Basic Math Examples

$(7 + 2 p) \cdot 5 = 11 + 6 p$

Step 1

Simplify $(7 + 2 p) \cdot 5$ .

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Step 1.1

Rewrite.

$0 + 0 + (7 + 2 p) \cdot 5 = 11 + 6 p$

Step 1.2

Simplify by adding zeros.

$(7 + 2 p) \cdot 5 = 11 + 6 p$

Step 1.3

Apply the distributive property.

$7 \cdot 5 + 2 p \cdot 5 = 11 + 6 p$

Step 1.4

Multiply.

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Step 1.4.1

Multiply $7$ by $5$ .

$35 + 2 p \cdot 5 = 11 + 6 p$

Step 1.4.2

Multiply $5$ by $2$ .

$35 + 10 p = 11 + 6 p$

Step 2

Move all terms containing $p$ to the left side of the equation.

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Step 2.1

Subtract $6 p$ from both sides of the equation.

$35 + 10 p - 6 p = 11$

Step 2.2

Subtract $6 p$ from $10 p$ .

$35 + 4 p = 11$

Step 3

Move all terms not containing $p$ to the right side of the equation.

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Step 3.1

Subtract $35$ from both sides of the equation.

$4 p = 11 - 35$

Step 3.2

Subtract $35$ from $11$ .

$4 p = - 24$

Step 4

Divide each term in $4 p = - 24$ by $4$ and simplify.

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Step 4.1

Divide each term in $4 p = - 24$ by $4$ .

$\frac{4 p}{4} = \frac{- 24}{4}$

Step 4.2

Simplify the left side.

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Step 4.2.1

Cancel the common factor of $4$ .

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Step 4.2.1.1

Cancel the common factor.

$\frac{4 p}{4} = \frac{- 24}{4}$

Step 4.2.1.2

Divide $p$ by $1$ .

$p = \frac{- 24}{4}$

Step 4.3

Simplify the right side.

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Step 4.3.1

Divide $- 24$ by $4$ .

$p = - 6$