Basic Math Examples

Solve for a 12500=20000(1+(0.065/4))^(4*a)
12500=20000(1+(0.0654))4a
Step 1
Rewrite the equation as 20000(1+0.0654)4a=12500.
20000(1+0.0654)4a=12500
Step 2
Simplify.
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Step 2.1
Divide 0.065 by 4.
20000(1+0.01625)4a=12500
Step 2.2
Add 1 and 0.01625.
200001.016254a=12500
200001.016254a=12500
Step 3
Divide each term in 200001.016254a=12500 by 20000 and simplify.
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Step 3.1
Divide each term in 200001.016254a=12500 by 20000.
200001.016254a20000=1250020000
Step 3.2
Simplify the left side.
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Step 3.2.1
Cancel the common factor of 20000.
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Step 3.2.1.1
Cancel the common factor.
200001.016254a20000=1250020000
Step 3.2.1.2
Divide 1.016254a by 1.
1.016254a=1250020000
1.016254a=1250020000
1.016254a=1250020000
Step 3.3
Simplify the right side.
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Step 3.3.1
Cancel the common factor of 12500 and 20000.
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Step 3.3.1.1
Factor 2500 out of 12500.
1.016254a=2500(5)20000
Step 3.3.1.2
Cancel the common factors.
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Step 3.3.1.2.1
Factor 2500 out of 20000.
1.016254a=2500525008
Step 3.3.1.2.2
Cancel the common factor.
1.016254a=2500525008
Step 3.3.1.2.3
Rewrite the expression.
1.016254a=58
1.016254a=58
1.016254a=58
1.016254a=58
1.016254a=58
Step 4
Take the natural logarithm of both sides of the equation to remove the variable from the exponent.
ln(1.016254a)=ln(58)
Step 5
Expand ln(1.016254a) by moving 4a outside the logarithm.
4aln(1.01625)=ln(58)
Step 6
Divide each term in 4aln(1.01625)=ln(58) by 4ln(1.01625) and simplify.
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Step 6.1
Divide each term in 4aln(1.01625)=ln(58) by 4ln(1.01625).
4aln(1.01625)4ln(1.01625)=ln(58)4ln(1.01625)
Step 6.2
Simplify the left side.
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Step 6.2.1
Cancel the common factor of 4.
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Step 6.2.1.1
Cancel the common factor.
4aln(1.01625)4ln(1.01625)=ln(58)4ln(1.01625)
Step 6.2.1.2
Rewrite the expression.
aln(1.01625)ln(1.01625)=ln(58)4ln(1.01625)
aln(1.01625)ln(1.01625)=ln(58)4ln(1.01625)
Step 6.2.2
Cancel the common factor of ln(1.01625).
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Step 6.2.2.1
Cancel the common factor.
aln(1.01625)ln(1.01625)=ln(58)4ln(1.01625)
Step 6.2.2.2
Divide a by 1.
a=ln(58)4ln(1.01625)
a=ln(58)4ln(1.01625)
a=ln(58)4ln(1.01625)
a=ln(58)4ln(1.01625)
Step 7
The result can be shown in multiple forms.
Exact Form:
a=ln(58)4ln(1.01625)
Decimal Form:
a=-7.28941768
 [x2  12  π  xdx ]