Basic Math Examples

$- 2 (j - 3) = - 2 j + 6$

Step 1

Simplify $- 2 (j - 3)$ .

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Step 1.1

Rewrite.

$0 + 0 - 2 (j - 3) = - 2 j + 6$

Step 1.2

Simplify by adding zeros.

$- 2 (j - 3) = - 2 j + 6$

Step 1.3

Apply the distributive property.

$- 2 j - 2 \cdot - 3 = - 2 j + 6$

Step 1.4

Multiply $- 2$ by $- 3$ .

$- 2 j + 6 = - 2 j + 6$

Step 2

Move all terms containing $j$ to the left side of the equation.

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Step 2.1

Add $2 j$ to both sides of the equation.

$- 2 j + 6 + 2 j = 6$

Step 2.2

Combine the opposite terms in $- 2 j + 6 + 2 j$ .

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Step 2.2.1

Add $- 2 j$ and $2 j$ .

$0 + 6 = 6$

Step 2.2.2

Add $0$ and $6$ .

$6 = 6$

Step 3

Since $6 = 6$ , the equation will always be true for any value of $j$ .

All real numbers

Step 4

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$