Basic Math Examples

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\begin{matrix} h = & 10 r = & 5 \end{matrix}

$\begin{array}{r} h = & 10 \\ r = & 5 \end{array}$

Step 1

The volume of a cone is equal to

\frac{1}{3}

$\frac{1}{3}$ times the area of the base

π r^{2}

$π r^{2}$ times the height

h

$h$ .

\frac{1}{3} \cdot π \cdot {(r a d i u s)}^{2} \cdot (h e i g h t)

$\frac{1}{3} \cdot π \cdot {(r a d i u s)}^{2} \cdot (h e i g h t)$

Step 2

Substitute the values of the radius

r = 5

$r = 5$ and height

h = 10

$h = 10$ into the formula to find the volume of the cone. Pi

π

$π$ is approximately equal to

3.14

$3.14$ .

\frac{1}{3} \cdot π \cdot 5^{2} \cdot 10

$\frac{1}{3} \cdot π \cdot 5^{2} \cdot 10$

Step 3

Combine

\frac{1}{3}

$\frac{1}{3}$ and

π

$π$ .

\frac{π}{3} \cdot 5^{2} \cdot 10

$\frac{π}{3} \cdot 5^{2} \cdot 10$

Step 4

Raise

5

$5$ to the power of

2

$2$ .

\frac{π}{3} \cdot 25 \cdot 10

$\frac{π}{3} \cdot 25 \cdot 10$

Step 5

Combine

\frac{π}{3}

$\frac{π}{3}$ and

25

$25$ .

\frac{π \cdot 25}{3} \cdot 10

$\frac{π \cdot 25}{3} \cdot 10$

Step 6

Move

25

$25$ to the left of

π

$π$ .

\frac{25 \cdot π}{3} \cdot 10

$\frac{25 \cdot π}{3} \cdot 10$

Step 7

Multiply

\frac{25 π}{3} \cdot 10

$\frac{25 π}{3} \cdot 10$ .

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Step 7.1

Combine

\frac{25 π}{3}

$\frac{25 π}{3}$ and

10

$10$ .

\frac{25 π \cdot 10}{3}

$\frac{25 π \cdot 10}{3}$

Step 7.2

Multiply

10

$10$ by

25

$25$ .

\frac{250 π}{3}

$\frac{250 π}{3}$

\frac{250 π}{3}

$\frac{250 π}{3}$

Step 8

The result can be shown in multiple forms.

Exact Form:

\frac{250 π}{3}

$\frac{250 π}{3}$

Decimal Form:

261.79938779 \dots

$261.79938779 \dots$