Basic Math Examples

$\frac{m}{9} \cdot 15 - 47 = 28$

Step 1

Simplify each term.

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Step 1.1

Cancel the common factor of $3$ .

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Step 1.1.1

Factor $3$ out of $9$ .

$\frac{m}{3 (3)} \cdot 15 - 47 = 28$

Step 1.1.2

Factor $3$ out of $15$ .

$\frac{m}{3 \cdot 3} \cdot (3 \cdot 5) - 47 = 28$

Step 1.1.3

Cancel the common factor.

$\frac{m}{3 \cdot 3} \cdot (3 \cdot 5) - 47 = 28$

Step 1.1.4

Rewrite the expression.

$\frac{m}{3} \cdot 5 - 47 = 28$

Step 1.2

Combine $\frac{m}{3}$ and $5$ .

$\frac{m \cdot 5}{3} - 47 = 28$

Step 1.3

Move $5$ to the left of $m$ .

$\frac{5 m}{3} - 47 = 28$

Step 2

Move all terms not containing $m$ to the right side of the equation.

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Step 2.1

Add $47$ to both sides of the equation.

$\frac{5 m}{3} = 28 + 47$

Step 2.2

Add $28$ and $47$ .

$\frac{5 m}{3} = 75$

Step 3

Multiply both sides of the equation by $\frac{3}{5}$ .

$\frac{3}{5} \cdot \frac{5 m}{3} = \frac{3}{5} \cdot 75$

Step 4

Simplify both sides of the equation.

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Step 4.1

Simplify the left side.

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Step 4.1.1

Simplify $\frac{3}{5} \cdot \frac{5 m}{3}$ .

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Step 4.1.1.1

Cancel the common factor of $3$ .

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Step 4.1.1.1.1

Cancel the common factor.

$\frac{3}{5} \cdot \frac{5 m}{3} = \frac{3}{5} \cdot 75$

Step 4.1.1.1.2

Rewrite the expression.

$\frac{1}{5} (5 m) = \frac{3}{5} \cdot 75$

Step 4.1.1.2

Cancel the common factor of $5$ .

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Step 4.1.1.2.1

Factor $5$ out of $5 m$ .

$\frac{1}{5} (5 (m)) = \frac{3}{5} \cdot 75$

Step 4.1.1.2.2

Cancel the common factor.

$\frac{1}{5} (5 m) = \frac{3}{5} \cdot 75$

Step 4.1.1.2.3

Rewrite the expression.

$m = \frac{3}{5} \cdot 75$

Step 4.2

Simplify the right side.

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Step 4.2.1

Simplify $\frac{3}{5} \cdot 75$ .

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Step 4.2.1.1

Cancel the common factor of $5$ .

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Step 4.2.1.1.1

Factor $5$ out of $75$ .

$m = \frac{3}{5} \cdot (5 (15))$

Step 4.2.1.1.2

Cancel the common factor.

$m = \frac{3}{5} \cdot (5 \cdot 15)$

Step 4.2.1.1.3

Rewrite the expression.

$m = 3 \cdot 15$

Step 4.2.1.2

Multiply $3$ by $15$ .

$m = 45$