = \ln (| x |) + C$ by $2$ and simplify.

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Step 6.3.1.1

Divide each term in $2 V^{\frac{1}{2}} = \ln (| x |) + C$ by $2$ .

$\frac{2 V^{\frac{1}{2}}}{2} = \frac{\ln (| x |)}{2} + \frac{C}{2}$

Step 6.3.1.2

Simplify the left side.

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Step 6.3.1.2.1

Cancel the common factor.

$\frac{2 V^{\frac{1}{2}}}{2} = \frac{\ln (| x |)}{2} + \frac{C}{2}$

Step 6.3.1.2.2

Divide $V^{\frac{1}{2}}$ by $1$ .

$V^{\frac{1}{2}} = \frac{\ln (| x |)}{2} + \frac{C}{2}$

Step 6.3.1.3

Simplify the right side.

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Step 6.3.1.3.1

Simplify each term.

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Step 6.3.1.3.1.1

Rewrite $\frac{\ln (| x |)}{2}$ as $\frac{1}{2} \ln (| x |)$ .

$V^{\frac{1}{2}} = \frac{1}{2} \ln (| x |) + \frac{C}{2}$

Step 6.3.1.3.1.2

Simplify $\frac{1}{2} \ln (| x |)$ by moving $\frac{1}{2}$ inside the logarithm.

$V^{\frac{1}{2}} = \ln ({| x |}^{\frac{1}{2}}) + \frac{C}{2}$

Step 6.3.2

Raise each side of the equation to the power of $2$ to eliminate the fractional exponent on the left side.

${(V^{\frac{1}{2}})}^{2} = {(\ln ({| x |}^{\frac{1}{2}}) + \frac{C}{2})}^{2}$

Step 6.3.3

Simplify the left side.

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Step 6.3.3.1

Simplify ${(V^{\frac{1}{2}})}^{2}$ .

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Step 6.3.3.1.1

Multiply the exponents in ${(V^{\frac{1}{2}})}^{2}$ .

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Step 6.3.3.1.1.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$V^{\frac{1}{2} \cdot 2} = {(\ln ({| x |}^{\frac{1}{2}}) + \frac{C}{2})}^{2}$

Step 6.3.3.1.1.2

Cancel the common factor of $2$ .

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Step 6.3.3.1.1.2.1

Cancel the common factor.

$V^{\frac{1}{2} \cdot 2} = {(\ln ({| x |}^{\frac{1}{2}}) + \frac{C}{2})}^{2}$

Step 6.3.3.1.1.2.2

Rewrite the expression.

$V^{1} = {(\ln ({| x |}^{\frac{1}{2}}) + \frac{C}{2})}^{2}$

Step 6.3.3.1.2

Simplify.

$V = {(\ln ({| x |}^{\frac{1}{2}}) + \frac{C}{2})}^{2}$

Step 6.4

Simplify the constant of integration.

$V = {(\ln ({| x |}^{\frac{1}{2}}) + C)}^{2}$

Step 7

Substitute $\frac{y}{x}$ for $V$ .

$\frac{y}{x} = {(\ln ({| x |}^{\frac{1}{2}}) + C)}^{2}$

Step 8

Solve $\frac{y}{x} = {(\ln ({| x |}^{\frac{1}{2}}) + C)}^{2}$ for $y$ .

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Step 8.1

Multiply both sides by $x$ .

$\frac{y}{x} x = {(\ln ({| x |}^{\frac{1}{2}}) + C)}^{2} x$

Step 8.2

Simplify.

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Step 8.2.1

Simplify the left side.

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Step 8.2.1.1

Cancel the common factor of $x$ .

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Step 8.2.1.1.1

Cancel the common factor.

$\frac{y}{x} x = {(\ln ({| x |}^{\frac{1}{2}}) + C)}^{2} x$

Step 8.2.1.1.2

Rewrite the expression.

$y = {(\ln ({| x |}^{\frac{1}{2}}) + C)}^{2} x$

Step 8.2.2

Simplify the right side.

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Step 8.2.2.1

Reorder factors in ${(\ln ({| x |}^{\frac{1}{2}}) + C)}^{2} x$ .

$y = x {(\ln ({| x |}^{\frac{1}{2}}) + C)}^{2}$