Basic Math Examples

$5 \cdot (2.8 \cdot a - 1.75) = 7 \cdot (2 \cdot a - 1.25)$

Step 1

Simplify $5 \cdot (2.8 \cdot a - 1.75)$ .

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Step 1.1

Rewrite.

$0 + 0 + 5 \cdot (2.8 \cdot a - 1.75) = 7 \cdot (2 \cdot a - 1.25)$

Step 1.2

Simplify by adding zeros.

$5 \cdot (2.8 \cdot a - 1.75) = 7 \cdot (2 \cdot a - 1.25)$

Step 1.3

Apply the distributive property.

$5 (2.8 a) + 5 \cdot - 1.75 = 7 \cdot (2 \cdot a - 1.25)$

Step 1.4

Multiply.

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Step 1.4.1

Multiply $2.8$ by $5$ .

$14 a + 5 \cdot - 1.75 = 7 \cdot (2 \cdot a - 1.25)$

Step 1.4.2

Multiply $5$ by $- 1.75$ .

$14 a - 8.75 = 7 \cdot (2 \cdot a - 1.25)$

Step 2

Simplify $7 \cdot (2 \cdot a - 1.25)$ .

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Step 2.1

Apply the distributive property.

$14 a - 8.75 = 7 (2 a) + 7 \cdot - 1.25$

Step 2.2

Multiply.

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Step 2.2.1

Multiply $2$ by $7$ .

$14 a - 8.75 = 14 a + 7 \cdot - 1.25$

Step 2.2.2

Multiply $7$ by $- 1.25$ .

$14 a - 8.75 = 14 a - 8.75$

Step 3

Move all terms containing $a$ to the left side of the equation.

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Step 3.1

Subtract $14 a$ from both sides of the equation.

$14 a - 8.75 - 14 a = - 8.75$

Step 3.2

Subtract $14 a$ from $14 a$ .

$0 a - 8.75 = - 8.75$

Step 3.3

Multiply $0$ by $a$ .

$0 - 8.75 = - 8.75$

Step 3.4

Subtract $8.75$ from $0$ .

$- 8.75 = - 8.75$

Step 4

Since $- 8.75 = - 8.75$ , the equation will always be true for any value of $a$ .

All real numbers

Step 5

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$