Basic Math Examples

$y + 2 = - 3 (c - 1)$

Step 1

Rewrite the equation as $- 3 (c - 1) = y + 2$ .

$- 3 (c - 1) = y + 2$

Step 2

Divide each term in $- 3 (c - 1) = y + 2$ by $- 3$ and simplify.

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Step 2.1

Divide each term in $- 3 (c - 1) = y + 2$ by $- 3$ .

$\frac{- 3 (c - 1)}{- 3} = \frac{y}{- 3} + \frac{2}{- 3}$

Step 2.2

Simplify the left side.

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Step 2.2.1

Cancel the common factor of $- 3$ .

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Step 2.2.1.1

Cancel the common factor.

$\frac{- 3 (c - 1)}{- 3} = \frac{y}{- 3} + \frac{2}{- 3}$

Step 2.2.1.2

Divide $c - 1$ by $1$ .

$c - 1 = \frac{y}{- 3} + \frac{2}{- 3}$

Step 2.3

Simplify the right side.

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Step 2.3.1

Simplify each term.

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Step 2.3.1.1

Move the negative in front of the fraction.

$c - 1 = - \frac{y}{3} + \frac{2}{- 3}$

Step 2.3.1.2

Move the negative in front of the fraction.

$c - 1 = - \frac{y}{3} - \frac{2}{3}$

Step 3

Move all terms not containing $c$ to the right side of the equation.

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Step 3.1

Add $1$ to both sides of the equation.

$c = - \frac{y}{3} - \frac{2}{3} + 1$

Step 3.2

Write $1$ as a fraction with a common denominator.

$c = - \frac{y}{3} - \frac{2}{3} + \frac{3}{3}$

Step 3.3

Combine the numerators over the common denominator.

$c = - \frac{y}{3} + \frac{- 2 + 3}{3}$

Step 3.4

Add $- 2$ and $3$ .

$c = - \frac{y}{3} + \frac{1}{3}$