Basic Math Examples

a^{2} + b^{2} = c^{2}

$a^{2} + b^{2} = c^{2}$

Step 1

Subtract

a^{2}

$a^{2}$ from both sides of the equation.

b^{2} = c^{2} - a^{2}

$b^{2} = c^{2} - a^{2}$

Step 2

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

b = \pm \sqrt{c^{2} - a^{2}}

$b = \pm \sqrt{c^{2} - a^{2}}$

Step 3

Since both terms are perfect squares, factor using the difference of squares formula,

a^{2} - b^{2} = (a + b) (a - b)

$a^{2} - b^{2} = (a + b) (a - b)$ where

a = c

$a = c$ and

b = a

$b = a$ .

b = \pm \sqrt{(c + a) (c - a)}

$b = \pm \sqrt{(c + a) (c - a)}$

Step 4

The complete solution is the result of both the positive and negative portions of the solution.

Tap for more steps...

Step 4.1

First, use the positive value of the

\pm

$\pm$ to find the first solution.

b = \sqrt{(c + a) (c - a)}

$b = \sqrt{(c + a) (c - a)}$

Step 4.2

Next, use the negative value of the

\pm

$\pm$ to find the second solution.

b = - \sqrt{(c + a) (c - a)}

$b = - \sqrt{(c + a) (c - a)}$

Step 4.3

The complete solution is the result of both the positive and negative portions of the solution.

b = \sqrt{(c + a) (c - a)}

$b = \sqrt{(c + a) (c - a)}$

b = - \sqrt{(c + a) (c - a)}

$b = - \sqrt{(c + a) (c - a)}$

b = \sqrt{(c + a) (c - a)}

$b = \sqrt{(c + a) (c - a)}$

b = - \sqrt{(c + a) (c - a)}

$b = - \sqrt{(c + a) (c - a)}$

a^{2} + b^{2} = c^{2}

$a^{2} + b^{2} = c^{2}$

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