Basic Math Examples

$\frac{3 z^{2} - 2 z - 5}{z^{2} + 6 z + 5} \div \frac{10 z^{2} \cdot (9 z) - 9}{2 z^{2} + 13 z + 15}$

Step 1

To divide by a fraction, multiply by its reciprocal.

$\frac{3 z^{2} - 2 z - 5}{z^{2} + 6 z + 5} \cdot \frac{2 z^{2} + 13 z + 15}{10 z^{2} \cdot (9 z) - 9}$

Step 2

Factor by grouping.

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Step 2.1

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 3 \cdot - 5 = - 15$ and whose sum is $b = - 2$ .

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Step 2.1.1

Factor $- 2$ out of $- 2 z$ .

$\frac{3 z^{2} - 2 (z) - 5}{z^{2} + 6 z + 5} \cdot \frac{2 z^{2} + 13 z + 15}{10 z^{2} \cdot (9 z) - 9}$

Step 2.1.2

Rewrite $- 2$ as $3$ plus $- 5$

$\frac{3 z^{2} + (3 - 5) z - 5}{z^{2} + 6 z + 5} \cdot \frac{2 z^{2} + 13 z + 15}{10 z^{2} \cdot (9 z) - 9}$

Step 2.1.3

Apply the distributive property.

$\frac{3 z^{2} + 3 z - 5 z - 5}{z^{2} + 6 z + 5} \cdot \frac{2 z^{2} + 13 z + 15}{10 z^{2} \cdot (9 z) - 9}$

Step 2.2

Factor out the greatest common factor from each group.

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Step 2.2.1

Group the first two terms and the last two terms.

$\frac{(3 z^{2} + 3 z) - 5 z - 5}{z^{2} + 6 z + 5} \cdot \frac{2 z^{2} + 13 z + 15}{10 z^{2} \cdot (9 z) - 9}$

Step 2.2.2

Factor out the greatest common factor (GCF) from each group.

$\frac{3 z (z + 1) - 5 (z + 1)}{z^{2} + 6 z + 5} \cdot \frac{2 z^{2} + 13 z + 15}{10 z^{2} \cdot (9 z) - 9}$

Step 2.3

Factor the polynomial by factoring out the greatest common factor, $z + 1$ .

$\frac{(z + 1) (3 z - 5)}{z^{2} + 6 z + 5} \cdot \frac{2 z^{2} + 13 z + 15}{10 z^{2} \cdot (9 z) - 9}$

Step 3

Factor $z^{2} + 6 z + 5$ using the AC method.

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Step 3.1

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $5$ and whose sum is $6$ .

$1, 5$

Step 3.2

Write the factored form using these integers.

$\frac{(z + 1) (3 z - 5)}{(z + 1) (z + 5)} \cdot \frac{2 z^{2} + 13 z + 15}{10 z^{2} \cdot (9 z) - 9}$

Step 4

Cancel the common factor of $z + 1$ .

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Step 4.1

Cancel the common factor.

$\frac{(z + 1) (3 z - 5)}{(z + 1) (z + 5)} \cdot \frac{2 z^{2} + 13 z + 15}{10 z^{2} \cdot (9 z) - 9}$

Step 4.2

Rewrite the expression.

$\frac{3 z - 5}{z + 5} \cdot \frac{2 z^{2} + 13 z + 15}{10 z^{2} \cdot (9 z) - 9}$

Step 5

Factor by grouping.

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Step 5.1

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 2 \cdot 15 = 30$ and whose sum is $b = 13$ .

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Step 5.1.1

Factor $13$ out of $13 z$ .

$\frac{3 z - 5}{z + 5} \cdot \frac{2 z^{2} + 13 (z) + 15}{10 z^{2} \cdot (9 z) - 9}$

Step 5.1.2

Rewrite $13$ as $3$ plus $10$

$\frac{3 z - 5}{z + 5} \cdot \frac{2 z^{2} + (3 + 10) z + 15}{10 z^{2} \cdot (9 z) - 9}$

Step 5.1.3

Apply the distributive property.

$\frac{3 z - 5}{z + 5} \cdot \frac{2 z^{2} + 3 z + 10 z + 15}{10 z^{2} \cdot (9 z) - 9}$

Step 5.2

Factor out the greatest common factor from each group.

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Step 5.2.1

Group the first two terms and the last two terms.

$\frac{3 z - 5}{z + 5} \cdot \frac{(2 z^{2} + 3 z) + 10 z + 15}{10 z^{2} \cdot (9 z) - 9}$

Step 5.2.2

Factor out the greatest common factor (GCF) from each group.

$\frac{3 z - 5}{z + 5} \cdot \frac{z (2 z + 3) + 5 (2 z + 3)}{10 z^{2} \cdot (9 z) - 9}$

Step 5.3

Factor the polynomial by factoring out the greatest common factor, $2 z + 3$ .

$\frac{3 z - 5}{z + 5} \cdot \frac{(2 z + 3) (z + 5)}{10 z^{2} \cdot (9 z) - 9}$

Step 6

Simplify the denominator.

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Step 6.1

Factor $9$ out of $10 z^{2} \cdot (9 z) - 9$ .

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Step 6.1.1

Factor $9$ out of $10 z^{2} \cdot (9 z)$ .

$\frac{3 z - 5}{z + 5} \cdot \frac{(2 z + 3) (z + 5)}{9 (10 z^{2} \cdot (z)) - 9}$

Step 6.1.2

Factor $9$ out of $- 9$ .

$\frac{3 z - 5}{z + 5} \cdot \frac{(2 z + 3) (z + 5)}{9 (10 z^{2} \cdot (z)) + 9 (- 1)}$

Step 6.1.3

Factor $9$ out of $9 (10 z^{2} \cdot (z)) + 9 (- 1)$ .

$\frac{3 z - 5}{z + 5} \cdot \frac{(2 z + 3) (z + 5)}{9 (10 z^{2} \cdot (z) - 1)}$

Step 6.2

Multiply $z^{2}$ by $z$ by adding the exponents.

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Step 6.2.1

Move $z$ .

$\frac{3 z - 5}{z + 5} \cdot \frac{(2 z + 3) (z + 5)}{9 (10 (z \cdot z^{2}) - 1)}$

Step 6.2.2

Multiply $z$ by $z^{2}$ .

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Step 6.2.2.1

Raise $z$ to the power of $1$ .

$\frac{3 z - 5}{z + 5} \cdot \frac{(2 z + 3) (z + 5)}{9 (10 (z^{1} z^{2}) - 1)}$

Step 6.2.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{3 z - 5}{z + 5} \cdot \frac{(2 z + 3) (z + 5)}{9 (10 z^{1 + 2} - 1)}$

Step 6.2.3

Add $1$ and $2$ .

$\frac{3 z - 5}{z + 5} \cdot \frac{(2 z + 3) (z + 5)}{9 (10 z^{3} - 1)}$

Step 7

Simplify terms.

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Step 7.1

Cancel the common factor of $z + 5$ .

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Step 7.1.1

Factor $z + 5$ out of $(2 z + 3) (z + 5)$ .

$\frac{3 z - 5}{z + 5} \cdot \frac{(z + 5) (2 z + 3)}{9 (10 z^{3} - 1)}$

Step 7.1.2

Cancel the common factor.

$\frac{3 z - 5}{z + 5} \cdot \frac{(z + 5) (2 z + 3)}{9 (10 z^{3} - 1)}$

Step 7.1.3

Rewrite the expression.

$(3 z - 5) \frac{2 z + 3}{9 (10 z^{3} - 1)}$

Step 7.2

Multiply $3 z - 5$ by $\frac{2 z + 3}{9 (10 z^{3} - 1)}$ .

$\frac{(3 z - 5) (2 z + 3)}{9 (10 z^{3} - 1)}$