Basic Math Examples

$\frac{5 \cdot S^{\frac{1}{3}}}{3 \cdot (20000 - 100 \cdot 102 + 5 \cdot S^{\frac{1}{3}} + 5 \cdot S^{\frac{1}{3}})}$

Step 1

Factor $5$ out of $5 \cdot S^{\frac{1}{3}}$ .

$\frac{5 (S^{\frac{1}{3}})}{3 \cdot (20000 - 100 \cdot 102 + 5 \cdot S^{\frac{1}{3}} + 5 \cdot S^{\frac{1}{3}})}$

Step 2

Cancel the common factors.

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Step 2.1

Factor $5$ out of $3 \cdot (20000 - 100 \cdot 102 + 5 \cdot S^{\frac{1}{3}} + 5 \cdot S^{\frac{1}{3}})$ .

$\frac{5 (S^{\frac{1}{3}})}{5 (3 \cdot (4000 - 20 \cdot 102 + S^{\frac{1}{3}} + S^{\frac{1}{3}}))}$

Step 2.2

Cancel the common factor.

$\frac{5 S^{\frac{1}{3}}}{5 (3 \cdot (4000 - 20 \cdot 102 + S^{\frac{1}{3}} + S^{\frac{1}{3}}))}$

Step 2.3

Rewrite the expression.

$\frac{S^{\frac{1}{3}}}{3 \cdot (4000 - 20 \cdot 102 + S^{\frac{1}{3}} + S^{\frac{1}{3}})}$

Step 3

Simplify the denominator.

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Step 3.1

Add $S^{\frac{1}{3}}$ and $S^{\frac{1}{3}}$ .

$\frac{S^{\frac{1}{3}}}{3 (4000 - 20 \cdot 102 + 2 S^{\frac{1}{3}})}$

Step 3.2

Factor $2$ out of $4000 - 20 \cdot 102 + 2 S^{\frac{1}{3}}$ .

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Step 3.2.1

Factor $2$ out of $4000$ .

$\frac{S^{\frac{1}{3}}}{3 (2 \cdot 2000 - 20 \cdot 102 + 2 S^{\frac{1}{3}})}$

Step 3.2.2

Factor $2$ out of $- 20 \cdot 102$ .

$\frac{S^{\frac{1}{3}}}{3 (2 \cdot 2000 + 2 (- 10 \cdot 102) + 2 S^{\frac{1}{3}})}$

Step 3.2.3

Factor $2$ out of $2 \cdot 2000 + 2 (- 10 \cdot 102)$ .

$\frac{S^{\frac{1}{3}}}{3 (2 \cdot (2000 - 10 \cdot 102) + 2 S^{\frac{1}{3}})}$

Step 3.2.4

Factor $2$ out of $2 \cdot (2000 - 10 \cdot 102) + 2 S^{\frac{1}{3}}$ .

$\frac{S^{\frac{1}{3}}}{3 (2 (2000 - 10 \cdot 102 + S^{\frac{1}{3}}))}$

Step 3.3

Multiply $- 10$ by $102$ .

$\frac{S^{\frac{1}{3}}}{3 (2 (2000 - 1020 + S^{\frac{1}{3}}))}$

Step 3.4

Subtract $1020$ from $2000$ .

$\frac{S^{\frac{1}{3}}}{3 \cdot 2 (980 + S^{\frac{1}{3}})}$

Step 3.5

Multiply $3$ by $2$ .

$\frac{S^{\frac{1}{3}}}{6 (980 + S^{\frac{1}{3}})}$