Basic Math Examples

4 c - 2 + 2 (5 c + 3) = - 2 (c + 3)

$4 c - 2 + 2 (5 c + 3) = - 2 (c + 3)$

Step 1

Simplify

4 c - 2 + 2 (5 c + 3)

$4 c - 2 + 2 (5 c + 3)$ .

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Step 1.1

Simplify each term.

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Step 1.1.1

Apply the distributive property.

4 c - 2 + 2 (5 c) + 2 \cdot 3 = - 2 (c + 3)

$4 c - 2 + 2 (5 c) + 2 \cdot 3 = - 2 (c + 3)$

Step 1.1.2

Multiply

5

$5$ by

2

$2$ .

4 c - 2 + 10 c + 2 \cdot 3 = - 2 (c + 3)

$4 c - 2 + 10 c + 2 \cdot 3 = - 2 (c + 3)$

Step 1.1.3

Multiply

2

$2$ by

3

$3$ .

4 c - 2 + 10 c + 6 = - 2 (c + 3)

$4 c - 2 + 10 c + 6 = - 2 (c + 3)$

4 c - 2 + 10 c + 6 = - 2 (c + 3)

$4 c - 2 + 10 c + 6 = - 2 (c + 3)$

Step 1.2

Simplify by adding terms.

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Step 1.2.1

Add

4 c

$4 c$ and

10 c

$10 c$ .

14 c - 2 + 6 = - 2 (c + 3)

$14 c - 2 + 6 = - 2 (c + 3)$

Step 1.2.2

Add

- 2

$- 2$ and

6

$6$ .

14 c + 4 = - 2 (c + 3)

$14 c + 4 = - 2 (c + 3)$

14 c + 4 = - 2 (c + 3)

$14 c + 4 = - 2 (c + 3)$

14 c + 4 = - 2 (c + 3)

$14 c + 4 = - 2 (c + 3)$

Step 2

Simplify

- 2 (c + 3)

$- 2 (c + 3)$ .

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Step 2.1

Apply the distributive property.

14 c + 4 = - 2 c - 2 \cdot 3

$14 c + 4 = - 2 c - 2 \cdot 3$

Step 2.2

Multiply

- 2

$- 2$ by

3

$3$ .

14 c + 4 = - 2 c - 6

$14 c + 4 = - 2 c - 6$

14 c + 4 = - 2 c - 6

$14 c + 4 = - 2 c - 6$

Step 3

Move all terms containing

c

$c$ to the left side of the equation.

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Step 3.1

Add

2 c

$2 c$ to both sides of the equation.

14 c + 4 + 2 c = - 6

$14 c + 4 + 2 c = - 6$

Step 3.2

Add

14 c

$14 c$ and

2 c

$2 c$ .

16 c + 4 = - 6

$16 c + 4 = - 6$

16 c + 4 = - 6

$16 c + 4 = - 6$

Step 4

Move all terms not containing

c

$c$ to the right side of the equation.

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Step 4.1

Subtract

4

$4$ from both sides of the equation.

16 c = - 6 - 4

$16 c = - 6 - 4$

Step 4.2

Subtract

4

$4$ from

- 6

$- 6$ .

16 c = - 10

$16 c = - 10$

16 c = - 10

$16 c = - 10$

Step 5

Divide each term in

16 c = - 10

$16 c = - 10$ by

16

$16$ and simplify.

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Step 5.1

Divide each term in

16 c = - 10

$16 c = - 10$ by

16

$16$ .

\frac{16 c}{16} = \frac{- 10}{16}

$\frac{16 c}{16} = \frac{- 10}{16}$

Step 5.2

Simplify the left side.

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Step 5.2.1

Cancel the common factor of

16

$16$ .

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Step 5.2.1.1

Cancel the common factor.

$\frac{16 c}{16} = \frac{- 10}{16}$

Step 5.2.1.2

Divide

$c$ by

$1$ .

$c = \frac{- 10}{16}$

$c = \frac{- 10}{16}$

$c = \frac{- 10}{16}$

Step 5.3

Simplify the right side.

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Step 5.3.1

Cancel the common factor of

$- 10$ and

$16$ .

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Step 5.3.1.1

Factor

$2$ out of

$- 10$ .

$c = \frac{2 (- 5)}{16}$

Step 5.3.1.2

Cancel the common factors.

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Step 5.3.1.2.1

Factor

$2$ out of

$16$ .

$c = \frac{2 \cdot - 5}{2 \cdot 8}$

Step 5.3.1.2.2

Cancel the common factor.

$c = \frac{2 \cdot - 5}{2 \cdot 8}$

Step 5.3.1.2.3

Rewrite the expression.

$c = \frac{- 5}{8}$

$c = \frac{- 5}{8}$

$c = \frac{- 5}{8}$

Step 5.3.2

Move the negative in front of the fraction.

$c = - \frac{5}{8}$

$c = - \frac{5}{8}$

$c = - \frac{5}{8}$

Step 6

The result can be shown in multiple forms.

Exact Form:

$c = - \frac{5}{8}$

Decimal Form:

$c = - 0.625$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$