Basic Math Examples

120 = 4 \cdot 6 \cdot 4 + 2 \cdot 4 \cdot h

$120 = 4 \cdot 6 \cdot 4 + 2 \cdot 4 \cdot h$

Step 1

Rewrite the equation as

4 \cdot 6 \cdot 4 + 2 \cdot 4 \cdot h = 120

$4 \cdot 6 \cdot 4 + 2 \cdot 4 \cdot h = 120$ .

4 \cdot 6 \cdot 4 + 2 \cdot 4 \cdot h = 120

$4 \cdot 6 \cdot 4 + 2 \cdot 4 \cdot h = 120$

Step 2

Simplify each term.

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Step 2.1

Multiply

4 \cdot 6 \cdot 4

$4 \cdot 6 \cdot 4$ .

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Step 2.1.1

Multiply

4

$4$ by

6

$6$ .

24 \cdot 4 + 2 \cdot 4 \cdot h = 120

$24 \cdot 4 + 2 \cdot 4 \cdot h = 120$

Step 2.1.2

Multiply

24

$24$ by

4

$4$ .

96 + 2 \cdot 4 \cdot h = 120

$96 + 2 \cdot 4 \cdot h = 120$

96 + 2 \cdot 4 \cdot h = 120

$96 + 2 \cdot 4 \cdot h = 120$

Step 2.2

Multiply

2

$2$ by

4

$4$ .

96 + 8 h = 120

$96 + 8 h = 120$

96 + 8 h = 120

$96 + 8 h = 120$

Step 3

Move all terms not containing

h

$h$ to the right side of the equation.

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Step 3.1

Subtract

96

$96$ from both sides of the equation.

8 h = 120 - 96

$8 h = 120 - 96$

Step 3.2

Subtract

96

$96$ from

120

$120$ .

8 h = 24

$8 h = 24$

8 h = 24

$8 h = 24$

Step 4

Divide each term in

8 h = 24

$8 h = 24$ by

8

$8$ and simplify.

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Step 4.1

Divide each term in

8 h = 24

$8 h = 24$ by

8

$8$ .

\frac{8 h}{8} = \frac{24}{8}

$\frac{8 h}{8} = \frac{24}{8}$

Step 4.2

Simplify the left side.

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Step 4.2.1

Cancel the common factor of

8

$8$ .

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Step 4.2.1.1

Cancel the common factor.

$\frac{8 h}{8} = \frac{24}{8}$

Step 4.2.1.2

Divide

$h$ by

$1$ .

$h = \frac{24}{8}$

$h = \frac{24}{8}$

$h = \frac{24}{8}$

Step 4.3

Simplify the right side.

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Step 4.3.1

Divide

$24$ by

$8$ .

$h = 3$

$h = 3$

$h = 3$

Enter a problem...

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$