Basic Math Examples

$7 (2 p + 1) - 4 (3 p + 2) = 0$

Step 1

Simplify $7 (2 p + 1) - 4 (3 p + 2)$ .

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Step 1.1

Simplify each term.

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Step 1.1.1

Apply the distributive property.

$7 (2 p) + 7 \cdot 1 - 4 (3 p + 2) = 0$

Step 1.1.2

Multiply $2$ by $7$ .

$14 p + 7 \cdot 1 - 4 (3 p + 2) = 0$

Step 1.1.3

Multiply $7$ by $1$ .

$14 p + 7 - 4 (3 p + 2) = 0$

Step 1.1.4

Apply the distributive property.

$14 p + 7 - 4 (3 p) - 4 \cdot 2 = 0$

Step 1.1.5

Multiply $3$ by $- 4$ .

$14 p + 7 - 12 p - 4 \cdot 2 = 0$

Step 1.1.6

Multiply $- 4$ by $2$ .

$14 p + 7 - 12 p - 8 = 0$

$14 p + 7 - 12 p - 8 = 0$

Step 1.2

Simplify by adding terms.

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Step 1.2.1

Subtract $12 p$ from $14 p$ .

$2 p + 7 - 8 = 0$

Step 1.2.2

Subtract $8$ from $7$ .

$2 p - 1 = 0$

$2 p - 1 = 0$

$2 p - 1 = 0$

Step 2

Add $1$ to both sides of the equation.

$2 p = 1$

Step 3

Divide each term in $2 p = 1$ by $2$ and simplify.

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Step 3.1

Divide each term in $2 p = 1$ by $2$ .

$\frac{2 p}{2} = \frac{1}{2}$

Step 3.2

Simplify the left side.

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Step 3.2.1

Cancel the common factor of $2$ .

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Step 3.2.1.1

Cancel the common factor.

$\frac{2 p}{2} = \frac{1}{2}$

Step 3.2.1.2

Divide $p$ by $1$ .

$p = \frac{1}{2}$

$p = \frac{1}{2}$

$p = \frac{1}{2}$

$p = \frac{1}{2}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$p = \frac{1}{2}$

Decimal Form:

$p = 0.5$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$