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Basic Math Examples
2y2-9y-13y2+4y+3-yy+1+12y+32y2−9y−13y2+4y+3−yy+1+12y+3
Step 1
Step 1.1
Consider the form x2+bx+cx2+bx+c. Find a pair of integers whose product is cc and whose sum is bb. In this case, whose product is 33 and whose sum is 44.
1,31,3
Step 1.2
Write the factored form using these integers.
2y2-9y-13(y+1)(y+3)-yy+1+12y+32y2−9y−13(y+1)(y+3)−yy+1+12y+3
2y2-9y-13(y+1)(y+3)-yy+1+12y+32y2−9y−13(y+1)(y+3)−yy+1+12y+3
Step 2
Step 2.1
Multiply yy+1yy+1 by y+3y+3y+3y+3.
2y2-9y-13(y+1)(y+3)-(yy+1⋅y+3y+3)+12y+32y2−9y−13(y+1)(y+3)−(yy+1⋅y+3y+3)+12y+3
Step 2.2
Multiply yy+1yy+1 by y+3y+3y+3y+3.
2y2-9y-13(y+1)(y+3)-y(y+3)(y+1)(y+3)+12y+32y2−9y−13(y+1)(y+3)−y(y+3)(y+1)(y+3)+12y+3
Step 2.3
Multiply 12y+312y+3 by y+1y+1y+1y+1.
2y2-9y-13(y+1)(y+3)-y(y+3)(y+1)(y+3)+12y+3⋅y+1y+12y2−9y−13(y+1)(y+3)−y(y+3)(y+1)(y+3)+12y+3⋅y+1y+1
Step 2.4
Multiply 12y+312y+3 by y+1y+1y+1y+1.
2y2-9y-13(y+1)(y+3)-y(y+3)(y+1)(y+3)+12(y+1)(y+3)(y+1)2y2−9y−13(y+1)(y+3)−y(y+3)(y+1)(y+3)+12(y+1)(y+3)(y+1)
Step 2.5
Reorder the factors of (y+3)(y+1)(y+3)(y+1).
2y2-9y-13(y+1)(y+3)-y(y+3)(y+1)(y+3)+12(y+1)(y+1)(y+3)2y2−9y−13(y+1)(y+3)−y(y+3)(y+1)(y+3)+12(y+1)(y+1)(y+3)
2y2-9y-13(y+1)(y+3)-y(y+3)(y+1)(y+3)+12(y+1)(y+1)(y+3)2y2−9y−13(y+1)(y+3)−y(y+3)(y+1)(y+3)+12(y+1)(y+1)(y+3)
Step 3
Step 3.1
Combine the numerators over the common denominator.
2y2-9y-13-y(y+3)+12(y+1)(y+1)(y+3)2y2−9y−13−y(y+3)+12(y+1)(y+1)(y+3)
Step 3.2
Simplify each term.
Step 3.2.1
Apply the distributive property.
2y2-9y-13-y⋅y-y⋅3+12(y+1)(y+1)(y+3)2y2−9y−13−y⋅y−y⋅3+12(y+1)(y+1)(y+3)
Step 3.2.2
Multiply yy by yy by adding the exponents.
Step 3.2.2.1
Move yy.
2y2-9y-13-(y⋅y)-y⋅3+12(y+1)(y+1)(y+3)2y2−9y−13−(y⋅y)−y⋅3+12(y+1)(y+1)(y+3)
Step 3.2.2.2
Multiply yy by yy.
2y2-9y-13-y2-y⋅3+12(y+1)(y+1)(y+3)2y2−9y−13−y2−y⋅3+12(y+1)(y+1)(y+3)
2y2-9y-13-y2-y⋅3+12(y+1)(y+1)(y+3)2y2−9y−13−y2−y⋅3+12(y+1)(y+1)(y+3)
Step 3.2.3
Multiply 33 by -1−1.
2y2-9y-13-y2-3y+12(y+1)(y+1)(y+3)2y2−9y−13−y2−3y+12(y+1)(y+1)(y+3)
Step 3.2.4
Apply the distributive property.
2y2-9y-13-y2-3y+12y+12⋅1(y+1)(y+3)2y2−9y−13−y2−3y+12y+12⋅1(y+1)(y+3)
Step 3.2.5
Multiply 1212 by 11.
2y2-9y-13-y2-3y+12y+12(y+1)(y+3)2y2−9y−13−y2−3y+12y+12(y+1)(y+3)
2y2-9y-13-y2-3y+12y+12(y+1)(y+3)2y2−9y−13−y2−3y+12y+12(y+1)(y+3)
Step 3.3
Simplify by adding terms.
Step 3.3.1
Subtract y2y2 from 2y22y2.
y2-9y-13-3y+12y+12(y+1)(y+3)y2−9y−13−3y+12y+12(y+1)(y+3)
Step 3.3.2
Subtract 3y3y from -9y−9y.
y2-12y-13+12y+12(y+1)(y+3)y2−12y−13+12y+12(y+1)(y+3)
Step 3.3.3
Combine the opposite terms in y2-12y-13+12y+12y2−12y−13+12y+12.
Step 3.3.3.1
Add -12y−12y and 12y12y.
y2+0-13+12(y+1)(y+3)y2+0−13+12(y+1)(y+3)
Step 3.3.3.2
Add y2y2 and 00.
y2-13+12(y+1)(y+3)y2−13+12(y+1)(y+3)
y2-13+12(y+1)(y+3)y2−13+12(y+1)(y+3)
Step 3.3.4
Add -13−13 and 1212.
y2-1(y+1)(y+3)y2−1(y+1)(y+3)
y2-1(y+1)(y+3)y2−1(y+1)(y+3)
y2-1(y+1)(y+3)y2−1(y+1)(y+3)
Step 4
Step 4.1
Rewrite 11 as 1212.
y2-12(y+1)(y+3)y2−12(y+1)(y+3)
Step 4.2
Since both terms are perfect squares, factor using the difference of squares formula, a2-b2=(a+b)(a-b)a2−b2=(a+b)(a−b) where a=ya=y and b=1b=1.
(y+1)(y-1)(y+1)(y+3)(y+1)(y−1)(y+1)(y+3)
(y+1)(y-1)(y+1)(y+3)(y+1)(y−1)(y+1)(y+3)
Step 5
Step 5.1
Cancel the common factor.
(y+1)(y-1)(y+1)(y+3)
Step 5.2
Rewrite the expression.
y-1y+3
y-1y+3