Basic Math Examples

- 2.5 n (1 - 2 n) - 1.5 n

$- 2.5 n (1 - 2 n) - 1.5 n$

Step 1

Simplify each term.

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Step 1.1

Apply the distributive property.

- 2.5 n \cdot 1 - 2.5 n (- 2 n) - 1.5 n

$- 2.5 n \cdot 1 - 2.5 n (- 2 n) - 1.5 n$

Step 1.2

Multiply

- 2.5

$- 2.5$ by

1

$1$ .

- 2.5 n - 2.5 n (- 2 n) - 1.5 n

$- 2.5 n - 2.5 n (- 2 n) - 1.5 n$

Step 1.3

Rewrite using the commutative property of multiplication.

- 2.5 n - 2.5 \cdot - 2 n \cdot n - 1.5 n

$- 2.5 n - 2.5 \cdot - 2 n \cdot n - 1.5 n$

Step 1.4

Simplify each term.

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Step 1.4.1

Multiply

n

$n$ by

n

$n$ by adding the exponents.

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Step 1.4.1.1

Move

n

$n$ .

- 2.5 n - 2.5 \cdot - 2 (n \cdot n) - 1.5 n

$- 2.5 n - 2.5 \cdot - 2 (n \cdot n) - 1.5 n$

Step 1.4.1.2

Multiply

n

$n$ by

n

$n$ .

- 2.5 n - 2.5 \cdot - 2 n^{2} - 1.5 n

$- 2.5 n - 2.5 \cdot - 2 n^{2} - 1.5 n$

- 2.5 n - 2.5 \cdot - 2 n^{2} - 1.5 n

$- 2.5 n - 2.5 \cdot - 2 n^{2} - 1.5 n$

Step 1.4.2

Multiply

- 2.5

$- 2.5$ by

- 2

$- 2$ .

- 2.5 n + 5 n^{2} - 1.5 n

$- 2.5 n + 5 n^{2} - 1.5 n$

- 2.5 n + 5 n^{2} - 1.5 n

$- 2.5 n + 5 n^{2} - 1.5 n$

- 2.5 n + 5 n^{2} - 1.5 n

$- 2.5 n + 5 n^{2} - 1.5 n$

Step 2

Subtract

1.5 n

$1.5 n$ from

- 2.5 n

$- 2.5 n$ .

5 n^{2} - 4 n

$5 n^{2} - 4 n$

[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$