Basic Math Examples



\begin{matrix} r = & 2 \end{matrix}

$\begin{array}{r} r = & 2 \end{array}$

Step 1

The volume of a sphere is equal to

\frac{4}{3}

$\frac{4}{3}$ times Pi

π

$π$ times the radius cubed.

\frac{4}{3} \cdot π \cdot {(r a d i u s)}^{3}

$\frac{4}{3} \cdot π \cdot {(r a d i u s)}^{3}$

Step 2

Substitute the value of the radius

r = 2

$r = 2$ into the formula to find the volume of the sphere. Pi

π

$π$ is approximately equal to

3.14

$3.14$ .

\frac{4}{3} \cdot π \cdot 2^{3}

$\frac{4}{3} \cdot π \cdot 2^{3}$

Step 3

Combine

\frac{4}{3}

$\frac{4}{3}$ and

π

$π$ .

\frac{4 π}{3} \cdot 2^{3}

$\frac{4 π}{3} \cdot 2^{3}$

Step 4

Raise

2

$2$ to the power of

3

$3$ .

\frac{4 π}{3} \cdot 8

$\frac{4 π}{3} \cdot 8$

Step 5

Multiply

\frac{4 π}{3} \cdot 8

$\frac{4 π}{3} \cdot 8$ .

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Step 5.1

Combine

\frac{4 π}{3}

$\frac{4 π}{3}$ and

8

$8$ .

\frac{4 π \cdot 8}{3}

$\frac{4 π \cdot 8}{3}$

Step 5.2

Multiply

8

$8$ by

4

$4$ .

\frac{32 π}{3}

$\frac{32 π}{3}$

\frac{32 π}{3}

$\frac{32 π}{3}$

Step 6

The result can be shown in multiple forms.

Exact Form:

\frac{32 π}{3}

$\frac{32 π}{3}$

Decimal Form:

33.51032163 \dots

$33.51032163 \dots$

 $\begin{array}{r} r = & 2 \end{array}$

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⎡ ⎢ ⎣ \begin{matrix} x^{2} & \frac{1}{2} \sqrt{π} & \int x d x \end{matrix} ⎤ ⎥ ⎦

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$