Basic Math Examples

$\sqrt{16 d} + \sqrt{d^{9}}$

Step 1

Rewrite $16 d$ as ${(2^{2})}^{2} d$ .

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Step 1.1

Rewrite $16$ as $4^{2}$ .

$\sqrt{4^{2} d} + \sqrt{d^{9}}$

Step 1.2

Rewrite $4$ as $2^{2}$ .

$\sqrt{{(2^{2})}^{2} d} + \sqrt{d^{9}}$

$\sqrt{{(2^{2})}^{2} d} + \sqrt{d^{9}}$

Step 2

Pull terms out from under the radical.

$2^{2} \sqrt{d} + \sqrt{d^{9}}$

Step 3

Raise $2$ to the power of $2$ .

$4 \sqrt{d} + \sqrt{d^{9}}$

Step 4

Rewrite $d^{9}$ as ${(d^{4})}^{2} d$ .

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Step 4.1

Factor out $d^{8}$ .

$4 \sqrt{d} + \sqrt{d^{8} d}$

Step 4.2

Rewrite $d^{8}$ as ${(d^{4})}^{2}$ .

$4 \sqrt{d} + \sqrt{{(d^{4})}^{2} d}$

$4 \sqrt{d} + \sqrt{{(d^{4})}^{2} d}$

Step 5

Pull terms out from under the radical.

$4 \sqrt{d} + d^{4} \sqrt{d}$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$