Basic Math Examples

$- \frac{12}{3 - 9 u} - \frac{6 u}{9 u^{2} + 6 u + 1} - \frac{6 u}{9 u^{2} - 1}$

Step 1

Simplify each term.

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Step 1.1

Cancel the common factor of $12$ and $3 - 9 u$ .

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Step 1.1.1

Factor $3$ out of $12$ .

$- \frac{3 \cdot 4}{3 - 9 u} - \frac{6 u}{9 u^{2} + 6 u + 1} - \frac{6 u}{9 u^{2} - 1}$

Step 1.1.2

Cancel the common factors.

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Step 1.1.2.1

Factor $3$ out of $3$ .

$- \frac{3 \cdot 4}{3 (1) - 9 u} - \frac{6 u}{9 u^{2} + 6 u + 1} - \frac{6 u}{9 u^{2} - 1}$

Step 1.1.2.2

Factor $3$ out of $- 9 u$ .

$- \frac{3 \cdot 4}{3 (1) + 3 (- 3 u)} - \frac{6 u}{9 u^{2} + 6 u + 1} - \frac{6 u}{9 u^{2} - 1}$

Step 1.1.2.3

Factor $3$ out of $3 (1) + 3 (- 3 u)$ .

$- \frac{3 \cdot 4}{3 (1 - 3 u)} - \frac{6 u}{9 u^{2} + 6 u + 1} - \frac{6 u}{9 u^{2} - 1}$

Step 1.1.2.4

Cancel the common factor.

$- \frac{3 \cdot 4}{3 (1 - 3 u)} - \frac{6 u}{9 u^{2} + 6 u + 1} - \frac{6 u}{9 u^{2} - 1}$

Step 1.1.2.5

Rewrite the expression.

$- \frac{4}{1 - 3 u} - \frac{6 u}{9 u^{2} + 6 u + 1} - \frac{6 u}{9 u^{2} - 1}$

Step 1.2

Factor using the perfect square rule.

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Step 1.2.1

Rewrite $9 u^{2}$ as ${(3 u)}^{2}$ .

$- \frac{4}{1 - 3 u} - \frac{6 u}{{(3 u)}^{2} + 6 u + 1} - \frac{6 u}{9 u^{2} - 1}$

Step 1.2.2

Rewrite $1$ as $1^{2}$ .

$- \frac{4}{1 - 3 u} - \frac{6 u}{{(3 u)}^{2} + 6 u + 1^{2}} - \frac{6 u}{9 u^{2} - 1}$

Step 1.2.3

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

$6 u = 2 \cdot (3 u) \cdot 1$

Step 1.2.4

Rewrite the polynomial.

$- \frac{4}{1 - 3 u} - \frac{6 u}{{(3 u)}^{2} + 2 \cdot (3 u) \cdot 1 + 1^{2}} - \frac{6 u}{9 u^{2} - 1}$

Step 1.2.5

Factor using the perfect square trinomial rule $a^{2} + 2 a b + b^{2} = {(a + b)}^{2}$ , where $a = 3 u$ and $b = 1$ .

$- \frac{4}{1 - 3 u} - \frac{6 u}{{(3 u + 1)}^{2}} - \frac{6 u}{9 u^{2} - 1}$

Step 1.3

Simplify the denominator.

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Step 1.3.1

Rewrite $9 u^{2}$ as ${(3 u)}^{2}$ .

$- \frac{4}{1 - 3 u} - \frac{6 u}{{(3 u + 1)}^{2}} - \frac{6 u}{{(3 u)}^{2} - 1}$

Step 1.3.2

Rewrite $1$ as $1^{2}$ .

$- \frac{4}{1 - 3 u} - \frac{6 u}{{(3 u + 1)}^{2}} - \frac{6 u}{{(3 u)}^{2} - 1^{2}}$

Step 1.3.3

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 3 u$ and $b = 1$ .

$- \frac{4}{1 - 3 u} - \frac{6 u}{{(3 u + 1)}^{2}} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 2

To write $- \frac{4}{1 - 3 u}$ as a fraction with a common denominator, multiply by $\frac{{(3 u + 1)}^{2}}{{(3 u + 1)}^{2}}$ .

$- \frac{4}{1 - 3 u} \cdot \frac{{(3 u + 1)}^{2}}{{(3 u + 1)}^{2}} - \frac{6 u}{{(3 u + 1)}^{2}} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 3

To write $- \frac{6 u}{{(3 u + 1)}^{2}}$ as a fraction with a common denominator, multiply by $\frac{1 - 3 u}{1 - 3 u}$ .

$- \frac{4}{1 - 3 u} \cdot \frac{{(3 u + 1)}^{2}}{{(3 u + 1)}^{2}} - \frac{6 u}{{(3 u + 1)}^{2}} \cdot \frac{1 - 3 u}{1 - 3 u} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 4

Write each expression with a common denominator of $(1 - 3 u) {(3 u + 1)}^{2}$ , by multiplying each by an appropriate factor of $1$ .

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Step 4.1

Multiply $\frac{4}{1 - 3 u}$ by $\frac{{(3 u + 1)}^{2}}{{(3 u + 1)}^{2}}$ .

$- \frac{4 {(3 u + 1)}^{2}}{(1 - 3 u) {(3 u + 1)}^{2}} - \frac{6 u}{{(3 u + 1)}^{2}} \cdot \frac{1 - 3 u}{1 - 3 u} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 4.2

Multiply $\frac{6 u}{{(3 u + 1)}^{2}}$ by $\frac{1 - 3 u}{1 - 3 u}$ .

$- \frac{4 {(3 u + 1)}^{2}}{(1 - 3 u) {(3 u + 1)}^{2}} - \frac{6 u (1 - 3 u)}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 4.3

Reorder the factors of $(1 - 3 u) {(3 u + 1)}^{2}$ .

$- \frac{4 {(3 u + 1)}^{2}}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u (1 - 3 u)}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 5

Combine the numerators over the common denominator.

$\frac{- 4 {(3 u + 1)}^{2} - 6 u (1 - 3 u)}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 6

Simplify the numerator.

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Step 6.1

Factor $2$ out of $- 4 {(3 u + 1)}^{2} - 6 u (1 - 3 u)$ .

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Step 6.1.1

Factor $2$ out of $- 4 {(3 u + 1)}^{2}$ .

$\frac{2 (- 2 {(3 u + 1)}^{2}) - 6 u (1 - 3 u)}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 6.1.2

Factor $2$ out of $- 6 u (1 - 3 u)$ .

$\frac{2 (- 2 {(3 u + 1)}^{2}) + 2 (- 3 u (1 - 3 u))}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 6.1.3

Factor $2$ out of $2 (- 2 {(3 u + 1)}^{2}) + 2 (- 3 u (1 - 3 u))$ .

$\frac{2 (- 2 {(3 u + 1)}^{2} - 3 u (1 - 3 u))}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 6.2

Rewrite ${(3 u + 1)}^{2}$ as $(3 u + 1) (3 u + 1)$ .

$\frac{2 (- 2 ((3 u + 1) (3 u + 1)) - 3 u (1 - 3 u))}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 6.3

Expand $(3 u + 1) (3 u + 1)$ using the FOIL Method.

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Step 6.3.1

Apply the distributive property.

$\frac{2 (- 2 (3 u (3 u + 1) + 1 (3 u + 1)) - 3 u (1 - 3 u))}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 6.3.2

Apply the distributive property.

$\frac{2 (- 2 (3 u (3 u) + 3 u \cdot 1 + 1 (3 u + 1)) - 3 u (1 - 3 u))}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 6.3.3

Apply the distributive property.

$\frac{2 (- 2 (3 u (3 u) + 3 u \cdot 1 + 1 (3 u) + 1 \cdot 1) - 3 u (1 - 3 u))}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 6.4

Simplify and combine like terms.

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Step 6.4.1

Simplify each term.

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Step 6.4.1.1

Rewrite using the commutative property of multiplication.

$\frac{2 (- 2 (3 \cdot 3 u \cdot u + 3 u \cdot 1 + 1 (3 u) + 1 \cdot 1) - 3 u (1 - 3 u))}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 6.4.1.2

Multiply $u$ by $u$ by adding the exponents.

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Step 6.4.1.2.1

Move $u$ .

$\frac{2 (- 2 (3 \cdot 3 (u \cdot u) + 3 u \cdot 1 + 1 (3 u) + 1 \cdot 1) - 3 u (1 - 3 u))}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 6.4.1.2.2

Multiply $u$ by $u$ .

$\frac{2 (- 2 (3 \cdot 3 u^{2} + 3 u \cdot 1 + 1 (3 u) + 1 \cdot 1) - 3 u (1 - 3 u))}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 6.4.1.3

Multiply $3$ by $3$ .

$\frac{2 (- 2 (9 u^{2} + 3 u \cdot 1 + 1 (3 u) + 1 \cdot 1) - 3 u (1 - 3 u))}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 6.4.1.4

Multiply $3$ by $1$ .

$\frac{2 (- 2 (9 u^{2} + 3 u + 1 (3 u) + 1 \cdot 1) - 3 u (1 - 3 u))}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 6.4.1.5

Multiply $3 u$ by $1$ .

$\frac{2 (- 2 (9 u^{2} + 3 u + 3 u + 1 \cdot 1) - 3 u (1 - 3 u))}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 6.4.1.6

Multiply $1$ by $1$ .

$\frac{2 (- 2 (9 u^{2} + 3 u + 3 u + 1) - 3 u (1 - 3 u))}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 6.4.2

Add $3 u$ and $3 u$ .

$\frac{2 (- 2 (9 u^{2} + 6 u + 1) - 3 u (1 - 3 u))}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 6.5

Apply the distributive property.

$\frac{2 (- 2 (9 u^{2}) - 2 (6 u) - 2 \cdot 1 - 3 u (1 - 3 u))}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 6.6

Simplify.

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Step 6.6.1

Multiply $9$ by $- 2$ .

$\frac{2 (- 18 u^{2} - 2 (6 u) - 2 \cdot 1 - 3 u (1 - 3 u))}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 6.6.2

Multiply $6$ by $- 2$ .

$\frac{2 (- 18 u^{2} - 12 u - 2 \cdot 1 - 3 u (1 - 3 u))}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 6.6.3

Multiply $- 2$ by $1$ .

$\frac{2 (- 18 u^{2} - 12 u - 2 - 3 u (1 - 3 u))}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 6.7

Apply the distributive property.

$\frac{2 (- 18 u^{2} - 12 u - 2 - 3 u \cdot 1 - 3 u (- 3 u))}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 6.8

Multiply $- 3$ by $1$ .

$\frac{2 (- 18 u^{2} - 12 u - 2 - 3 u - 3 u (- 3 u))}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 6.9

Rewrite using the commutative property of multiplication.

$\frac{2 (- 18 u^{2} - 12 u - 2 - 3 u - 3 \cdot - 3 u \cdot u)}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 6.10

Simplify each term.

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Step 6.10.1

Multiply $u$ by $u$ by adding the exponents.

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Step 6.10.1.1

Move $u$ .

$\frac{2 (- 18 u^{2} - 12 u - 2 - 3 u - 3 \cdot - 3 (u \cdot u))}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 6.10.1.2

Multiply $u$ by $u$ .

$\frac{2 (- 18 u^{2} - 12 u - 2 - 3 u - 3 \cdot - 3 u^{2})}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 6.10.2

Multiply $- 3$ by $- 3$ .

$\frac{2 (- 18 u^{2} - 12 u - 2 - 3 u + 9 u^{2})}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 6.11

Add $- 18 u^{2}$ and $9 u^{2}$ .

$\frac{2 (- 9 u^{2} - 12 u - 2 - 3 u)}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 6.12

Subtract $3 u$ from $- 12 u$ .

$\frac{2 (- 9 u^{2} - 15 u - 2)}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (3 u - 1)}$

Step 7

Simplify with factoring out.

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Step 7.1

Factor $- 1$ out of $3 u$ .

$\frac{2 (- 9 u^{2} - 15 u - 2)}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (- (- 3 u) - 1)}$

Step 7.2

Rewrite $- 1$ as $- 1 (1)$ .

$\frac{2 (- 9 u^{2} - 15 u - 2)}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (- (- 3 u) - 1 (1))}$

Step 7.3

Factor $- 1$ out of $- (- 3 u) - 1 (1)$ .

$\frac{2 (- 9 u^{2} - 15 u - 2)}{{(3 u + 1)}^{2} (1 - 3 u)} - \frac{6 u}{(3 u + 1) (- (- 3 u + 1))}$

Step 7.4

Reorder terms.

$\frac{2 (- 9 u^{2} - 15 u - 2)}{{(3 u + 1)}^{2} (- 3 u + 1)} - \frac{6 u}{(3 u + 1) (- (- 3 u + 1))}$

Step 8

To write $\frac{2 (- 9 u^{2} - 15 u - 2)}{{(3 u + 1)}^{2} (- 3 u + 1)}$ as a fraction with a common denominator, multiply by $\frac{- 1}{- 1}$ .

$\frac{2 (- 9 u^{2} - 15 u - 2)}{{(3 u + 1)}^{2} (- 3 u + 1)} \cdot \frac{- 1}{- 1} - \frac{6 u}{(3 u + 1) (- (- 3 u + 1))}$

Step 9

To write $- \frac{6 u}{(3 u + 1) (- (- 3 u + 1))}$ as a fraction with a common denominator, multiply by $\frac{3 u + 1}{3 u + 1}$ .

$\frac{2 (- 9 u^{2} - 15 u - 2)}{{(3 u + 1)}^{2} (- 3 u + 1)} \cdot \frac{- 1}{- 1} - \frac{6 u}{(3 u + 1) (- (- 3 u + 1))} \cdot \frac{3 u + 1}{3 u + 1}$

Step 10

Write each expression with a common denominator of $(- 3 u + 1) \cdot - 1 {(3 u + 1)}^{2}$ , by multiplying each by an appropriate factor of $1$ .

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Step 10.1

Multiply $\frac{2 (- 9 u^{2} - 15 u - 2)}{{(3 u + 1)}^{2} (- 3 u + 1)}$ by $\frac{- 1}{- 1}$ .

$\frac{2 (- 9 u^{2} - 15 u - 2) \cdot - 1}{{(3 u + 1)}^{2} (- 3 u + 1) \cdot - 1} - \frac{6 u}{(3 u + 1) (- (- 3 u + 1))} \cdot \frac{3 u + 1}{3 u + 1}$

Step 10.2

Multiply $\frac{6 u}{(3 u + 1) (- (- 3 u + 1))}$ by $\frac{3 u + 1}{3 u + 1}$ .

$\frac{2 (- 9 u^{2} - 15 u - 2) \cdot - 1}{{(3 u + 1)}^{2} (- 3 u + 1) \cdot - 1} - \frac{6 u (3 u + 1)}{(3 u + 1) (- (- 3 u + 1)) (3 u + 1)}$

Step 10.3

Raise $3 u + 1$ to the power of $1$ .

$\frac{2 (- 9 u^{2} - 15 u - 2) \cdot - 1}{{(3 u + 1)}^{2} (- 3 u + 1) \cdot - 1} - \frac{6 u (3 u + 1)}{- (- 3 u + 1) ({(3 u + 1)}^{1} (3 u + 1))}$

Step 10.4

Raise $3 u + 1$ to the power of $1$ .

$\frac{2 (- 9 u^{2} - 15 u - 2) \cdot - 1}{{(3 u + 1)}^{2} (- 3 u + 1) \cdot - 1} - \frac{6 u (3 u + 1)}{- (- 3 u + 1) ({(3 u + 1)}^{1} {(3 u + 1)}^{1})}$

Step 10.5

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 (- 9 u^{2} - 15 u - 2) \cdot - 1}{{(3 u + 1)}^{2} (- 3 u + 1) \cdot - 1} - \frac{6 u (3 u + 1)}{- (- 3 u + 1) {(3 u + 1)}^{1 + 1}}$

Step 10.6

Add $1$ and $1$ .

$\frac{2 (- 9 u^{2} - 15 u - 2) \cdot - 1}{{(3 u + 1)}^{2} (- 3 u + 1) \cdot - 1} - \frac{6 u (3 u + 1)}{- (- 3 u + 1) {(3 u + 1)}^{2}}$

Step 10.7

Reorder the factors of ${(3 u + 1)}^{2} (- 3 u + 1) \cdot - 1$ .

$\frac{2 (- 9 u^{2} - 15 u - 2) \cdot - 1}{- {(3 u + 1)}^{2} (- 3 u + 1)} - \frac{6 u (3 u + 1)}{- (- 3 u + 1) {(3 u + 1)}^{2}}$

Step 10.8

Reorder the factors of $- (- 3 u + 1) {(3 u + 1)}^{2}$ .

$\frac{2 (- 9 u^{2} - 15 u - 2) \cdot - 1}{- {(3 u + 1)}^{2} (- 3 u + 1)} - \frac{6 u (3 u + 1)}{- {(3 u + 1)}^{2} (- 3 u + 1)}$

Step 11

Combine the numerators over the common denominator.

$\frac{2 (- 9 u^{2} - 15 u - 2) \cdot - 1 - 6 u (3 u + 1)}{- {(3 u + 1)}^{2} (- 3 u + 1)}$

Step 12

Simplify the numerator.

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Step 12.1

Factor $2$ out of $2 (- 9 u^{2} - 15 u - 2) \cdot - 1 - 6 u (3 u + 1)$ .

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Step 12.1.1

Factor $2$ out of $2 (- 9 u^{2} - 15 u - 2) \cdot - 1$ .

$\frac{2 ((- 9 u^{2} - 15 u - 2) \cdot - 1) - 6 u (3 u + 1)}{- {(3 u + 1)}^{2} (- 3 u + 1)}$

Step 12.1.2

Factor $2$ out of $- 6 u (3 u + 1)$ .

$\frac{2 ((- 9 u^{2} - 15 u - 2) \cdot - 1) + 2 (- 3 u (3 u + 1))}{- {(3 u + 1)}^{2} (- 3 u + 1)}$

Step 12.1.3

Factor $2$ out of $2 ((- 9 u^{2} - 15 u - 2) \cdot - 1) + 2 (- 3 u (3 u + 1))$ .

$\frac{2 ((- 9 u^{2} - 15 u - 2) \cdot - 1 - 3 u (3 u + 1))}{- {(3 u + 1)}^{2} (- 3 u + 1)}$

Step 12.2

Apply the distributive property.

$\frac{2 (- 9 u^{2} \cdot - 1 - 15 u \cdot - 1 - 2 \cdot - 1 - 3 u (3 u + 1))}{- {(3 u + 1)}^{2} (- 3 u + 1)}$

Step 12.3

Simplify.

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Step 12.3.1

Multiply $- 1$ by $- 9$ .

$\frac{2 (9 u^{2} - 15 u \cdot - 1 - 2 \cdot - 1 - 3 u (3 u + 1))}{- {(3 u + 1)}^{2} (- 3 u + 1)}$

Step 12.3.2

Multiply $- 1$ by $- 15$ .

$\frac{2 (9 u^{2} + 15 u - 2 \cdot - 1 - 3 u (3 u + 1))}{- {(3 u + 1)}^{2} (- 3 u + 1)}$

Step 12.3.3

Multiply $- 2$ by $- 1$ .

$\frac{2 (9 u^{2} + 15 u + 2 - 3 u (3 u + 1))}{- {(3 u + 1)}^{2} (- 3 u + 1)}$

Step 12.4

Apply the distributive property.

$\frac{2 (9 u^{2} + 15 u + 2 - 3 u (3 u) - 3 u \cdot 1)}{- {(3 u + 1)}^{2} (- 3 u + 1)}$

Step 12.5

Rewrite using the commutative property of multiplication.

$\frac{2 (9 u^{2} + 15 u + 2 - 3 \cdot 3 u \cdot u - 3 u \cdot 1)}{- {(3 u + 1)}^{2} (- 3 u + 1)}$

Step 12.6

Multiply $- 3$ by $1$ .

$\frac{2 (9 u^{2} + 15 u + 2 - 3 \cdot 3 u \cdot u - 3 u)}{- {(3 u + 1)}^{2} (- 3 u + 1)}$

Step 12.7

Simplify each term.

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Step 12.7.1

Multiply $u$ by $u$ by adding the exponents.

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Step 12.7.1.1

Move $u$ .

$\frac{2 (9 u^{2} + 15 u + 2 - 3 \cdot 3 (u \cdot u) - 3 u)}{- {(3 u + 1)}^{2} (- 3 u + 1)}$

Step 12.7.1.2

Multiply $u$ by $u$ .

$\frac{2 (9 u^{2} + 15 u + 2 - 3 \cdot 3 u^{2} - 3 u)}{- {(3 u + 1)}^{2} (- 3 u + 1)}$

Step 12.7.2

Multiply $- 3$ by $3$ .

$\frac{2 (9 u^{2} + 15 u + 2 - 9 u^{2} - 3 u)}{- {(3 u + 1)}^{2} (- 3 u + 1)}$

Step 12.8

Subtract $9 u^{2}$ from $9 u^{2}$ .

$\frac{2 (15 u + 2 + 0 - 3 u)}{- {(3 u + 1)}^{2} (- 3 u + 1)}$

Step 12.9

Add $15 u$ and $0$ .

$\frac{2 (15 u + 2 - 3 u)}{- {(3 u + 1)}^{2} (- 3 u + 1)}$

Step 12.10

Subtract $3 u$ from $15 u$ .

$\frac{2 (12 u + 2)}{- {(3 u + 1)}^{2} (- 3 u + 1)}$

Step 12.11

Factor $2$ out of $12 u + 2$ .

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Step 12.11.1

Factor $2$ out of $12 u$ .

$\frac{2 (2 (6 u) + 2)}{- {(3 u + 1)}^{2} (- 3 u + 1)}$

Step 12.11.2

Factor $2$ out of $2$ .

$\frac{2 (2 (6 u) + 2 (1))}{- {(3 u + 1)}^{2} (- 3 u + 1)}$

Step 12.11.3

Factor $2$ out of $2 (6 u) + 2 (1)$ .

$\frac{2 (2 (6 u + 1))}{- {(3 u + 1)}^{2} (- 3 u + 1)}$

$\frac{2 \cdot 2 (6 u + 1)}{- {(3 u + 1)}^{2} (- 3 u + 1)}$

Step 12.12

Multiply $2$ by $2$ .

$\frac{4 (6 u + 1)}{- {(3 u + 1)}^{2} (- 3 u + 1)}$

Step 13

Simplify with factoring out.

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Step 13.1

Move the negative in front of the fraction.

$- \frac{4 (6 u + 1)}{{(3 u + 1)}^{2} (- 3 u + 1)}$

Step 13.2

Factor $- 1$ out of $- 3 u$ .

$- \frac{4 (6 u + 1)}{{(3 u + 1)}^{2} (- (3 u) + 1)}$

Step 13.3

Rewrite $1$ as $- 1 (- 1)$ .

$- \frac{4 (6 u + 1)}{{(3 u + 1)}^{2} (- (3 u) - 1 (- 1))}$

Step 13.4

Factor $- 1$ out of $- (3 u) - 1 (- 1)$ .

$- \frac{4 (6 u + 1)}{{(3 u + 1)}^{2} (- (3 u - 1))}$

Step 13.5

Simplify the expression.

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Step 13.5.1

Rewrite $- (3 u - 1)$ as $- 1 (3 u - 1)$ .

$- \frac{4 (6 u + 1)}{{(3 u + 1)}^{2} (- 1 (3 u - 1))}$

Step 13.5.2

Move the negative in front of the fraction.

$- - \frac{4 (6 u + 1)}{{(3 u + 1)}^{2} (3 u - 1)}$

Step 13.5.3

Multiply $- 1$ by $- 1$ .

$1 \frac{4 (6 u + 1)}{{(3 u + 1)}^{2} (3 u - 1)}$

Step 13.5.4

Multiply $\frac{4 (6 u + 1)}{{(3 u + 1)}^{2} (3 u - 1)}$ by $1$ .

$\frac{4 (6 u + 1)}{{(3 u + 1)}^{2} (3 u - 1)}$