Basic Math Examples

$15 \cdot 1.5 + 2 \cdot 3 \cdot 4.5 - y \cdot 6 = 0$

Step 1

Simplify $15 \cdot 1.5 + 2 \cdot 3 \cdot 4.5 - y \cdot 6$ .

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Step 1.1

Simplify each term.

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Step 1.1.1

Multiply $15$ by $1.5$ .

$22.5 + 2 \cdot 3 \cdot 4.5 - y \cdot 6 = 0$

Step 1.1.2

Multiply $2 \cdot 3 \cdot 4.5$ .

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Step 1.1.2.1

Multiply $2$ by $3$ .

$22.5 + 6 \cdot 4.5 - y \cdot 6 = 0$

Step 1.1.2.2

Multiply $6$ by $4.5$ .

$22.5 + 27 - y \cdot 6 = 0$

Step 1.1.3

Multiply $6$ by $- 1$ .

$22.5 + 27 - 6 y = 0$

Step 1.2

Add $22.5$ and $27$ .

$49.5 - 6 y = 0$

Step 2

Subtract $49.5$ from both sides of the equation.

$- 6 y = - 49.5$

Step 3

Divide each term in $- 6 y = - 49.5$ by $- 6$ and simplify.

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Step 3.1

Divide each term in $- 6 y = - 49.5$ by $- 6$ .

$\frac{- 6 y}{- 6} = \frac{- 49.5}{- 6}$

Step 3.2

Simplify the left side.

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Step 3.2.1

Cancel the common factor of $- 6$ .

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Step 3.2.1.1

Cancel the common factor.

$\frac{- 6 y}{- 6} = \frac{- 49.5}{- 6}$

Step 3.2.1.2

Divide $y$ by $1$ .

$y = \frac{- 49.5}{- 6}$

Step 3.3

Simplify the right side.

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Step 3.3.1

Divide $- 49.5$ by $- 6$ .

$y = 8.25$