Basic Math Examples

Simplify 2y^2-y=6
2y2-y=62y2y=6
Step 1
Subtract 6 from both sides of the equation.
2y2-y-6=0
Step 2
Factor by grouping.
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Step 2.1
For a polynomial of the form ax2+bx+c, rewrite the middle term as a sum of two terms whose product is ac=2-6=-12 and whose sum is b=-1.
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Step 2.1.1
Factor -1 out of -y.
2y2-(y)-6=0
Step 2.1.2
Rewrite -1 as 3 plus -4
2y2+(3-4)y-6=0
Step 2.1.3
Apply the distributive property.
2y2+3y-4y-6=0
2y2+3y-4y-6=0
Step 2.2
Factor out the greatest common factor from each group.
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Step 2.2.1
Group the first two terms and the last two terms.
(2y2+3y)-4y-6=0
Step 2.2.2
Factor out the greatest common factor (GCF) from each group.
y(2y+3)-2(2y+3)=0
y(2y+3)-2(2y+3)=0
Step 2.3
Factor the polynomial by factoring out the greatest common factor, 2y+3.
(2y+3)(y-2)=0
(2y+3)(y-2)=0
Step 3
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
2y+3=0
y-2=0
Step 4
Set 2y+3 equal to 0 and solve for y.
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Step 4.1
Set 2y+3 equal to 0.
2y+3=0
Step 4.2
Solve 2y+3=0 for y.
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Step 4.2.1
Subtract 3 from both sides of the equation.
2y=-3
Step 4.2.2
Divide each term in 2y=-3 by 2 and simplify.
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Step 4.2.2.1
Divide each term in 2y=-3 by 2.
2y2=-32
Step 4.2.2.2
Simplify the left side.
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Step 4.2.2.2.1
Cancel the common factor of 2.
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Step 4.2.2.2.1.1
Cancel the common factor.
2y2=-32
Step 4.2.2.2.1.2
Divide y by 1.
y=-32
y=-32
y=-32
Step 4.2.2.3
Simplify the right side.
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Step 4.2.2.3.1
Move the negative in front of the fraction.
y=-32
y=-32
y=-32
y=-32
y=-32
Step 5
Set y-2 equal to 0 and solve for y.
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Step 5.1
Set y-2 equal to 0.
y-2=0
Step 5.2
Add 2 to both sides of the equation.
y=2
y=2
Step 6
The final solution is all the values that make (2y+3)(y-2)=0 true.
y=-32,2
Step 7
The result can be shown in multiple forms.
Exact Form:
y=-32,2
Decimal Form:
y=-1.5,2
Mixed Number Form:
y=-112,2
 [x2  12  π  xdx ]