Basic Math Examples

s + 4^{2} = - 2 s

$s + 4^{2} = - 2 s$

Step 1

Raise

4

$4$ to the power of

2

$2$ .

s + 16 = - 2 s

$s + 16 = - 2 s$

Step 2

Move all terms containing

s

$s$ to the left side of the equation.

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Step 2.1

Add

2 s

$2 s$ to both sides of the equation.

s + 16 + 2 s = 0

$s + 16 + 2 s = 0$

Step 2.2

Add

s

$s$ and

2 s

$2 s$ .

3 s + 16 = 0

$3 s + 16 = 0$

3 s + 16 = 0

$3 s + 16 = 0$

Step 3

Subtract

16

$16$ from both sides of the equation.

3 s = - 16

$3 s = - 16$

Step 4

Divide each term in

3 s = - 16

$3 s = - 16$ by

3

$3$ and simplify.

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Step 4.1

Divide each term in

3 s = - 16

$3 s = - 16$ by

3

$3$ .

\frac{3 s}{3} = \frac{- 16}{3}

$\frac{3 s}{3} = \frac{- 16}{3}$

Step 4.2

Simplify the left side.

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Step 4.2.1

Cancel the common factor of

3

$3$ .

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Step 4.2.1.1

Cancel the common factor.

$\frac{3 s}{3} = \frac{- 16}{3}$

Step 4.2.1.2

Divide

$s$ by

$1$ .

$s = \frac{- 16}{3}$

$s = \frac{- 16}{3}$

$s = \frac{- 16}{3}$

Step 4.3

Simplify the right side.

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Step 4.3.1

Move the negative in front of the fraction.

$s = - \frac{16}{3}$

$s = - \frac{16}{3}$

$s = - \frac{16}{3}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$s = - \frac{16}{3}$

Decimal Form:

$s = - 5.\overline{3}$

Mixed Number Form:

$s = - 5 \frac{1}{3}$

Enter a problem...

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$