Basic Math Examples

$- 3 (b - 5) = - 2 (- 3 + 2 b)$

Step 1

Simplify $- 3 (b - 5)$ .

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Step 1.1

Rewrite.

$0 + 0 - 3 (b - 5) = - 2 (- 3 + 2 b)$

Step 1.2

Simplify by adding zeros.

$- 3 (b - 5) = - 2 (- 3 + 2 b)$

Step 1.3

Apply the distributive property.

$- 3 b - 3 \cdot - 5 = - 2 (- 3 + 2 b)$

Step 1.4

Multiply $- 3$ by $- 5$ .

$- 3 b + 15 = - 2 (- 3 + 2 b)$

Step 2

Simplify $- 2 (- 3 + 2 b)$ .

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Step 2.1

Apply the distributive property.

$- 3 b + 15 = - 2 \cdot - 3 - 2 (2 b)$

Step 2.2

Multiply.

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Step 2.2.1

Multiply $- 2$ by $- 3$ .

$- 3 b + 15 = 6 - 2 (2 b)$

Step 2.2.2

Multiply $2$ by $- 2$ .

$- 3 b + 15 = 6 - 4 b$

Step 3

Move all terms containing $b$ to the left side of the equation.

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Step 3.1

Add $4 b$ to both sides of the equation.

$- 3 b + 15 + 4 b = 6$

Step 3.2

Add $- 3 b$ and $4 b$ .

$b + 15 = 6$

Step 4

Move all terms not containing $b$ to the right side of the equation.

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Step 4.1

Subtract $15$ from both sides of the equation.

$b = 6 - 15$

Step 4.2

Subtract $15$ from $6$ .

$b = - 9$