Basic Math Examples

$- 3 | 2 r - 1 | = 15$

Step 1

Divide each term in $- 3 | 2 r - 1 | = 15$ by $- 3$ and simplify.

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Step 1.1

Divide each term in $- 3 | 2 r - 1 | = 15$ by $- 3$ .

$\frac{- 3 | 2 r - 1 |}{- 3} = \frac{15}{- 3}$

Step 1.2

Simplify the left side.

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Step 1.2.1

Cancel the common factor of $- 3$ .

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Step 1.2.1.1

Cancel the common factor.

$\frac{- 3 | 2 r - 1 |}{- 3} = \frac{15}{- 3}$

Step 1.2.1.2

Divide $| 2 r - 1 |$ by $1$ .

$| 2 r - 1 | = \frac{15}{- 3}$

Step 1.3

Simplify the right side.

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Step 1.3.1

Divide $15$ by $- 3$ .

$| 2 r - 1 | = - 5$

Step 2

There is no value of $r$ that makes the equation be true since an absolute value can never be negative.

No solution