Basic Math Examples

8 B + C = A

$8 B + C = A$

Step 1

Subtract

C

$C$ from both sides of the equation.

8 B = A - C

$8 B = A - C$

Step 2

Divide each term in

8 B = A - C

$8 B = A - C$ by

8

$8$ and simplify.

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Step 2.1

Divide each term in

8 B = A - C

$8 B = A - C$ by

8

$8$ .

\frac{8 B}{8} = \frac{A}{8} + \frac{- C}{8}

$\frac{8 B}{8} = \frac{A}{8} + \frac{- C}{8}$

Step 2.2

Simplify the left side.

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Step 2.2.1

Cancel the common factor of

8

$8$ .

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Step 2.2.1.1

Cancel the common factor.

$\frac{8 B}{8} = \frac{A}{8} + \frac{- C}{8}$

Step 2.2.1.2

Divide

$B$ by

$1$ .

$B = \frac{A}{8} + \frac{- C}{8}$

$B = \frac{A}{8} + \frac{- C}{8}$

$B = \frac{A}{8} + \frac{- C}{8}$

Step 2.3

Simplify the right side.

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Step 2.3.1

Move the negative in front of the fraction.

$B = \frac{A}{8} - \frac{C}{8}$

$B = \frac{A}{8} - \frac{C}{8}$

$B = \frac{A}{8} - \frac{C}{8}$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$