Basic Math Examples

$68 \sqrt{24}$ , $412$

Step 1

Rewrite $24$ as $2^{2} \cdot 6$ .

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Step 1.1

Factor $4$ out of $24$ .

$68 \sqrt{4 (6)}, 412$

Step 1.2

Rewrite $4$ as $2^{2}$ .

$68 \sqrt{2^{2} \cdot 6}, 412$

Step 2

Pull terms out from under the radical.

$68 (2 \sqrt{6}), 412$

Step 3

Multiply $2$ by $68$ .

$136 \sqrt{6}, 412$

Step 4

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{136 \sqrt{6} + 412}{2}$

Step 5

Cancel the common factor of $136 \sqrt{6} + 412$ and $2$ .

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Step 5.1

Factor $2$ out of $136 \sqrt{6}$ .

$\frac{2 (68 \sqrt{6}) + 412}{2}$

Step 5.2

Factor $2$ out of $412$ .

$\frac{2 (68 \sqrt{6}) + 2 \cdot 206}{2}$

Step 5.3

Factor $2$ out of $2 (68 \sqrt{6}) + 2 (206)$ .

$\frac{2 (68 \sqrt{6} + 206)}{2}$

Step 5.4

Cancel the common factors.

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Step 5.4.1

Factor $2$ out of $2$ .

$\frac{2 (68 \sqrt{6} + 206)}{2 (1)}$

Step 5.4.2

Cancel the common factor.

$\frac{2 (68 \sqrt{6} + 206)}{2 \cdot 1}$

Step 5.4.3

Rewrite the expression.

$\frac{68 \sqrt{6} + 206}{1}$

Step 5.4.4

Divide $68 \sqrt{6} + 206$ by $1$ .

$68 \sqrt{6} + 206$

Step 6

Divide.

$372.5653025$

Step 7

The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

$372.6$