Basic Math Examples

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\begin{matrix} b_{1} = & 5 b_{2} = & 3 h = & 7 \end{matrix}

$\begin{array}{r} b_{1} = & 5 \\ b_{2} = & 3 \\ h = & 7 \end{array}$

Step 1

The area of a trapezoid is equal to

\frac{1}{2}

$\frac{1}{2}$ times the height times the sum of the bases

b_{1} + b_{2}

$b_{1} + b_{2}$ .

\frac{1}{2} \cdot (h e i g h t) \cdot (b_{1} + b_{2})

$\frac{1}{2} \cdot (h e i g h t) \cdot (b_{1} + b_{2})$

Step 2

Substitute the values of the height

h = 7

$h = 7$ and bases (

b_{1} = 5

$b_{1} = 5$ and

b_{2} = 3

$b_{2} = 3$ ) into the formula for the area of a trapezoid.

\frac{1}{2} \cdot 7 \cdot (5 + 3)

$\frac{1}{2} \cdot 7 \cdot (5 + 3)$

Step 3

Combine

\frac{1}{2}

$\frac{1}{2}$ and

7

$7$ .

\frac{7}{2} \cdot (5 + 3)

$\frac{7}{2} \cdot (5 + 3)$

Step 4

Add

5

$5$ and

3

$3$ .

\frac{7}{2} \cdot 8

$\frac{7}{2} \cdot 8$

Step 5

Cancel the common factor of

2

$2$ .

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Step 5.1

Factor

2

$2$ out of

8

$8$ .

\frac{7}{2} \cdot (2 (4))

$\frac{7}{2} \cdot (2 (4))$

Step 5.2

Cancel the common factor.

$\frac{7}{2} \cdot (2 \cdot 4)$

Step 5.3

Rewrite the expression.

$7 \cdot 4$

Step 6

Multiply

$7$ by

$4$ .

$28$