Basic Math Examples

- 2 \frac{3}{8} \cdot \frac{8}{5}

$- 2 \frac{3}{8} \cdot \frac{8}{5}$

Step 1

Convert

2 \frac{3}{8}

$2 \frac{3}{8}$ to an improper fraction.

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Step 1.1

A mixed number is an addition of its whole and fractional parts.

- (2 + \frac{3}{8}) \cdot \frac{8}{5}

$- (2 + \frac{3}{8}) \cdot \frac{8}{5}$

Step 1.2

Add

2

$2$ and

\frac{3}{8}

$\frac{3}{8}$ .

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Step 1.2.1

To write

2

$2$ as a fraction with a common denominator, multiply by

\frac{8}{8}

$\frac{8}{8}$ .

- (2 \cdot \frac{8}{8} + \frac{3}{8}) \cdot \frac{8}{5}

$- (2 \cdot \frac{8}{8} + \frac{3}{8}) \cdot \frac{8}{5}$

Step 1.2.2

Combine

2

$2$ and

\frac{8}{8}

$\frac{8}{8}$ .

- (\frac{2 \cdot 8}{8} + \frac{3}{8}) \cdot \frac{8}{5}

$- (\frac{2 \cdot 8}{8} + \frac{3}{8}) \cdot \frac{8}{5}$

Step 1.2.3

Combine the numerators over the common denominator.

- \frac{2 \cdot 8 + 3}{8} \cdot \frac{8}{5}

$- \frac{2 \cdot 8 + 3}{8} \cdot \frac{8}{5}$

Step 1.2.4

Simplify the numerator.

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Step 1.2.4.1

Multiply

2

$2$ by

8

$8$ .

- \frac{16 + 3}{8} \cdot \frac{8}{5}

$- \frac{16 + 3}{8} \cdot \frac{8}{5}$

Step 1.2.4.2

Add

16

$16$ and

3

$3$ .

- \frac{19}{8} \cdot \frac{8}{5}

$- \frac{19}{8} \cdot \frac{8}{5}$

- \frac{19}{8} \cdot \frac{8}{5}

$- \frac{19}{8} \cdot \frac{8}{5}$

- \frac{19}{8} \cdot \frac{8}{5}

$- \frac{19}{8} \cdot \frac{8}{5}$

- \frac{19}{8} \cdot \frac{8}{5}

$- \frac{19}{8} \cdot \frac{8}{5}$

Step 2

Cancel the common factor of

8

$8$ .

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Step 2.1

Move the leading negative in

- \frac{19}{8}

$- \frac{19}{8}$ into the numerator.

\frac{- 19}{8} \cdot \frac{8}{5}

$\frac{- 19}{8} \cdot \frac{8}{5}$

Step 2.2

Cancel the common factor.

$\frac{- 19}{8} \cdot \frac{8}{5}$

Step 2.3

Rewrite the expression.

$- 19 \cdot \frac{1}{5}$

Step 3

Combine

$- 19$ and

$\frac{1}{5}$ .

$\frac{- 19}{5}$

Step 4

Move the negative in front of the fraction.

$- \frac{19}{5}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$- \frac{19}{5}$

Decimal Form:

$- 3.8$

Mixed Number Form:

$- 3 \frac{4}{5}$