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Solve for y y=4(2)-3

$y = 4 (2) - 3$

Step 1

Multiply $4$ by $2$ .

$y = 8 - 3$

Step 2

Subtract $3$ from $8$ .

$y = 5$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$

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