Basic Math Examples

- 3 | 2 r - 1 | = 15

$- 3 | 2 r - 1 | = 15$

Step 1

Divide each term in

- 3 | 2 r - 1 | = 15

$- 3 | 2 r - 1 | = 15$ by

- 3

$- 3$ and simplify.

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Step 1.1

Divide each term in

- 3 | 2 r - 1 | = 15

$- 3 | 2 r - 1 | = 15$ by

- 3

$- 3$ .

\frac{- 3 | 2 r - 1 |}{- 3} = \frac{15}{- 3}

$\frac{- 3 | 2 r - 1 |}{- 3} = \frac{15}{- 3}$

Step 1.2

Simplify the left side.

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Step 1.2.1

Cancel the common factor of

- 3

$- 3$ .

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Step 1.2.1.1

Cancel the common factor.

$\frac{- 3 | 2 r - 1 |}{- 3} = \frac{15}{- 3}$

Step 1.2.1.2

Divide

$| 2 r - 1 |$ by

$1$ .

$| 2 r - 1 | = \frac{15}{- 3}$

Step 1.3

Simplify the right side.

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Step 1.3.1

Divide

$15$ by

$- 3$ .

$| 2 r - 1 | = - 5$

Step 2

There is no value of

$r$ that makes the equation be true since an absolute value can never be negative.

No solution