Basic Math Examples

$(| - 14 \cdot - 6 - 77 | + 9) \div 2 {(- 9 + \sqrt{49})}^{3}$

Step 1

Simplify the numerator.

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Step 1.1

Multiply $- 14$ by $- 6$ .

$(| 84 - 77 | + 9) \div 2 {(- 9 + \sqrt{49})}^{3}$

Step 1.2

Subtract $77$ from $84$ .

$(| 7 | + 9) \div 2 {(- 9 + \sqrt{49})}^{3}$

Step 1.3

The absolute value is the distance between a number and zero. The distance between $0$ and $7$ is $7$ .

$(7 + 9) \div 2 {(- 9 + \sqrt{49})}^{3}$

Step 1.4

Add $7$ and $9$ .

$16 \div 2 {(- 9 + \sqrt{49})}^{3}$

Step 2

Simplify terms.

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Step 2.1

Divide $16$ by $2$ .

$8 {(- 9 + \sqrt{49})}^{3}$

Step 2.2

Simplify each term.

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Step 2.2.1

Rewrite $49$ as $7^{2}$ .

$8 {(- 9 + \sqrt{7^{2}})}^{3}$

Step 2.2.2

Pull terms out from under the radical, assuming positive real numbers.

$8 {(- 9 + 7)}^{3}$

Step 2.3

Simplify the expression.

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Step 2.3.1

Add $- 9$ and $7$ .

$8 {(- 2)}^{3}$

Step 2.3.2

Raise $- 2$ to the power of $3$ .

$8 \cdot - 8$

Step 2.3.3

Multiply $8$ by $- 8$ .

$- 64$