Basic Math Examples

$- 36 = 3 C + 5 (c + 4)$

Step 1

Rewrite the equation as $3 C + 5 (c + 4) = - 36$ .

$3 C + 5 (c + 4) = - 36$

Step 2

Simplify each term.

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Step 2.1

Apply the distributive property.

$3 C + 5 c + 5 \cdot 4 = - 36$

Step 2.2

Multiply $5$ by $4$ .

$3 C + 5 c + 20 = - 36$

Step 3

Move all terms not containing $C$ to the right side of the equation.

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Step 3.1

Subtract $5 c$ from both sides of the equation.

$3 C + 20 = - 36 - 5 c$

Step 3.2

Subtract $20$ from both sides of the equation.

$3 C = - 36 - 5 c - 20$

Step 3.3

Subtract $20$ from $- 36$ .

$3 C = - 5 c - 56$

Step 4

Divide each term in $3 C = - 5 c - 56$ by $3$ and simplify.

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Step 4.1

Divide each term in $3 C = - 5 c - 56$ by $3$ .

$\frac{3 C}{3} = \frac{- 5 c}{3} + \frac{- 56}{3}$

Step 4.2

Simplify the left side.

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Step 4.2.1

Cancel the common factor of $3$ .

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Step 4.2.1.1

Cancel the common factor.

$\frac{3 C}{3} = \frac{- 5 c}{3} + \frac{- 56}{3}$

Step 4.2.1.2

Divide $C$ by $1$ .

$C = \frac{- 5 c}{3} + \frac{- 56}{3}$

Step 4.3

Simplify the right side.

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Step 4.3.1

Simplify each term.

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Step 4.3.1.1

Move the negative in front of the fraction.

$C = - \frac{5 c}{3} + \frac{- 56}{3}$

Step 4.3.1.2

Move the negative in front of the fraction.

$C = - \frac{5 c}{3} - \frac{56}{3}$