Calculus Examples

$lim_{x \to \infty} \frac{8 x - 5}{\sqrt{4 x^{2} + 3}}$

Step 1

Divide the numerator and denominator by the highest power of $x$ in the denominator, which is $x = \sqrt{x^{2}}$ .

$lim_{x \to \infty} \frac{\frac{8 x}{x} + \frac{- 5}{x}}{\sqrt{\frac{4 x^{2}}{x^{2}} + \frac{3}{x^{2}}}}$

Step 2

Evaluate the limit.

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Step 2.1

Simplify each term.

$lim_{x \to \infty} \frac{8 - \frac{5}{x}}{\sqrt{\frac{4 x^{2}}{x^{2}} + \frac{3}{x^{2}}}}$

Step 2.2

Cancel the common factor of $x^{2}$ .

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Step 2.2.1

Cancel the common factor.

$lim_{x \to \infty} \frac{8 - \frac{5}{x}}{\sqrt{\frac{4 x^{2}}{x^{2}} + \frac{3}{x^{2}}}}$

Step 2.2.2

Divide $4$ by $1$ .

$lim_{x \to \infty} \frac{8 - \frac{5}{x}}{\sqrt{4 + \frac{3}{x^{2}}}}$

Step 2.3

Split the limit using the Limits Quotient Rule on the limit as $x$ approaches $\infty$ .

$\frac{lim_{x \to \infty} 8 - \frac{5}{x}}{lim_{x \to \infty} \sqrt{4 + \frac{3}{x^{2}}}}$

Step 2.4

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $\infty$ .

$\frac{lim_{x \to \infty} 8 - lim_{x \to \infty} \frac{5}{x}}{lim_{x \to \infty} \sqrt{4 + \frac{3}{x^{2}}}}$

Step 2.5

Evaluate the limit of $8$ which is constant as $x$ approaches $\infty$ .

$\frac{8 - lim_{x \to \infty} \frac{5}{x}}{lim_{x \to \infty} \sqrt{4 + \frac{3}{x^{2}}}}$

Step 2.6

Move the term $5$ outside of the limit because it is constant with respect to $x$ .

$\frac{8 - 5 lim_{x \to \infty} \frac{1}{x}}{lim_{x \to \infty} \sqrt{4 + \frac{3}{x^{2}}}}$

Step 3

Since its numerator approaches a real number while its denominator is unbounded, the fraction $\frac{1}{x}$ approaches $0$ .

$\frac{8 - 5 \cdot 0}{lim_{x \to \infty} \sqrt{4 + \frac{3}{x^{2}}}}$

Step 4

Evaluate the limit.

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Step 4.1

Move the limit under the radical sign.

$\frac{8 - 5 \cdot 0}{\sqrt{lim_{x \to \infty} 4 + \frac{3}{x^{2}}}}$

Step 4.2

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $\infty$ .

$\frac{8 - 5 \cdot 0}{\sqrt{lim_{x \to \infty} 4 + lim_{x \to \infty} \frac{3}{x^{2}}}}$

Step 4.3

Evaluate the limit of $4$ which is constant as $x$ approaches $\infty$ .

$\frac{8 - 5 \cdot 0}{\sqrt{4 + lim_{x \to \infty} \frac{3}{x^{2}}}}$

Step 4.4

Move the term $3$ outside of the limit because it is constant with respect to $x$ .

$\frac{8 - 5 \cdot 0}{\sqrt{4 + 3 lim_{x \to \infty} \frac{1}{x^{2}}}}$

Step 5

Since its numerator approaches a real number while its denominator is unbounded, the fraction $\frac{1}{x^{2}}$ approaches $0$ .

$\frac{8 - 5 \cdot 0}{\sqrt{4 + 3 \cdot 0}}$

Step 6

Simplify the answer.

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Step 6.1

Simplify the numerator.

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Step 6.1.1

Multiply $- 5$ by $0$ .

$\frac{8 + 0}{\sqrt{4 + 3 \cdot 0}}$

Step 6.1.2

Add $8$ and $0$ .

$\frac{8}{\sqrt{4 + 3 \cdot 0}}$

Step 6.2

Simplify the denominator.

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Step 6.2.1

Multiply $3$ by $0$ .

$\frac{8}{\sqrt{4 + 0}}$

Step 6.2.2

Add $4$ and $0$ .

$\frac{8}{\sqrt{4}}$

Step 6.2.3

Rewrite $4$ as $2^{2}$ .

$\frac{8}{\sqrt{2^{2}}}$

Step 6.2.4

Pull terms out from under the radical, assuming positive real numbers.

$\frac{8}{2}$

Step 6.3

Divide $8$ by $2$ .

$4$