Basic Math Examples

7 = (\frac{16}{81}) \cdot {(9)}^{2} \cdot h

$7 = (\frac{16}{81}) \cdot {(9)}^{2} \cdot h$

Step 1

Rewrite the equation as

\frac{16}{81} \cdot 9^{2} \cdot h = 7

$\frac{16}{81} \cdot 9^{2} \cdot h = 7$ .

\frac{16}{81} \cdot 9^{2} \cdot h = 7

$\frac{16}{81} \cdot 9^{2} \cdot h = 7$

Step 2

Simplify.

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Step 2.1

Raise

9

$9$ to the power of

2

$2$ .

\frac{16}{81} \cdot 81 \cdot h = 7

$\frac{16}{81} \cdot 81 \cdot h = 7$

Step 2.2

Cancel the common factor of

81

$81$ .

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Step 2.2.1

Cancel the common factor.

$\frac{16}{81} \cdot 81 \cdot h = 7$

Step 2.2.2

Rewrite the expression.

$16 \cdot h = 7$

$16 \cdot h = 7$

$16 \cdot h = 7$

Step 3

Divide each term in

$16 \cdot h = 7$ by

$16$ and simplify.

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Step 3.1

Divide each term in

$16 \cdot h = 7$ by

$16$ .

$\frac{16 \cdot h}{16} = \frac{7}{16}$

Step 3.2

Simplify the left side.

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Step 3.2.1

Cancel the common factor of

$16$ .

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Step 3.2.1.1

Cancel the common factor.

$\frac{16 \cdot h}{16} = \frac{7}{16}$

Step 3.2.1.2

Divide

$h$ by

$1$ .

$h = \frac{7}{16}$

$h = \frac{7}{16}$

$h = \frac{7}{16}$

$h = \frac{7}{16}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$h = \frac{7}{16}$

Decimal Form:

$h = 0.4375$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$