Basic Math Examples

Solve for a 60÷a+38=48
60÷a+38=4860÷a+38=48
Step 1
Rewrite the division as a fraction.
60a+38=4860a+38=48
Step 2
Move all terms not containing aa to the right side of the equation.
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Step 2.1
Subtract 3838 from both sides of the equation.
60a=48-3860a=4838
Step 2.2
Subtract 3838 from 4848.
60a=1060a=10
60a=1060a=10
Step 3
Find the LCD of the terms in the equation.
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Step 3.1
Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.
a,1a,1
Step 3.2
The LCM of one and any expression is the expression.
aa
aa
Step 4
Multiply each term in 60a=1060a=10 by aa to eliminate the fractions.
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Step 4.1
Multiply each term in 60a=1060a=10 by aa.
60aa=10a60aa=10a
Step 4.2
Simplify the left side.
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Step 4.2.1
Cancel the common factor of aa.
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Step 4.2.1.1
Cancel the common factor.
60aa=10a
Step 4.2.1.2
Rewrite the expression.
60=10a
60=10a
60=10a
60=10a
Step 5
Solve the equation.
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Step 5.1
Rewrite the equation as 10a=60.
10a=60
Step 5.2
Divide each term in 10a=60 by 10 and simplify.
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Step 5.2.1
Divide each term in 10a=60 by 10.
10a10=6010
Step 5.2.2
Simplify the left side.
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Step 5.2.2.1
Cancel the common factor of 10.
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Step 5.2.2.1.1
Cancel the common factor.
10a10=6010
Step 5.2.2.1.2
Divide a by 1.
a=6010
a=6010
a=6010
Step 5.2.3
Simplify the right side.
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Step 5.2.3.1
Divide 60 by 10.
a=6
a=6
a=6
a=6
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